Hello Aspirants. Welcome to Online Quantitative Aptitude section in AffairsCloud.com. Here we are given some** Mixture and Alligations** problems that is important for competitive exams. We have included Some questions that are repeatedly asked in exams !!

**In what proportion must a grocer mix one kind of bajra at Rs.4.50 per kg with another at Rs.4 per kg in order that by selling the mixture at Rs.5.20 per kg he may make a profit of 20%?**

A)1:2

B)2:1

C)1:1

D)3:1Answer –**A)1:2**

Explanation :

Mean Price= C.P. of per kg mixture=100/120 ×5.20 = R.s 4.333

By Allegation rule

4 4.5

…….4.333………

0.167 0.333**Milk and water are mixed in the vessels A and B in the ratios 5:2 and 8:5 respectively. In what proportion should quantities be taken from the two vessels so as to form a mixture containing milk and water in the ratio 9:4?**

A)7:2

B)5:2

C)2:7

D)1:7Answer –**A)7:2**

Explanation :

In A C.P. of 1 liter milk Rs5/7 and that of B= Rs8/13, mixture= Rs9/13

5/7 8/13

……9/13….

1/13 2/91**How must a shop owner mix 4 types of rice worth Rs95, Rs60, Rs90 and Rs50 per kg so that he can make the mixture of these rice worth Rs80 per kg?**

A)3:2:4:6

B)2:3:6:4

C)1:5:3:6

D)6:4:3:2Answer –**A)3:2:4:6**

Explanation :

**1**^{st}pair: 50 95 2^{nd}pair: 60 90

**80 80**

**15 30 10 20**

Final ratio 15:10:20:30**Two bottles A and B contain diluted sulphuric acid. In bottle A, the amount of water is double the amount of acid while in bottle B, the amount of acid is 3 times that of water. How much mixture should be taken from each bottle in order to prepare 5 liters diluted sulphuric acid containing equal amount of acid and water?**

A)1,4

B)3,2

C)4,1

D)2,3Answer –**B)3,2**

Explanation :

In bottle A ratio acid: water=1:2, B=3:1

Mixture= 1:1, required acid=1/2

1/3 3/4

…….1/2…..

1/4 1/6**A jar contains a mixture of two liquids A and B in the ratio 4:1. When 10litres of the mixture is taken out and 10 liters of liquid B is poured into the jar, the ration becomes 2:3. How many liters of liquid A was contained in the jar?**

A)14 liters

B)18 liters

C)16 liters

D)20 litersAnswer –**C)16 liters**

Explanation :

% of B in the original mix= 1/5 * 100=20%

In final mix= 3/5 *100=60%

20 100

…….60……..

40 40

Total mix= 10+10=20 liters so qty of A=20/5 *4**A container contains 40 liters of the milk. From the container 4 liters of the milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?**

A)29.61 liters

B)30.16 liters

C)29.16 liters

D)13.16 litersAnswer –**C)29.16 liters**

Explanation :

Amount of milk left after 3 operations

40(1-4/40) ^3 liters**A dairy man pays Rs.6.40 per liter of milk. He adds water and sells the mixture at Rs.8 per liter thereby making 37.5% profit. Find the ratio of the water to milk received by the customers?**

A)1:15

B)1:20

C)1:12

D)1:10Answer –**D)1:10**

Explanation :

Suppose milk x and water y liters

Reqd. ratio of water and milk= y:x

CP of x liters milk=Rs.6.4x

SP of x liters milk=Rs.8(x+y)

64=8(x+y)*100/137.5

X:y=1:10**If 50% of 2:3 solution of milk and water is replaced with water, then the concentration of the solution is reduced by**

A)25

B)33

C)50

D)75Answer –**B)33**

Explanation :

Milk : water

20 30

-10 -15

+25

—- —-

10 40

Concentration of solution reduced by 10 i.e. 50% and dilution increased by 40 i.e. 33.33%**Milk and water are in the ratio of 3:2 in a mixture of 80 liters. How much water should be added so that the rate of milk and water become 2:3?**

A)25

B)40

C)35

D)20Answer –**B)40**

Explanation :

Milk =48 water =32

48/(32+x) = 2/3**How much water must be added to 100cc of 80% solution of Boric acid to reduce it to a 50% solution?**

A)30

B)40

C)50

D)60Answer –**D)60**

Explanation :50%(100+x)=80

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