Hello Aspirants. Welcome to Online Quantitative Aptitude section in AffairsCloud.com. Here we are creating question sample From all topics , which are Important for upcoming IBPS exams. We have included Some questions that are repeatedly asked in exams.

**300 gm of sugar solution has 40% sugar in it. How much sugar should be added to make it 50% in the solution?**

A) 60 gm

B) 50 gm

C) 22 gm

D) 28 gm

**A) 60 gm**

Explanation:

Sugar in 300 gm = 40/100 * 300 = 120 gm

Let x gm of sugar to be added.

So after addition of sugar, 50% of the whole new solution (300+x) should be the quantity of new sugar quantity.

50 % of (300+x) = 120+x

Solve x, x = 60

**How many words can be formed with the letters of the word ANKITA?**

A) 720

B) 5040

C) 120

D) 360

**D) 360**

Explanation:

Total 6 letters, in which A is repeated twice, so words that can be formed = 6!/2! = 720/2 = 360

**A bag contains 3 red, 5 yellow and 4 green balls. 3 balls are drawn at random. What is the probability that the balls drawn contain exactly 2 green balls?**A) 1/2

B) 13/55

C) 12/54

D) 12/55

**D) 12/55**

Explanation:

Total 12 balls, 2 balls should be green so for this^{4}C_{2}

Third ball can be any color except green, except green 8 balls are there, so for 1 ball,^{8}C_{1}

Prob =^{4}C_{2}*^{8}C_{1}/^{12}C_{3}**The ratio of money with Sita and Rita is 7:15 and that with Rita and Mita is 7:16. If Sita has Rs. 490, how much money does Mita have?**

A) Rs 2200

B) Rs 2600

C) Rs 2500

D) Rs 2400

**D) Rs 2400**

Explanation:

S/R = 7/15, R/M = 7/16

So, S : R : M = 7*7 : 15*7 : 15*16 = 49 : 135 : 240

Now Sita has Rs 490, so Mita has Rs 2400

**A can do a piece of work in the same time in which B and C can together do it. If A and B can together do it in 10 days and C alone in 50 days, then B alone could do it in:**

A) 20 days

B) 22 days

C) 25 days

D) 28 days

**C) 25 days**

Explanation:

(A+B+C)’s 1 day’s work: 1/A + 1/B + 1/C = 1/10 + 1/50 = 3/25

Given 1/A = 1/B +1/C

So, 1/A +1/A = 3/25 gives 1/A = 3/50

1/A + 1/B = 1/10, so 1/B = 1/10 – 3/50 = 1/25

So B can do in 25 days

**Inside a square plot, a circular garden is developed which exactly fits in the square plot and the diameter of the garden is equal to the side of the square plot which is 28 metres. What is the area of the space left out in the square plot after developing the garden?**

A) 98 m2

B) 146 m2

C) 84 m2

D) 168 m2

**D) 168 m2**

Explanation:

Side of square = 28

Diameter of circular garden = 28, so radius = 14

Area of space left out = area of square – area of circle

= 28*28 – 22/7 * 14 *14

**A, B, and C invested some money in ratio 3 : 4 : 5. After some time, they receive a profit which is divided among them in ratio 4 : 5 : 6. Find the ratio of the time of their respective investments.**

A. 80 : 72 : 75

B. 80 : 75 : 72

C. 75 : 72 : 80

D. 72 : 80 : 75

**B. 80 : 75 : 72**

Explanation:

Let their times are a months, b months, c months respectively.

Investment ratio is 3 : 4 : 5. Then the ratio of profits should be 3*a : 4*b : 5*c

And this ratio is given to be 4 : 5 : 6. So 3a : 4b : 5c = 4 : 5 : 6

So 3a = 4, 4b = 5, 5c = 6

a = 4/3, b = 5/4 , c = 6/5

a : b : c = 4/3 : 5/4 : 6/5 = 80 : 75 : 72**A committee of 4 is to be formed from among 4 girls and 5 boys. What is the probability that the committee will have number of boys less than number of girls?**

A) 1/12

B) 1/6

C) 1/10

D) 2/13

**B) 1/6**

**Explanation:**

Case 1: 4 girls and 0 boys

4C4/9C4

Case 2: 3 girls and 1 boy

4C3*5C1/9C4

Total probability = 4C4/9C4 + 4C3*5C1/9C4

**Sixteen men can complete a work in 12 days. Twenty four children can complete the same work in 18 days. Twelve men and eight children started working and after 8 days three more children joined them. How many days will they now take to complete the remaining work?**

A) 2

B) 4

C) 6

D) 8

**B) 4**

Explanation:

16 m = 12 D so, 1 m can do in 16*12 days, so 12 m can do in 16*12/12 = 16 days

24 c = 18 d, so 1 c can do in 24*18 days, so 8 c can do in 24*18/8 = 54 days and 3 c can do in 24*18/3 = 144 days

Now let after 8 days, x more days are required by all (12m + 8c) + 3c

So (8+x)/16 + (8+x)/54 + x/144 = 1

Solve for x**A motorboat in still water travels at a speed of 36 kmph. It goes 56 km upstream in 1 hour 45 minutes. The time taken by it to cover the same distance down the stream will be**

A) 2 hours 25 minutes

B) 3 hours

C) 1 hour 24 minutes

D) 2 hours 21 minutes

**C) 1 hour 24 minutes**

Explanation:

Speed of boat in still water (B) = 36 km/hr

1hr 45 min = 1 + 45/60 = 7/4 hrs

Upstream speed (U)= 56/(7/4) = 32 km/hr

B = (D+U)/2, so 36 = (D+32)/2, D = 40 km/hr

Time for downstream = 56/40 = 7/5 hrs

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