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Question 1 of 15
1. Question
1 pointsCategory: Quantitative AptitudeDirections (1 – 5): Study the pie chart and answer the questions that follow:
The pie chart shows the monthly expenses of a person done on various items.
If the monthly salary of the person is Rs 6,000, for how many items he has spent more than Rs 1,000 per month?
Correct
Explanation:
Shortcut
(x/100)*6000 = 1000, gives x = 16.67%
So the ones having more expense % than 16.67% which is A and CIncorrect
Explanation:
Shortcut
(x/100)*6000 = 1000, gives x = 16.67%
So the ones having more expense % than 16.67% which is A and C 
Question 2 of 15
2. Question
1 pointsCategory: Quantitative AptitudeDirections (1 – 5): Study the pie chart and answer the questions that follow:
The pie chart shows the monthly expenses of a person done on various items.
What will be the annual expenses on item C in the case provided in question 1?
Correct
Explanation:
For C = (23/100)*6000 = 1380
So annually = 1380*12 = 16560Incorrect
Explanation:
For C = (23/100)*6000 = 1380
So annually = 1380*12 = 16560 
Question 3 of 15
3. Question
1 pointsCategory: Quantitative AptitudeDirections (1 – 5): Study the pie chart and answer the questions that follow:
The pie chart shows the monthly expenses of a person done on various items.
If the person spends Rs 500 per month on item E, what will be his monthly salary?
Correct
Explanation:
(10/100)*x = 500Incorrect
Explanation:
(10/100)*x = 500 
Question 4 of 15
4. Question
1 pointsCategory: Quantitative AptitudeDirections (1 – 5): Study the pie chart and answer the questions that follow:
The pie chart shows the monthly expenses of a person done on various items.
Expenses on item D are approximately how much percent more than on item B, if the monthly salary of the person is Rs 12,000?
Correct
Explanation:
Required % = (157)/7 * 100Incorrect
Explanation:
Required % = (157)/7 * 100 
Question 5 of 15
5. Question
1 pointsCategory: Quantitative AptitudeDirections (1 – 5): Study the pie chart and answer the questions that follow:
The pie chart shows the monthly expenses of a person done on various items.
What is the angle made at the centre of the pie chart by the sector representing the expenses on item F?
Correct
Explanation:
(15/100)*360 = 54Incorrect
Explanation:
(15/100)*360 = 54 
Question 6 of 15
6. Question
1 pointsCategory: Quantitative AptitudeRs 20,000 was invested at 20% rate of interest per annum. What is the total interest earned after 2 years if the interest is compounded half yearly for the first year and compounded yearly for the second year?
Correct
Explanation:
Amount after 1st year = 20,000 [(1+10/100)]^{2} = Rs 24,200
Amount after 2nd year = 24,200 [(1+20/100)]^{1} = Rs 29,040
So CI = 29040 – 20000 = 9040Incorrect
Explanation:
Amount after 1st year = 20,000 [(1+10/100)]^{2} = Rs 24,200
Amount after 2nd year = 24,200 [(1+20/100)]^{1} = Rs 29,040
So CI = 29040 – 20000 = 9040 
Question 7 of 15
7. Question
1 pointsCategory: Quantitative AptitudeA and B started from a same point in same direction with their speeds being in the ratio 3 : 4. What is the time taken by B to reach their destination if A took 30 minutes more than B to reach destination?
Correct
Explanation:
Let time taken by B is t hrs, then by A is (t + 30/60) hrs
Speeds ratio = 3 : 4
Distance is same. So
3 * (t + 1/2) = 4 * t
Solve, t = 1 1/2 hrsIncorrect
Explanation:
Let time taken by B is t hrs, then by A is (t + 30/60) hrs
Speeds ratio = 3 : 4
Distance is same. So
3 * (t + 1/2) = 4 * t
Solve, t = 1 1/2 hrs 
Question 8 of 15
8. Question
1 pointsCategory: Quantitative AptitudePipes A, B and C are such that A and B can fill tank in 15 and 20 hours respectively and C can empty tank in 30 hours. First A is opened for 2 hours, than B for 2 hours and then C for 2 hours. This process continued until the tank got filled. In how many hours will the tank get filled this way?
