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Question 1 of 10
1. Question
1 points
Category: Quantitative Aptitude
What annual installment will discharge a debt of Rs 6000 due in 5 years at 10% per annum simple interest?
Correct
Explanation:
I = 100A/ [100t + rt(t-1)/2]
So I = 100*6000/ [100*5 + 10*5*(5-1)/2] = 100*6000/ [500 + 100]
Incorrect
Explanation:
I = 100A/ [100t + rt(t-1)/2]
So I = 100*6000/ [100*5 + 10*5*(5-1)/2] = 100*6000/ [500 + 100]
Question 2 of 10
2. Question
1 points
Category: Quantitative Aptitude
When a bus drove at 55 km/hr from bus stop, it reached school 20 minutes late and when the same bus drove at 60 km/hr, it reached school 15 minutes earlier. What is the distance between bus stop and school?
Correct
Explanation:
Difference in time = 20 – (-15) = 35 minutes or 35/60 hr
Distance = Product of speeds/Difference of speeds * Difference in time
i.e. [60*55/(60-55)] * 35/60
Incorrect
Explanation:
Difference in time = 20 – (-15) = 35 minutes or 35/60 hr
Distance = Product of speeds/Difference of speeds * Difference in time
i.e. [60*55/(60-55)] * 35/60
Question 3 of 10
3. Question
1 points
Category: Quantitative Aptitude
A and B invested in a business as Rs 3000 and Rs 3500 respectively. After 4 months A added Rs 3000 more and B invested amount such that it became equal to which A has invested now as total. If after a year, B gets Rs 9610 as his share of profit, what is the total profit?
In how many ways all the letters of the word ‘ASSISTANT’ be arranged such that all vowels are together?
Correct
Explanation:
Take vowels in a box together as one – A, I, A other are S, S, S, T, N, T
So there are 7 that to be placed for this 7!, now there are 3 S and 2 T so 7!/(3! * 2!)
Now inside box, there are 3 vowels with 2 A, so there arrangement = 3!/2!
So total = 7!/(3! * 2!) * 3!/2!
Incorrect
Explanation:
Take vowels in a box together as one – A, I, A other are S, S, S, T, N, T
So there are 7 that to be placed for this 7!, now there are 3 S and 2 T so 7!/(3! * 2!)
Now inside box, there are 3 vowels with 2 A, so there arrangement = 3!/2!
So total = 7!/(3! * 2!) * 3!/2!
The difference in the ages of Raghav and Sumit is 7 years. The ratio of ages of Sumit before 4 years and Raghav after 4 years is 7 : 12. What is the sum of their present ages?
Correct
Explanation:
R – S = 7
(S-4)/(R+4) = 7/12
Solve both equations, S = 25, R = 32, so sum = 25+32
Incorrect
Explanation:
R – S = 7
(S-4)/(R+4) = 7/12
Solve both equations, S = 25, R = 32, so sum = 25+32
Question 7 of 10
7. Question
1 points
Category: Quantitative Aptitude
Find the least number which when divided by 2, 7, 10 and 15 leaves a remainder 8 but leaves no remainder when same number is divided by 11.
Correct
Explanation:
LCM(2, 7, 10, 15) = 210
So the number will be somewhat = 210x + 8
This number leaves no remainder when divided by 11, so x = 3 to get (210x+8) fully divided by 11
So number = 210*3 + 8
Incorrect
Explanation:
LCM(2, 7, 10, 15) = 210
So the number will be somewhat = 210x + 8
This number leaves no remainder when divided by 11, so x = 3 to get (210x+8) fully divided by 11
So number = 210*3 + 8
Question 8 of 10
8. Question
1 points
Category: Quantitative Aptitude
20 men and 25 women can complete a work in 8 days. The same work can be completed by 30 women and 16 men in 7 days. What is the ratio of the daily work done by a man to that of a woman?
Correct
Explanation:
20m + 25w = 8
So 160m + 200w = 1
Also 16m + 30w = 7
So 112m + 210w = 1
So 160m + 200w = 112m + 210w
Solve, m/w = 5/24
Incorrect
Explanation:
20m + 25w = 8
So 160m + 200w = 1
Also 16m + 30w = 7
So 112m + 210w = 1
So 160m + 200w = 112m + 210w
Solve, m/w = 5/24
Question 9 of 10
9. Question
1 points
Category: Quantitative Aptitude
By selling 100 articles, a tradesman makes a loss equal to the cost price of 18 articles. Find his loss%.
Correct
Explanation:
C.P of 100 articles – S.P of 100 articles = C.P of 18 articles
C.P of 82 articles = S.P of 100 articles
loss% = [(100 – 82)/100] * 100 = 18%
Incorrect
Explanation:
C.P of 100 articles – S.P of 100 articles = C.P of 18 articles
C.P of 82 articles = S.P of 100 articles
loss% = [(100 – 82)/100] * 100 = 18%
Question 10 of 10
10. Question
1 points
Category: Quantitative Aptitude
The sum of 6% of a number and 3% of other number is 3/7 of the sum of 2% of the first number and 9% of second. The ratio of first number to second number is
