Hello Aspirants. Welcome to Online Maths in AffairsCloud.com. Here we are creating question sample in **Probability**, which is common for all the competitive exams. We have included Some questions that are repeatedly asked in exams !!

**A five digit number is formed with the digits 0,1,2,3 and 4 without repetition.Find the chance that the number is divisible by 5**

A)3/5

B)1/5

C)2/5

D)4/5**Answer -B) 1/5**

Explanation :

5 digit number = 5! = 120

Divisible by 5 then the last digit should be 0

Then the remaining position have the possibility = 4! =24

P = (4!/5!) = 24/120 = 1/5**A bag contain 6 white balls and 4 red balls .Three balls are drawn randomly.What is the probability that one ball is red and other 2 are white**

A)1/2

B)2/1

C)3/2

D)1/3**Answer -A) 1/2**

Explanation :

Total no of balls = 6+ 4 = 10

3 balls drawn = 10C_{3}=(10×9×8)/(3×2×1) =120

one ball is red and other 2 are white = 4C_{1}×6C_{2 }

_{ }4C_{1}×6C2 =(4×6×5)/(1×2)= 60

P = 60/120 = ½**A box contain 10 red balls, 7 green balls and 12 blue balls. A ball is drawn at random. What is the probability that the ball drawn is either red or green ?**

A)7/29

B)12/29

C)17/29

D)10/29**Answer – C) 17/29**

Explanation :

Total no of balls =10+7+12 = 29

P(R) =10/29

P(G) = 7/29

P(Either red or green) = 10/29 + 7/29 = 17/29**A dice is thrown twice . What is the probability that at least one of them comes up with number 4**

A)12/36

B)11/36

C)1/6

D)11/6**Answer -B) 11/36**

Explanation :**From a group of 5 men and 2 women , 2 persons are selected at random. Find the probability that at least one woman is selected ?**

A)11/7

B)21/11

C)11/21

D)1/21**Answer -C)11/21**

Explanation :

n(S) = 7C_{2 }= (7×6)/(1×2) = 21

n(E) = 2C2+5C_{1 *}2C_{1 = 1+11}

P = n(E)/n(S) = 11/21**A bag contains 11 red and 5 green balls. Find the probability that 4 balls are red and 3 balls are green when 7 balls are drawn at random.**

A)16/52

B)15/52

C)11/52

D)10/52**Answer -B) 15/52**

Explanation :

n(S) = 16C_{7 }= 11440

n(E) = 11C_{4 }×5C_{3 }= 330×10 = 3300

P = n(E)/ n(S) = 3300/11440 = 15/52**Four different objects 1,2,3 are distributed at random in four places. What is the probability that none of the objects occupies the place corresponding to its number ?**

A)1/6

B)1/3

C)1/2

D)1**Answer – C) ½**

Explanation :

PLACE: 1 2 3 4

Random : 2134 , 2143 , 2314 ,2341 , 2413 ,2431

None of the objects occupies the place of that number = 2143 ,2341,2413

n(S) = 6, n(E) = 3

p = 3/6 = ½**A box contain 8 red balls, 6 green balls and 8 blue balls. A ball is drawn at random. What is the probability that the ball drawn is neither red nor green ?**

A)10/29

B)2/11

C)11/4

D)4/11**Answer -D) 4/11**

Explanation :

Total no of balls =8+6+8 = 22

P(B) =8/22

P(neither red nor green) = 8/22 = 4/11**A box contains 5 green , 4 yellow and 3 white marbles. Three marbles are drawn at random. What is the probability that they are not of the same colour ?**

A)40/44

B)44/41

C)41/44

D)40/39**Answer -C) 41/44**

Explanation :

n(E) = 5C_{3+ }4C_{3+}3C_{3 = 10+4+1 = 15}

_{n(S) = }12C_{3 = 220}

P = n(E)/ n(S) = 15/220 =3/44

Required probability = 1-3/44 = 41/44**Two dice are thrown simultaneously .What is the probability of getting 2 numbers whose product is even ?**

A)3/4

B)4/3

C)1/4

D)1/3**Answer -A) 3/4**

Explanation :

**AffairsCloud Recommends Oliveboard Mock Test**

**AffairsCloud Ebook - Support Us to Grow**

**Govt Jobs by Category**

**Bank Jobs Notification**