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Question 1 of 15
1. Question
1 pointsCategory: Quantitative AptitudeA work is to be completed in 10 days. 5 men started the work. After 4 days, it was realized that the work will not be completed on time, so a second group of 5 more men were employed whose efficiency was twice that of the previous men. In how many days the work can be completed by 1 man of 2nd group?
Correct
Explanation:
Let 1 man of 1st group can do work in x days, so 1 man of 2nd group will do in (x/2) days [efficiency is twice so days are halved].
Five men of 1st group did wok for all 10 days so, and 5 men of 2nd group did work for (104)=6 days.
5 men of first group will do work in 1 day = (1/x)*5, so in 10 days = (1/x)*5 * 10. Similarly with second group. so
(1/x)*5 * 10 + (2/x)*5 * 6 = 1
Solve, x = 110,
So 1 man of second group will do work in (110/2) daysIncorrect
Explanation:
Let 1 man of 1st group can do work in x days, so 1 man of 2nd group will do in (x/2) days [efficiency is twice so days are halved].
Five men of 1st group did wok for all 10 days so, and 5 men of 2nd group did work for (104)=6 days.
5 men of first group will do work in 1 day = (1/x)*5, so in 10 days = (1/x)*5 * 10. Similarly with second group. so
(1/x)*5 * 10 + (2/x)*5 * 6 = 1
Solve, x = 110,
So 1 man of second group will do work in (110/2) days 
Question 2 of 15
2. Question
1 pointsCategory: Quantitative AptitudeThe ratio of the age of A 4 years hence and B’s present age is 8 : 9. After 12 years A’s age will be 12 less than twice B’s present age. Find the ratio of A’s present age to B’s age 4 years ago.
Correct
Explanation:
(A+4)/B = 8/9 so 9A – 8B = 36
Also (A+12) = 2B – 12, so A – 2B = 24
Solve, both equations, A = 12, B= 18
So required ratio is 12/(184) = 12/14Incorrect
Explanation:
(A+4)/B = 8/9 so 9A – 8B = 36
Also (A+12) = 2B – 12, so A – 2B = 24
Solve, both equations, A = 12, B= 18
So required ratio is 12/(184) = 12/14 
Question 3 of 15
3. Question
1 pointsCategory: Quantitative AptitudeA boy started from point P at 50 km/hr. After 1 hour another boy started from point P at 60 km/hr in the same direction as the first boy. After how much time the second boy will meet the first one?
Correct
Explanation:
Let first boy meets after t hours when he started, so second boy took (t1) hours to reach the same distance.
So distance covered by first boy in t hours = distance covered by second boy in (t1) hours
50*t = 60*(t1)
Solve, t = 6 hours
So second boy met first after (61) = 5 hoursIncorrect
Explanation:
Let first boy meets after t hours when he started, so second boy took (t1) hours to reach the same distance.
So distance covered by first boy in t hours = distance covered by second boy in (t1) hours
50*t = 60*(t1)
Solve, t = 6 hours
So second boy met first after (61) = 5 hours 
Question 4 of 15
4. Question
1 pointsCategory: Quantitative AptitudeThere were 5000 students in a school. In a year school lost its reputation so 5% students left the school. The teachers work harder so the percentage of students grew by 5% and 10% in the subsequent two years. What is the approximate number of students in the school after 3 years?
Correct
Explanation:
5000 (100 – 5/100) (100 + 5/100) (100 + 10/100)
= 5000 (95/100) (105/100) (110/100) = 95*105*11/20 = 5486.25 ≈ 5490Incorrect
Explanation:
5000 (100 – 5/100) (100 + 5/100) (100 + 10/100)
= 5000 (95/100) (105/100) (110/100) = 95*105*11/20 = 5486.25 ≈ 5490 
Question 5 of 15
5. Question
1 pointsCategory: Quantitative AptitudeA box contains 6 blue and 5 yellow balls. Two balls are drawn one by one with replacement. What is the probability that both balls are different in color?