Correct
Explanation:
In 1 hour, A does 1/15 work, B does 1/20 work and C does 1/30 work
So in 2 hours, A does 2/15 work, B does 2/20 work and C does 2/30 work
After (2+2+2) = 6 hours, work done is (2/15) + (2/20) – (2/130) = 1/6
Multiply by 5 both sides, so
After 30 hours, work done is 5/6
Remaining work = 1 – 5/6 = 1/6. Now after this there is A’s turn and in next 2 hours A does 2/15 work, so now work left = 1/6 – 2/15 = 1/30
So now 32 hours passed, remaining work is 1/30 and there is B’s turn. B does 1/20 work in 1 hour, so the remaining 1/30 work in 2/3 hours
So total 32 2/3 hoursIncorrect
Explanation:
In 1 hour, A does 1/15 work, B does 1/20 work and C does 1/30 work
So in 2 hours, A does 2/15 work, B does 2/20 work and C does 2/30 work
After (2+2+2) = 6 hours, work done is (2/15) + (2/20) – (2/130) = 1/6
Multiply by 5 both sides, so
After 30 hours, work done is 5/6
Remaining work = 1 – 5/6 = 1/6. Now after this there is A’s turn and in next 2 hours A does 2/15 work, so now work left = 1/6 – 2/15 = 1/30
So now 32 hours passed, remaining work is 1/30 and there is B’s turn. B does 1/20 work in 1 hour, so the remaining 1/30 work in 2/3 hours
So total 32 2/3 hours 
Question 9 of 15
9. Question
1 pointsCategory: Quantitative AptitudeA certain amount invested at 5% rate of interest per annum for 4 years gave a simple interest of Rs 312. If the same amount would have been invested at 4% rate of interest per annum compounded annually, what would be the compound interest obtained after same time?
Correct
Explanation:
312 = P*5*4/100
So principal = Rs 1560
CI = 1560 [(1 +4/100)^2 – 1]
= 1560 [729/625 – 1]Incorrect
Explanation:
312 = P*5*4/100
So principal = Rs 1560
CI = 1560 [(1 +4/100)^2 – 1]
= 1560 [729/625 – 1] 
Question 10 of 15
10. Question
1 pointsCategory: Quantitative AptitudeA solution contains milk and water in the ratio 3 : 2. In 500 gms of solution, 100 gms of water is added. Find the percentage of water in the solution thus formed?
Correct
Explanation:
In 500 gm, water is 2/5 * 500 = 200 gm
Now 100 gm of water added, so water become (200+100) = 300gm
Total solution becomes (500+100) = 600 gm
Required % = (300/600) * 100Incorrect
Explanation:
In 500 gm, water is 2/5 * 500 = 200 gm
Now 100 gm of water added, so water become (200+100) = 300gm
Total solution becomes (500+100) = 600 gm
Required % = (300/600) * 100 
Question 11 of 15
11. Question
1 pointsCategory: Quantitative AptitudeA bag contains 3 white, 4 black and 5 green marbles. If 2 marbles are drawn at random from the bag, find the probability that both balls are different in color?
Correct
Explanation:
Case 1: 1 white+1 black
^{3}C_{1}*^{4}C_{1}/^{12}C_{2}
Case 2: 1 white+1 green
^{3}C_{1}*^{5}C_{1}/^{12}C_{2}
Case 3: 1 green+1 black
^{5}C_{1}*^{4}C_{1}/^{12}C_{2}
Add all cases
Or
find prob of both same color and subtract from 1Incorrect
Explanation:
Case 1: 1 white+1 black
^{3}C_{1}*^{4}C_{1}/^{12}C_{2}
Case 2: 1 white+1 green
^{3}C_{1}*^{5}C_{1}/^{12}C_{2}
Case 3: 1 green+1 black
^{5}C_{1}*^{4}C_{1}/^{12}C_{2}
Add all cases
Or
find prob of both same color and subtract from 1 
Question 12 of 15
12. Question
1 pointsCategory: Quantitative AptitudeThe ratio of ages of Amit and Charu is 4 : 9 and that of Amit and Bhavna is 2 : 3. If the difference in ages of Bhavna and Charu is 15 years, what is the total of the ages of all of three?
