Hello Aspirants. Welcome to Online Quantitative Aptitude section in AffairsCloud.com. Here we are creating question sample From all topics , which are Important for upcoming IBPS exams. We have included Some questions that are repeatedly asked in exams.

**At a certain rate per annum, the simple interest on a sum of money for 1 year is Rs 260 and the compound interest on the same sum for 2 yrs is Rs 540.80. The rate of interest per annum is**

A. 10%

B. 4%

C. 8%

D. 6%

**C. 8%**

Explanation:

SI for 2 yrs = 2 × 260 = 520

Difference in CI and SI for 2 yrs = 540.80 – 520 = 20.80

For 2 yrs, Difference = r×SI / 2×100

So, 20.80 = r×520/2× 100

Solve, r = 8%**In how many ways the letters of word COMPLETE be arranged such that all vowels are always together?**

A. 2290

B. 1290

C. 2150

D. 2160

**D. 2160**

Explanation:

CMPLT OEE

We have to take OEE together, so in all we have 6 letters {C, M, P, L, T, OEE}

Ways for these 6 is 6!

Now for OEE, ways are 3!, and since it contains 2 E’s, so ways are 3!/2!

Total ways = 6! × 3!/2! = 2160**There are 5 males and 4 females. A committee is to be formed comprising 4 people. How many ways are there to do so such that a particular male is always to be included?**

A. 52

B. 56

C. 48

D. 30

**B. 56**

Explanation:

Since a particular male is to included always, so there remains 4 males for selection and 4 females, and also since a total of 4 is to selected, and 1 male is already included, so 3 are to be selected now.

So ways are^{8}C_{3}= 56**x**^{2}+ 28x + 195 = 0; y^{2}+ 28y – 60 = 0

A. x ≤ y

B. x ≥ y

C. x > y

D. No relationship

**C. 4**

Explanation:

x^{2}+ 28x + 195 = 0

(x+15)(x+13) = 0

x = -15, -13

y^{2}+ 28y – 60 = 0

(y+30)(y-2) = 0

y = -30, 2

put on number line

-30 -15 -13 2

We can see that no relationship can be established.**A and B together can complete the work in 4 days. A alone starts working and leaves it after working for 3 days, completing only half of the work. In how many days can it be completed if the remaining job is undertaken by B?**

A. 5

B. 8

C. 6

D. 4

**C. 6**

Explanation:

1/A + 1/B = 1/4

A works for 3 days and completes half of the work. This gives

1/A * 3 = 1/2

A = 6

So 1/B = 1/4 – 1/6 = 1/12

So B can complete a job in 12 days, so half of the job will be complete in 6 days.**A man, a woman or a boy can do a piece of work in 3, 4 and 12 days respectively. How many boys must assist one man and one woman to do the work in one day?**

A. 6

B. 5

C. 4

D. 10

**B. 5**

Explanation:

Let ‘x’ boys. So,

1/3 + 1/4 + 1/12 * x = 1

Solve, x = 5

**While selling a cooler a shopkeeper gives a discounts of 10% on the marked price. If he gives a discount of 12% he earns Rs 35 as profit. The marked price of cooler is**

A. Rs 2250

B. Rs 1750

C. Rs 1625

D. Rs 1725

**B. Rs 1750**

Explanation:

35*100 / (-10 – (-12)) = 1750**A man buys a chair and a table for Rs 6000. He sells the chair at a loss of 10% and table at a gain of 10%. He still gains Rs 100 on the whole. The cost price of table is**

A. Rs 3050

B. Rs 3500

C. Rs 2850

D. Rs 4000

**B. Rs 3500**

Explanation:

Gain% on the whole = 100/6000 * 100 = 5/3%

By the method of allegation:

-10 10

. 5/3

10 – 5/3 = 25/3 5/3 – (-10) = 35/3

Ratio = 25/3 : 35/3 = 5 : 7

So CP of table = 7/(5+7) * 6000 = 3500**If the compound interest for two successive years is Rs 1100 and Rs 1210 respectively, then what is the rate percent?**

A. 11%

B. 10%

C. 12.1%

D. None of these

**B. 10%**

Explanation:

R% of 1100 = 1210 – 1100

R/100 * 1100 = 110

R = 10%

**By selling 8 articles, a tradesman makes a loss equal to the cost price of 4 articles. Find loss%.**

A. 25%

B. 100/3%

C. 50%

D. None of these

**C. 50%**

Explanation:

C.P of 8 articles – S.P of 8 articles = C.P of 4 articles

C.P of 4 articles = S.P of 8 articles

Loss% = (8 – 4)/8 * 100 = 50%

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