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Question 1 of 15
1. Question
1 points
Category: Quantitative Aptitude
A bag contains 25 paise, 50 paise, and Rs 2 coins in the ratio 12 : 15 : 20 respectively. If the total value of money in bag is Rs 505, what is the total number of coins in the bag?
Correct
Explanation:
Coins – 12x, 15x, 20x, so
Value of 25 paise coins = (25/100)*12x = 3x, of 50 paise coin = (50/100)*15x = 15x/2, of Rs 2 coins = 2*20x = 40x
So total value is 3x+(15x/2)+40x = 101x/2 which equals 505, so x = 10
Total coins = 12x+15x+20x = 47x = 470
Incorrect
Explanation:
Coins – 12x, 15x, 20x, so
Value of 25 paise coins = (25/100)*12x = 3x, of 50 paise coin = (50/100)*15x = 15x/2, of Rs 2 coins = 2*20x = 40x
So total value is 3x+(15x/2)+40x = 101x/2 which equals 505, so x = 10
Total coins = 12x+15x+20x = 47x = 470
Question 2 of 15
2. Question
1 points
Category: Quantitative Aptitude
The speed of stream is 4 km/hr. To travel 10 km upstream, 20 minutes are taken more than to travel 10 km downstream by a boat. What is the downstream speed?
Correct
Explanation:
Let speed of boat in still water = x km/hr
So speed upstream = x-4, and speed downstream = x+4
Now given:
Time to travel 10 km downstream + 20/60= time to travel 10 km upstream
So 10/(x+4) + 1/3 = 10/(x-4)
10/(x-4) – 10/(x+4) = 1/3
10x+40 – (10x-40)/(x2 – 16) = 1/3
80/(x2 – 16) = 1/3
x2 – 16 = 240
solve, x = 16
so downstream speed = 16+4
Incorrect
Explanation:
Let speed of boat in still water = x km/hr
So speed upstream = x-4, and speed downstream = x+4
Now given:
Time to travel 10 km downstream + 20/60= time to travel 10 km upstream
So 10/(x+4) + 1/3 = 10/(x-4)
10/(x-4) – 10/(x+4) = 1/3
10x+40 – (10x-40)/(x2 – 16) = 1/3
80/(x2 – 16) = 1/3
x2 – 16 = 240
solve, x = 16
so downstream speed = 16+4
Question 3 of 15
3. Question
1 points
Category: Quantitative Aptitude
From a vessel containing milk, 4 litres is drawn out and at the same time 6 litres of water poured. Now 6 l of the mixture formed is taken out. If the initial quantity of milk in the vessel is 34 litres, what is the remaining quantity of milk in the mixture?
Correct
Explanation:
4 l drawn, milk = 34-4 = 30 l, water added 6 l
So ratio of milk to water is 30 : 6 = 5 : 1
Now 6 l of mixture taken out, so remaining milk is = 30 – (5/6) * 6 = 25
Incorrect
Explanation:
4 l drawn, milk = 34-4 = 30 l, water added 6 l
So ratio of milk to water is 30 : 6 = 5 : 1
Now 6 l of mixture taken out, so remaining milk is = 30 – (5/6) * 6 = 25
Rs 5800 is to be invested in two schemes such that interest after 5 years and 4 years is same on respective parts. If scheme A offers 12% rate of interest and scheme B offers 14% rate of interest, what is the amount invested in scheme A?
Correct
Explanation:
Shortcut when interests are equal:
1/(5*12) : 1/((4*14)
14 : 15
So amount invested in scheme A = (14/29) * 5800 = 2800
Incorrect
Explanation:
Shortcut when interests are equal:
1/(5*12) : 1/((4*14)
14 : 15
So amount invested in scheme A = (14/29) * 5800 = 2800
Question 7 of 15
7. Question
1 points
Category: Quantitative Aptitude
How many kg of wheat costing Rs 10 per kg must be mixed with 16 Kg of wheat costing Rs 15 per Kg, so that there may be gain of 30% by selling the mixture of Rs 15.6 per Kg?
Correct
Explanation:
With 30% gain and SP = 15.6, CP = (100/130)*15.6 = 12
By method of allegation:
1st wheat (x kg)…………..2nd wheat (16 kg)
10……………………………..…….15
.,…………………..12
3………………………………………2
3 : 2
So x/16 = 3/2
Incorrect
Explanation:
With 30% gain and SP = 15.6, CP = (100/130)*15.6 = 12
By method of allegation:
1st wheat (x kg)…………..2nd wheat (16 kg)
10……………………………..…….15
.,…………………..12
3………………………………………2
3 : 2
So x/16 = 3/2
Question 8 of 15
8. Question
1 points
Category: Quantitative Aptitude
A trader bought an article at 10% discount. The same article is sold at 20% above the marked price. What will be the actual profit percent of trader in this transaction?
Correct
Explanation:
Let MP = 100, so CP for trader = Rs 90 (at 10% discount)
And he sold at 20% above MP, so SP for trader = 120
So profit% = (120-90)/90 * 100
Incorrect
Explanation:
Let MP = 100, so CP for trader = Rs 90 (at 10% discount)
And he sold at 20% above MP, so SP for trader = 120
So profit% = (120-90)/90 * 100
Question 9 of 15
9. Question
1 points
Category: Quantitative Aptitude
There are 4 boys and 5 girls from which 5 people are to be selected. Find the number of ways in which they can be selected so that a particular girl is always selected.
