Hello Aspirants. Welcome to Online Quantitative Aptitude section in AffairsCloud.com. Here we are creating question sample From all topics , which are Important for upcoming IBPS exams. We have included Some questions that are repeatedly asked in exams.
- At a certain rate per annum, the simple interest on a sum of money for 1 year is Rs 260 and the compound interest on the same sum for 2 yrs is Rs 540.80. The rate of interest per annum is
A. 10%
B. 4%
C. 8%
D. 6%C. 8%
Explanation:
SI for 2 yrs = 2 × 260 = 520
Difference in CI and SI for 2 yrs = 540.80 – 520 = 20.80
For 2 yrs, Difference = r×SI / 2×100
So, 20.80 = r×520/2× 100
Solve, r = 8% - In how many ways the letters of word COMPLETE be arranged such that all vowels are always together?
A. 2290
B. 1290
C. 2150
D. 2160D. 2160
Explanation:
CMPLT OEE
We have to take OEE together, so in all we have 6 letters {C, M, P, L, T, OEE}
Ways for these 6 is 6!
Now for OEE, ways are 3!, and since it contains 2 E’s, so ways are 3!/2!
Total ways = 6! × 3!/2! = 2160 - There are 5 males and 4 females. A committee is to be formed comprising 4 people. How many ways are there to do so such that a particular male is always to be included?
A. 52
B. 56
C. 48
D. 30B. 56
Explanation:
Since a particular male is to included always, so there remains 4 males for selection and 4 females, and also since a total of 4 is to selected, and 1 male is already included, so 3 are to be selected now.
So ways are 8C3 = 56 - x2 + 28x + 195 = 0; y2 + 28y – 60 = 0
A. x ≤ y
B. x ≥ y
C. x > y
D. No relationshipC. 4
Explanation:
x2 + 28x + 195 = 0
(x+15)(x+13) = 0
x = -15, -13
y2 + 28y – 60 = 0
(y+30)(y-2) = 0
y = -30, 2
put on number line
-30 -15 -13 2
We can see that no relationship can be established. - A and B together can complete the work in 4 days. A alone starts working and leaves it after working for 3 days, completing only half of the work. In how many days can it be completed if the remaining job is undertaken by B?
A. 5
B. 8
C. 6
D. 4C. 6
Explanation:
1/A + 1/B = 1/4
A works for 3 days and completes half of the work. This gives
1/A * 3 = 1/2
A = 6
So 1/B = 1/4 – 1/6 = 1/12
So B can complete a job in 12 days, so half of the job will be complete in 6 days. - A man, a woman or a boy can do a piece of work in 3, 4 and 12 days respectively. How many boys must assist one man and one woman to do the work in one day?
A. 6
B. 5
C. 4
D. 10B. 5
Explanation:
Let ‘x’ boys. So,
1/3 + 1/4 + 1/12 * x = 1
Solve, x = 5 - While selling a cooler a shopkeeper gives a discounts of 10% on the marked price. If he gives a discount of 12% he earns Rs 35 as profit. The marked price of cooler is
A. Rs 2250
B. Rs 1750
C. Rs 1625
D. Rs 1725B. Rs 1750
Explanation:
35*100 / (-10 – (-12)) = 1750 - A man buys a chair and a table for Rs 6000. He sells the chair at a loss of 10% and table at a gain of 10%. He still gains Rs 100 on the whole. The cost price of table is
A. Rs 3050
B. Rs 3500
C. Rs 2850
D. Rs 4000B. Rs 3500
Explanation:
Gain% on the whole = 100/6000 * 100 = 5/3%
By the method of allegation:
-10 10
. 5/3
10 – 5/3 = 25/3 5/3 – (-10) = 35/3
Ratio = 25/3 : 35/3 = 5 : 7
So CP of table = 7/(5+7) * 6000 = 3500 - If the compound interest for two successive years is Rs 1100 and Rs 1210 respectively, then what is the rate percent?
A. 11%
B. 10%
C. 12.1%
D. None of theseB. 10%
Explanation:
R% of 1100 = 1210 – 1100
R/100 * 1100 = 110
R = 10% - By selling 8 articles, a tradesman makes a loss equal to the cost price of 4 articles. Find loss%.
A. 25%
B. 100/3%
C. 50%
D. None of theseC. 50%
Explanation:
C.P of 8 articles – S.P of 8 articles = C.P of 4 articles
C.P of 4 articles = S.P of 8 articles
Loss% = (8 – 4)/8 * 100 = 50%
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