Hello Aspirants.
Welcome to Online Quantitative Aptitude Section in AffairsCloud.com. Here we are creating question sample in Number Series and Quadratic Equations based on prelim pattern, which is common for SBI,IBPS, RBI,LIC, NICL and other  competitive exams.
Q(1-5) In the following questions two equations numbered I & II are given. You have to solve both equations and mark one of the option given below.
- I. 2X² – 27√2X + 182 = 0
II. 3Y² – 29√3Y + 210 =0
A. X > Y
B. X < Y
C. X ≥ Y
D. X ≤ Y
E. X = Y or relationship cannot be establishedAnswer – B. X < Y
Explanation :
X = 13/√2, 14/√2
Y = 14/√3, 15/√3 - I. 91X² + 128X + 45 = 0
II. 28Y² + 41Y + 15 =0
A. X > Y
B. X < Y
C. X ≥ Y
D. X ≤ Y
E. X = Y or relationship cannot be establishedAnswer – C. X ≥ Y
Explanation :
X = -9/13, -5/7
Y = -5/7, -3/4 - I. X² -15√2X + 100 = 0
II.Y² – 25√2Y + 300 =0
A. X > Y
B. X < Y
C. X ≥ Y
D. X ≤ Y
E. X = Y or relationship cannot be establishedAnswer – D. X ≤ YÂ
Explanation :
X = 5√2, 10√2
Y = 10√2, 15√2 - I. X² -55X +756 = 0
II. Y² -59Y +870 =0
A. X > Y
B. X < Y
C. X ≥ Y
D. X ≤ Y
E. X = Y or relationship cannot be establishedAnswer – B. X < Y
Explanation :
X = 27,28
Y = 29,30 - I. 22X² -59X +39 = 0
II. 18Y² -73Y +70 =0
A. X > Y
B. X < Y
C. X ≥ Y
D. X ≤ Y
E. X = Y or relationship cannot be establishedAnswer – B. X < Y
Explanation :
X = 13/11, 3/2
Y = 14/9, 5/2 - Shiva is running on a road at the rate of 10 Km/hr. In the same direction a Bus going at a speed of 130 Km/hr passed him. He could see the Bus only for 30 Seconds. Then up to what distance he could see the Bus?
A. 1 Km
B. 2 Km
C. 3 Km
D. 4 Km
E. Cannot be determinedAnswer – A. 1 Km
Explanation :
130-10 = x/30*18/5
x = 1000 m - iPhone 7 is available at cost of Rs.45,999 in Market. Airtel Company introduced a Plan where we can buy mobile with one time down payment of Rs. 8308. After that we need to pay for Rs.1999 EMI for some months. Rajesh bought mobile through this offer, then in total he paid Rs. 10285 more than actual cost of Mobile. Then for how many Months did Rajesh paid EMI?
A. 12 Months
B. 18 Months
C. 24 Months
D. 30 Months
E. NoneAnswer – C. 24 Months
Explanation :
Total money paid = 45999+10285 = 56284
56284= 8308+1999*x
x = 24 - Bhaskar had two sons Uday and Surya whose ages are 12 and 14 Years respectively. He deposited equal money on each of them in two different Banks which offered 6% , 8% Simple Interest to Uday and Surya respectively. Bhaskar plan is such that at certain age both of their amounts will become equal. Then at what age their amounts will be equal?
A. 20
B. 21
C. 24
D. 27
E. Cannot be determinedAnswer – A. 20
Explanation :
(x-12)*6 = (x-14)*8
X =20 - Ravi took a Loan of 4Lakh rupees from a Bank on a condition that he will be charged at 5% p.a. at CI for the first 2 years and at 10% p.a. at CI for the rest of the years. After 2 years he returned 2/3 amount which has to be paid. He returned remaining amount again after 2 years. Then what is the total amount paid by him to Bank?
A. 618770
B. 618780
C. 617780
D. 618870
E. NoneAnswer – D. 618870
Explanation :
@5% = 4L*(1+5/100) 2 = 441000
returned 2/3 = 147000
@10% = 147000*(1+10/100) 2 = 177870
Total = 441000+177870 = 618870 - A container is filled upto 80% of its capacity with mixture of Water and Milk in the ratio of 1:3. Now 1/25 th of Mixture is taken out and 24 litres of water is added. Then the ratio of Water to Milk becomes 1:2. Then what is capacity of Jar in litre?
A. 200
B. 250
C. 300
D. 400
E. Cannot be determinedAnswer – B. 250
Explanation :
W/M = 1:3
(x-x/25+24)/(3x- 3x/25) = 1:2
x = 50 4x =200
capacity of jar = 250
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