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Quantitative Aptitude Questions for IBPS PO Mains Exam Set – 47

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Hello Aspirants. Welcome to Online Quantitative Aptitude section in AffairsCloud.com. Here we are creating question sample From all topics , which are Important for upcoming IBPS exams. We have included Some questions that are repeatedly asked in exams.

  1. A reduction of 20% in the price of oranges enables a man to buy 5 oranges more for Rs 10. The price of an orange before reduction was
    A) 20 paise
    B) 40 paise
    C) 50 paise
    D) 60 paise
    C) 50 paise
    Explanation:
    Reduction in price = 20/100 * 10 = Rs 2
    For 5 oranges, reduction in cost = 2/5 Rs or 200/5 = 40 paise
    So actual cost before reduction = 40/1-0.20 = 50 paise

  2. In an examination a student who gets 20% of the maximum marks fails by 5 marks. Another student who scores 30% of the maximum marks gets 20 marks more than the pass marks. The necessary percentage required for passing is
    A) 32%
    B) 23%
    C) 22%
    D) 20%
    C) 22%
    Explanation:
    Let max marks = x
    Who gets 20% of x, fails by 5 marks, this means passing marks = 20/100 * x + 5 = x/5 +5
    Who gets 30% of x, gets 20 more marks, this means passing marks = 30/100 * x – 20 = 3x/10 – 20
    So x/5 +5 = 3x/10 – 20
    Solve, x = 250
    Passing marks = 250/5 + 5 = 55
    % = 55/250 * 100 = 22%

  3. A builder borrows Rs 2550 to be paid back with compound interest at the rate of 4% per annum by the end of 2 years in two equal yearly installments. How much will each installment be?
    A) Rs 1352
    B) Rs 1377
    C) Rs 1275
    D) Rs 1283
     A) Rs 1352

    Explanation:
    Formula for installment in CI for 2 yrs is A = I/[1+r/100] + I/[1+r/100]2
    So, 2550 = I/[1+4/100] + I/[1+4/100]2
    Solve, I = 1352

  4. A pipe of diameter ‘d’ can drain a certain water tank in 40 minutes. The time taken by the pipe of diameter ‘2d’ for doing the same job is
    A) 5 mins
    B) 10 mins
    C) 20 mins
    D) 25 mins
    B) 10 mins

    Explanation:
    Time is inversely proportional to the square of diameter. So,
    t1/t2 = (d2)^2/(d1)^2
    40/t2 = (2d)^2/(d)^2
    Solve, t2 = 10 mins

  5. A contactor undertakes to make a road in 40 days and employs 25 men. After 24 days, he finds that only one-third of the road is made. How many extra men should he employ so that he is able to complete the work 4 days earlier?
    A) 100
    B) 60
    C) 75
    D) 55
    C) 75
    Explanation:
    4 days earlier the work is to be completed, this means in (40-4) = 36 days
    After 24 days, the meaning work is to be completed in (36-24) = 12 days
    Remaining work = 1 – 1/3 = 2/3
    Let x extra men are to be employed. So,
    25 * 24 * 2/3 = (x+25) * 12 * 1/3
    Solve, x = 75

  6. A sum of Rs 400 amounts to Rs 480 in 4 years. What will it amount to if the rate of interest is increased by 2%?
    A) Rs 484
    B) Rs 560
    C) Rs 512
    D) Rs 600
    C) Rs 512
    Explanation:
    Increase in rate = 400*4*2/100 = 32
    So increase in amount = 480+32 = 512

  7. A retailer buys 40 pens at the marked price of 36 pens. If he sells these pens giving a discount of 1%, what is the profit percent?
    A. 9%
    B. 10%
    C. 11%
    D. 12%
    B. 10%
    Explanation:
    Let MP of 1 pen = Re 1
    CP of 40 pens = MP of 36 pens = Rs 36
    MP of 40 pens = Rs 40
    So after discount of 1%, SP of 40 pens = 99/100 * 40 = Rs 39.6
    So profit% = (39.6 – 36) / 36 * 100 = 10%

  8. A can cultivate 2/5th of the land in 6 days and B can cultivate 1/3rd of the same land in 10 days. Working together A and B can cultivate 4/5th of the land in
    A) 4 days
    B) 5 days
    C) 8 days
    D) 10 days
    C) 8 days
    Explanation:
    A can cultivate 2/5th of the land in 6 days, so whole land in 5/2 * 6 = 15 days.
    B can cultivate 1/3th of the land in 10 days, so whole land in 3/1 * 10 = 30 days.
    A and B together can complete whole land in 15*30/(15+30) = 10 days.
    So 4/5th land in 4/5 * 10 = 8 days

  9. A does half as much work as B in one sixth of the time. If together they take 10 days to complete a work, how many days shall B take to do it alone?
    A) 70
    B) 30
    C) 40
    D) 50
    C) 40
    Explanation:
    Let B do whole work in ‘x’ days.
    A does ½ work in x/6 days, so whole work in 2x/6 = x/3 days
    Together they take 10 days, so x * x/3 / (x+x/3) = 10
    Solve, x = 40 days

  10. A and B can do a piece of work in 10 days and 17 days respectively. They start the work on alternate days with A starting the work. In how many days the work will be completed?
    A. 12 8/17 days
    B. 12 8/15 days
    C. 12 days
    D. 13 days
    A. 12 8/17 days
    Explanation:
    2 day’s work of A + B = 1/10 + 1/17 = 27/170
    Multiply by 6 both sides
    12 day’s work of A + B = 162/170
    Remaining work = 1 – 162/170 = 8/170 = 4/85
    Now on 13th day A’s turn, he does 1/10 work in 1 day, so 4/85 work in 8/17 day.
    Total days 12 8/17