Correct
Explanation:
Balls are drawn one by one so 2 cases:
When first ball is blue prob. = 6/11 * 5/11 = 30/121 [since replacement so 11 in both denominators]
When first ball is yellow prob. = 5/11 * 6/11 = 30/121
Add both casesIncorrect
Explanation:
Balls are drawn one by one so 2 cases:
When first ball is blue prob. = 6/11 * 5/11 = 30/121 [since replacement so 11 in both denominators]
When first ball is yellow prob. = 5/11 * 6/11 = 30/121
Add both cases 
Question 6 of 15
6. Question
1 pointsCategory: Quantitative AptitudeDirections (6 – 10): Study the following table and answer the questions that follow:
The table shows the number of students in 5 sections – A, B, C, D and E of class 10 in a school, the percentage of girls in each section and the ratio of number of boys who come by bus and who do not come by bus in the respective sections.Sections Total No. of
Students% of Girls Ratio of number of boys
who come by bus to
who do not come by busA 450 20% 2 7 B 290 40% 1 2 C 360 35% 4 5 D 540 25% 2 3 E 250 20% 7 3 Approximately what percentage of girls in section B are less than that in section C?
Correct
Explanation:
Girls in section B = (40/100)*290 = 116
In section C = (35/100)*360 = 126
Required % = (126116)/126 * 100 ≈ 8%Incorrect
Explanation:
Girls in section B = (40/100)*290 = 116
In section C = (35/100)*360 = 126
Required % = (126116)/126 * 100 ≈ 8% 
Question 7 of 15
7. Question
1 pointsCategory: Quantitative AptitudeDirections (6 – 10): Study the following table and answer the questions that follow:
The table shows the number of students in 5 sections – A, B, C, D and E of class 10 in a school, the percentage of girls in each section and the ratio of number of boys who come by bus and who do not come by bus in the respective sections.Sections Total No. of
Students% of Girls Ratio of number of boys
who come by bus to
who do not come by busA 450 20% 2 7 B 290 40% 1 2 C 360 35% 4 5 D 540 25% 2 3 E 250 20% 7 3 How many boys in section D do not come by bus?
Correct
Explanation:
3/5 * (75/100)*540Incorrect
Explanation:
3/5 * (75/100)*540 
Question 8 of 15
8. Question
1 pointsCategory: Quantitative AptitudeDirections (6 – 10): Study the following table and answer the questions that follow:
The table shows the number of students in 5 sections – A, B, C, D and E of class 10 in a school, the percentage of girls in each section and the ratio of number of boys who come by bus and who do not come by bus in the respective sections.Sections Total No. of
Students% of Girls Ratio of number of boys
who come by bus to
who do not come by busA 450 20% 2 7 B 290 40% 1 2 C 360 35% 4 5 D 540 25% 2 3 E 250 20% 7 3 What is the difference between the total number of girls in A section and number of boys in B section who come by bus
Correct
Explanation:
Girls in A = (20/100)*450 = 90
Boys in B who come by bus = (1/3) * (60/100)*290 = 58
Difference = 9058Incorrect
Explanation:
Girls in A = (20/100)*450 = 90
Boys in B who come by bus = (1/3) * (60/100)*290 = 58
Difference = 9058 
Question 9 of 15
9. Question
1 pointsCategory: Quantitative AptitudeDirections (6 – 10): Study the following table and answer the questions that follow:
The table shows the number of students in 5 sections – A, B, C, D and E of class 10 in a school, the percentage of girls in each section and the ratio of number of boys who come by bus and who do not come by bus in the respective sections.Sections Total No. of
Students% of Girls Ratio of number of boys
who come by bus to
who do not come by busA 450 20% 2 7 B 290 40% 1 2 C 360 35% 4 5 D 540 25% 2 3 E 250 20% 7 3 What is the total number of boys in section D and E?
