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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeWhat annual installment will discharge a debt of Rs 6000 due in 5 years at 10% per annum simple interest?
Correct
Explanation:
I = 100A/ [100t + rt(t-1)/2]
So I = 100*6000/ [100*5 + 10*5*(5-1)/2] = 100*6000/ [500 + 100]Incorrect
Explanation:
I = 100A/ [100t + rt(t-1)/2]
So I = 100*6000/ [100*5 + 10*5*(5-1)/2] = 100*6000/ [500 + 100] -
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeWhen a bus drove at 55 km/hr from bus stop, it reached school 20 minutes late and when the same bus drove at 60 km/hr, it reached school 15 minutes earlier. What is the distance between bus stop and school?
Correct
Explanation:
Difference in time = 20 – (-15) = 35 minutes or 35/60 hr
Distance = Product of speeds/Difference of speeds * Difference in time
i.e. [60*55/(60-55)] * 35/60Incorrect
Explanation:
Difference in time = 20 – (-15) = 35 minutes or 35/60 hr
Distance = Product of speeds/Difference of speeds * Difference in time
i.e. [60*55/(60-55)] * 35/60 -
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeA and B invested in a business as Rs 3000 and Rs 3500 respectively. After 4 months A added Rs 3000 more and B invested amount such that it became equal to which A has invested now as total. If after a year, B gets Rs 9610 as his share of profit, what is the total profit?
Correct
Explanation:
3000*4 + 6000*8 : 3500*4 +6000*8
30*4 + 60*8 : 35*4 + 60*8
6 + 3*8 : 7 + 3*8
30 : 31
so (31/61) * x = 9610
solve, x = 18910Incorrect
Explanation:
3000*4 + 6000*8 : 3500*4 +6000*8
30*4 + 60*8 : 35*4 + 60*8
6 + 3*8 : 7 + 3*8
30 : 31
so (31/61) * x = 9610
solve, x = 18910 -
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeIn how many ways all the letters of the word ‘ASSISTANT’ be arranged such that all vowels are together?
Correct
Explanation:
Take vowels in a box together as one – A, I, A other are S, S, S, T, N, T
So there are 7 that to be placed for this 7!, now there are 3 S and 2 T so 7!/(3! * 2!)
Now inside box, there are 3 vowels with 2 A, so there arrangement = 3!/2!
So total = 7!/(3! * 2!) * 3!/2!Incorrect
Explanation:
Take vowels in a box together as one – A, I, A other are S, S, S, T, N, T
So there are 7 that to be placed for this 7!, now there are 3 S and 2 T so 7!/(3! * 2!)
Now inside box, there are 3 vowels with 2 A, so there arrangement = 3!/2!
So total = 7!/(3! * 2!) * 3!/2! -
Question 5 of 10
5. Question
1 pointsCategory: Quantitative Aptitude(4/5) + (2/7) + (2/3) + (2 2/5) =
Correct
Explanation:
(4/5) + (2/7) + (2/3) + (2 2/5)
(4/5) + (2 2/5) + (2/7) + (2/3)
(16/5) + (20/21)Incorrect
Explanation:
(4/5) + (2/7) + (2/3) + (2 2/5)
(4/5) + (2 2/5) + (2/7) + (2/3)
(16/5) + (20/21) -
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeThe difference in the ages of Raghav and Sumit is 7 years. The ratio of ages of Sumit before 4 years and Raghav after 4 years is 7 : 12. What is the sum of their present ages?
Correct
Explanation:
R – S = 7
(S-4)/(R+4) = 7/12
Solve both equations, S = 25, R = 32, so sum = 25+32Incorrect
Explanation:
R – S = 7
(S-4)/(R+4) = 7/12
Solve both equations, S = 25, R = 32, so sum = 25+32 -
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeFind the least number which when divided by 2, 7, 10 and 15 leaves a remainder 8 but leaves no remainder when same number is divided by 11.
Correct
Explanation:
LCM(2, 7, 10, 15) = 210
So the number will be somewhat = 210x + 8
This number leaves no remainder when divided by 11, so x = 3 to get (210x+8) fully divided by 11
So number = 210*3 + 8Incorrect
Explanation:
LCM(2, 7, 10, 15) = 210
So the number will be somewhat = 210x + 8
This number leaves no remainder when divided by 11, so x = 3 to get (210x+8) fully divided by 11
So number = 210*3 + 8 -
Question 8 of 10
8. Question
1 pointsCategory: Quantitative Aptitude20 men and 25 women can complete a work in 8 days. The same work can be completed by 30 women and 16 men in 7 days. What is the ratio of the daily work done by a man to that of a woman?
Correct
Explanation:
20m + 25w = 8
So 160m + 200w = 1
Also 16m + 30w = 7
So 112m + 210w = 1
So 160m + 200w = 112m + 210w
Solve, m/w = 5/24Incorrect
Explanation:
20m + 25w = 8
So 160m + 200w = 1
Also 16m + 30w = 7
So 112m + 210w = 1
So 160m + 200w = 112m + 210w
Solve, m/w = 5/24 -
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeBy selling 100 articles, a tradesman makes a loss equal to the cost price of 18 articles. Find his loss%.
Correct
Explanation:
C.P of 100 articles – S.P of 100 articles = C.P of 18 articles
C.P of 82 articles = S.P of 100 articles
loss% = [(100 – 82)/100] * 100 = 18%Incorrect
Explanation:
C.P of 100 articles – S.P of 100 articles = C.P of 18 articles
C.P of 82 articles = S.P of 100 articles
loss% = [(100 – 82)/100] * 100 = 18% -
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeThe sum of 6% of a number and 3% of other number is 3/7 of the sum of 2% of the first number and 9% of second. The ratio of first number to second number is
Correct
Explanation:
6x + 3y = (3/7) * (2x + 9y)
42x + 21y = 6x + 27y
36x = 6y
So x/y = 1/6Incorrect
Explanation:
6x + 3y = (3/7) * (2x + 9y)
42x + 21y = 6x + 27y
36x = 6y
So x/y = 1/6
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