Correct
Explanation:
A particular girl is already selected from the 5 girls
This means now 4 girls left and 4 boys. From these 8 people, 4 are to be selected.
So 8C4
Incorrect
Explanation:
A particular girl is already selected from the 5 girls
This means now 4 girls left and 4 boys. From these 8 people, 4 are to be selected.
So 8C4
Question 10 of 15
10. Question
1 points
Category: Quantitative Aptitude
A and B can complete a work in 40 and 60 days respectively. They started a work which is to be completed in 20 days. But it was found that they will not be able to complete work on time, so a third person C was appointed after 12 days. In how many days C can alone complete the work?
Correct
Explanation:
A and B worked for 20 days. In 1 days they could have completed work (1/40 + 1/60) = 1/24
So in 20 days, they did (1/24)*20 = 5/6
This means C did 1 – 5/6 = 1/6 of work in 8 days
So he can do 1 work in 48 days
Incorrect
Explanation:
A and B worked for 20 days. In 1 days they could have completed work (1/40 + 1/60) = 1/24
So in 20 days, they did (1/24)*20 = 5/6
This means C did 1 – 5/6 = 1/6 of work in 8 days
So he can do 1 work in 48 days
Question 11 of 15
11. Question
1 points
Category: Quantitative Aptitude
A sum of rupees is divided between three people A, B and C in such a way that after 2 years, 3 years and 4 years respectively the amount they get is equal. If the rate of interest is 5 percent, what is the ratio in which the amount is divided?
Correct
Incorrect
Question 12 of 15
12. Question
1 points
Category: Quantitative Aptitude
A rectangular park has dimensions 100m × 40m. A circular lawn is in the middle of park. If the area of rectangular park leaving the circular lawn is 1536 m2, what is the circumference of the circular lawn?
Correct
Explanation:
Area of park = 100*40 = 4000
So area of circular lawn = 4000-1536 = 2464
So ᴨr2 = 2464
Solve, r = 28
So circumference = 2ᴨr
Incorrect
Explanation:
Area of park = 100*40 = 4000
So area of circular lawn = 4000-1536 = 2464
So ᴨr2 = 2464
Solve, r = 28
So circumference = 2ᴨr
Question 13 of 15
13. Question
1 points
Category: Quantitative Aptitude
20 men can complete a work in 48 days. 12 men start the work and after working for 20 days, 4 more men join. After working for 30 days more, how many more men are needed to be joined so that the remaining work gets completed in 10 days?
Correct
Explanation:
Shortcut:
20*48 = 12*20 + 16*30 + (16+x)*10
Solve, x = 8
OR
20 men in 48 days, so 12 in (20*48)/12 = 80
They worked for 20 days, so did (1/80)*20 = 1/4 of work
Now 4 more men joined, so 16 men can do in (20*48)/16 = 60 days
They worked for 30 days, so they did (1/60)*30 = 1/2 of work
Now work done = (1/4) +(1/2) = 3/4, so remaining work = 1 – 3/4 = 1/4
This 1/4 work is to be completed in 10 days.
20 men do 1 work in 48 days, so let (16+x) men do 1/4 work in 10 days
So 20*48*(1/4) = (16+x)*10*1
Solve, x = 8
Incorrect
Explanation:
Shortcut:
20*48 = 12*20 + 16*30 + (16+x)*10
Solve, x = 8
OR
20 men in 48 days, so 12 in (20*48)/12 = 80
They worked for 20 days, so did (1/80)*20 = 1/4 of work
Now 4 more men joined, so 16 men can do in (20*48)/16 = 60 days
They worked for 30 days, so they did (1/60)*30 = 1/2 of work
Now work done = (1/4) +(1/2) = 3/4, so remaining work = 1 – 3/4 = 1/4
This 1/4 work is to be completed in 10 days.
20 men do 1 work in 48 days, so let (16+x) men do 1/4 work in 10 days
So 20*48*(1/4) = (16+x)*10*1
Solve, x = 8
Question 14 of 15
14. Question
1 points
Category: Quantitative Aptitude
A and B entered into a partnership with A invested Rs 5000 for 8 months and B invested Rs 5500 for 6 months. In the last 4 months, both invested Rs 7000 and Rs 8000 respectively. If after a year, a total of Rs 31,920 is gained as a profit, what is A’s share in the profit?
Correct
Explanation:
5000*8 + 7000*4 : 5500*6 + 8000*4
68 : 65
So A got = (68/133)*31920
Incorrect
Explanation:
5000*8 + 7000*4 : 5500*6 + 8000*4
68 : 65
So A got = (68/133)*31920
Question 15 of 15
15. Question
1 points
Category: Quantitative Aptitude
A starts from point P at 20 km/hr towards point Q. After 2 hours B starts from point Q at some speed towards A. They both meet when they reach half the distance between points P and Q. If A covered one-fourth of total distance in 2 hours, what is the speed of B?
Correct
Explanation:
A covered one-fourth of total distance in 2 hours, so 1/2 distance in 4 hours
Now B has covered that same distance that A covered in (4-2) = 2 hours [B started after 2 hrs]
And since distances are same
So distance by A = distance covered by B gives
20*4 = x*2
Solve, x = 40km/hr
Incorrect
Explanation:
A covered one-fourth of total distance in 2 hours, so 1/2 distance in 4 hours
Now B has covered that same distance that A covered in (4-2) = 2 hours [B started after 2 hrs]
And since distances are same
So distance by A = distance covered by B gives
20*4 = x*2
Solve, x = 40km/hr
