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Ajay travels first one-third of the total distance at the speed of 10 kmph and the second one-third distance at the speed of 20 kmph and the third one – third distance at the speed of 60 kmph. What is the average speed of Ajay?

Correct

Answer : 1. 18 kmph
Explanation:
Time for first 1/3 of distance = ((y/3)/ 10)
Time for second 1/3 of distance = ((y/3)/20)
Time for third 1/3 of distance = ((y/3)/60)
Time for entire trip = x = ((y/3)/10) + ((y/3)/20) + ((y/3)/60)
180x = 6y +3y + y
180x = 10y
x = y/18
Average speed = D/T = y/x
= y / (y/18)
= y * (18/y)
= 18 km/hr

Incorrect

Answer : 1. 18 kmph
Explanation:
Time for first 1/3 of distance = ((y/3)/ 10)
Time for second 1/3 of distance = ((y/3)/20)
Time for third 1/3 of distance = ((y/3)/60)
Time for entire trip = x = ((y/3)/10) + ((y/3)/20) + ((y/3)/60)
180x = 6y +3y + y
180x = 10y
x = y/18
Average speed = D/T = y/x
= y / (y/18)
= y * (18/y)
= 18 km/hr

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

Vinay and Vijay are two partners and they have invested Rs. 54,000 and Rs. 90,000 in business respectively. After one year Vinay received Rs 1200 as his share of profit out of total profit of Rs. 4200 including his certain commission on total profit since he is a working partner and rest profit is received by Vijay. What is the commission of Vinay as a percentage of the total profit?

Correct

Answer : 1. 1200
Explanation:
Ratio of profit of Vinay : Vijay (excluding commission of Vinay) = 54000 : 90000 =>3 : 5
Now the share of profit of Vijay = 4200 – 1200 = Rs. 3000
So the share of profit Vinay (excluding commission) = Rs. 1800
So the commission of Vinay = 3000 – 1800 = 1200

Incorrect

Answer : 1. 1200
Explanation:
Ratio of profit of Vinay : Vijay (excluding commission of Vinay) = 54000 : 90000 =>3 : 5
Now the share of profit of Vijay = 4200 – 1200 = Rs. 3000
So the share of profit Vinay (excluding commission) = Rs. 1800
So the commission of Vinay = 3000 – 1800 = 1200

Answer : 5. X = Y or relation cannot be established
Explanation:
480/x = [480/(x – 8)] – 3
x = 40, -32
y(10y – 1) = 2
10y2 – y – 2 = 0; y = 0.5, -0.4

Incorrect

Answer : 5. X = Y or relation cannot be established
Explanation:
480/x = [480/(x – 8)] – 3
x = 40, -32
y(10y – 1) = 2
10y2 – y – 2 = 0; y = 0.5, -0.4

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

If Siva is as much elder than Ramesh as he is younger to Deepak and sum of the ages of Ramesh and Deepak is 46 year, then what will be the age of Siva after six years?

Correct

Answer : 4. 29
Explanation :
Let the present ages of Siva is x year and he is younger to Deepak by y year
Then Deepak’s age = x + y
Ramesh’s age = x – y
(x + y) + (x – y) = 46
x = 23
The age of Siva after five years is – 29

Incorrect

Answer : 4. 29
Explanation :
Let the present ages of Siva is x year and he is younger to Deepak by y year
Then Deepak’s age = x + y
Ramesh’s age = x – y
(x + y) + (x – y) = 46
x = 23
The age of Siva after five years is – 29

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

A Cultural Competition is organised by the college A through which they will provide scholarship of rupees one lakhs to only one student. There are 100 fourth year students, 150 third year students, 200 second year students and 250 first year students. What is the probability that a second year student is chosen.

Correct

Answer : 2. 2/7
Explanation :
Second year students = 200
Probability = 200/700 = 2/7

Incorrect

Answer : 2. 2/7
Explanation :
Second year students = 200
Probability = 200/700 = 2/7

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