Correct
Explanation:
D + E
(75/100)*540 + (80/100)*250 = 405+200Incorrect
Explanation:
D + E
(75/100)*540 + (80/100)*250 = 405+200 
Question 10 of 15
10. Question
1 pointsCategory: Quantitative AptitudeDirections (6 – 10): Study the following table and answer the questions that follow:
The table shows the number of students in 5 sections – A, B, C, D and E of class 10 in a school, the percentage of girls in each section and the ratio of number of boys who come by bus and who do not come by bus in the respective sections.Sections Total No. of
Students% of Girls Ratio of number of boys
who come by bus to
who do not come by busA 450 20% 2 7 B 290 40% 1 2 C 360 35% 4 5 D 540 25% 2 3 E 250 20% 7 3 What is the ratio of number of boys who come by bus in section C to number of boys who do not come by bus in section B?
Correct
Explanation:
Boys who come by bus in section C = (4/9) * (65/100)*360 = 104
Boys who do not come by bus in section B = (2/3) * (60/100)*290 = 116
104 : 116 = 26 : 29Incorrect
Explanation:
Boys who come by bus in section C = (4/9) * (65/100)*360 = 104
Boys who do not come by bus in section B = (2/3) * (60/100)*290 = 116
104 : 116 = 26 : 29 
Question 11 of 15
11. Question
1 pointsCategory: Quantitative AptitudeDirections (1115): In the following questions, solve and find what will come in place of ?
4/5 + 1/3 + 5/7 + 6 (2/3) = ?
Correct
Explanation:
4/5 + 1/3 + 5/7 + 6 (2/3)
4/5 + 5/7 + 1/3 +20/3
4/5 + 5/7 + 7 = 298/35Incorrect
Explanation:
4/5 + 1/3 + 5/7 + 6 (2/3)
4/5 + 5/7 + 1/3 +20/3
4/5 + 5/7 + 7 = 298/35 
Question 12 of 15
12. Question
1 pointsCategory: Quantitative AptitudeDirections (1115): In the following questions, solve and find what will come in place of ?
2256 – 1865 + 567 – 259 = ?
Correct
Explanation:
2256 – 1865 + 567 – 259 = ?
(2256 + 567) – (1865 + 259) = ?Incorrect
Explanation:
2256 – 1865 + 567 – 259 = ?
(2256 + 567) – (1865 + 259) = ? 
Question 13 of 15
13. Question
1 pointsCategory: Quantitative AptitudeDirections (1115): In the following questions, solve and find what will come in place of ?
(55)^{2} + 36 × 19 – (30)^{2} = (?)^{2}
Correct
Explanation:
(55)^{2} + 36 × 19 – (30)^{2} = (?)^{2}
3025 + 684 – 900 = (?)^{2}
√2809 = ?Incorrect
Explanation:
(55)^{2} + 36 × 19 – (30)^{2} = (?)^{2}
3025 + 684 – 900 = (?)^{2}
√2809 = ? 
Question 14 of 15
14. Question
1 pointsCategory: Quantitative AptitudeDirections (1115): In the following questions, solve and find what will come in place of ?
27 × 524 ÷ 4 + 39 – 23 = ?
Correct
Explanation:
27 × 524 ÷ 4 + 39 – 23 = ?
27 × 131 + 39 – 23 = ?
27 × 131 + 39 – 23 = ?
3537 + 16 = ?Incorrect
Explanation:
27 × 524 ÷ 4 + 39 – 23 = ?
27 × 131 + 39 – 23 = ?
27 × 131 + 39 – 23 = ?
3537 + 16 = ? 
Question 15 of 15
15. Question
1 pointsCategory: Quantitative AptitudeDirections (1115): In the following questions, solve and find what will come in place of ?
21% of 450 + √3136 = 6*12.5 + ?
Correct
Explanation:
21% of 450 + √3136 = 6*12.5 + ?
94.50 + 56 = 75 + ?Incorrect
Explanation:
21% of 450 + √3136 = 6*12.5 + ?
94.50 + 56 = 75 + ?
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