Correct
Explanation:
B/A = 3/2 and A/C = 4/9
So B : A : C = 3*4 : 2*4 : 2*9 = 6 : 4 : 9
So 9x – 6x = 15, this gives x = 5
So age of A = 4x = 20
Age of B = 6x = 30
Age of C = 9x = 45Incorrect
Explanation:
B/A = 3/2 and A/C = 4/9
So B : A : C = 3*4 : 2*4 : 2*9 = 6 : 4 : 9
So 9x – 6x = 15, this gives x = 5
So age of A = 4x = 20
Age of B = 6x = 30
Age of C = 9x = 45 
Question 13 of 15
13. Question
1 pointsCategory: Quantitative AptitudeA three step process removes the impurities step by step from the material as 60%, 50% and 20% respectively. If after performing 3 steps also, 3600 units of impurities are present, what was the number of impurities present originally in the material?
Correct
Explanation:
Let x units of impurities present initially
After first stage, 60% impurities removed, so 40% remained
After second stage, 50% impurities removed, so 50% remained. And after third stage, 20% impurities removed, so 80% remained.
So x*(40/100)*(50/100)*(80/100) = 3600
Solve, x = 22,500Incorrect
Explanation:
Let x units of impurities present initially
After first stage, 60% impurities removed, so 40% remained
After second stage, 50% impurities removed, so 50% remained. And after third stage, 20% impurities removed, so 80% remained.
So x*(40/100)*(50/100)*(80/100) = 3600
Solve, x = 22,500 
Question 14 of 15
14. Question
1 pointsCategory: Quantitative Aptitude40 men can complete a work in 96 days. They all started the work, and after 24 days 20 more men joined. Some men left after further 32 days. If the remaining work now completed in 20 days, what is the number of men who left?
Correct
Explanation:
Shortcut:
40*96 = 40*24 + 60*32 + (60x)*20
Solve, x = 12
OR
40 men complete work in 96 days. So 60 men in (40*96)/60 = 64 days
40 men worked for 20 days, after this (40+20) = 60 men worked for 32 days, after this (60x) men completed the work in 20 more days.
Let these (60x) men completes 1 work in y days.
So (1/96)*24 + (1/64)*32 + (1/y)*20 = 1
Solve, y = 80
This means (60x) men complete 1 work in 80 days
M1*D1 = M2*D2
40*96 = (60x)*80
Solve, x = 12Incorrect
Explanation:
Shortcut:
40*96 = 40*24 + 60*32 + (60x)*20
Solve, x = 12
OR
40 men complete work in 96 days. So 60 men in (40*96)/60 = 64 days
40 men worked for 20 days, after this (40+20) = 60 men worked for 32 days, after this (60x) men completed the work in 20 more days.
Let these (60x) men completes 1 work in y days.
So (1/96)*24 + (1/64)*32 + (1/y)*20 = 1
Solve, y = 80
This means (60x) men complete 1 work in 80 days
M1*D1 = M2*D2
40*96 = (60x)*80
Solve, x = 12 
Question 15 of 15
15. Question
1 pointsCategory: Quantitative AptitudeA and B started a business by investing Rs10,000 and Rs 11,000 respectively. After 4 months they both withdrew Rs 1000. After a further of half year, A invested Rs 1000 more and B invested Rs 2000 more. If a total profit received after a year is Rs 54,450, what is the difference in the shares of A and B?
Correct
Explanation:
10000*4 + 9000*6 + 10000*2 : 11000*4 + 10000*6 + 12000*2
10000*6 + 9000*6 : 11000*4 + 10000*6 + 12000*2
10*6 + 9*6 : 11*4 + 10*6 + 12*2
10*3 + 9*3 : 11*2 + 10*3 + 12
57 : 64
Difference = (6457)/(57+64) * 54450Incorrect
Explanation:
10000*4 + 9000*6 + 10000*2 : 11000*4 + 10000*6 + 12000*2
10000*6 + 9000*6 : 11000*4 + 10000*6 + 12000*2
10*6 + 9*6 : 11*4 + 10*6 + 12*2
10*3 + 9*3 : 11*2 + 10*3 + 12
57 : 64
Difference = (6457)/(57+64) * 54450
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