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Question 1 of 15

1. Question

1 points

Category: Quantitative Aptitude

A bag contains 25 paise, 50 paise, and Rs 2 coins in the ratio 12 : 15 : 20 respectively. If the total value of money in bag is Rs 505, what is the total number of coins in the bag?

Correct

Explanation:
Coins – 12x, 15x, 20x, so
Value of 25 paise coins = (25/100)*12x = 3x, of 50 paise coin = (50/100)*15x = 15x/2, of Rs 2 coins = 2*20x = 40x
So total value is 3x+(15x/2)+40x = 101x/2 which equals 505, so x = 10
Total coins = 12x+15x+20x = 47x = 470

Incorrect

Explanation:
Coins – 12x, 15x, 20x, so
Value of 25 paise coins = (25/100)*12x = 3x, of 50 paise coin = (50/100)*15x = 15x/2, of Rs 2 coins = 2*20x = 40x
So total value is 3x+(15x/2)+40x = 101x/2 which equals 505, so x = 10
Total coins = 12x+15x+20x = 47x = 470

Question 2 of 15

2. Question

1 points

Category: Quantitative Aptitude

The speed of stream is 4 km/hr. To travel 10 km upstream, 20 minutes are taken more than to travel 10 km downstream by a boat. What is the downstream speed?

Correct

Explanation:
Let speed of boat in still water = x km/hr
So speed upstream = x-4, and speed downstream = x+4
Now given:
Time to travel 10 km downstream + 20/60= time to travel 10 km upstream
So 10/(x+4) + 1/3 = 10/(x-4)
10/(x-4) – 10/(x+4) = 1/3
10x+40 – (10x-40)/(x^{2} – 16) = 1/3
80/(x^{2} – 16) = 1/3
x^{2} – 16 = 240
solve, x = 16
so downstream speed = 16+4

Incorrect

Explanation:
Let speed of boat in still water = x km/hr
So speed upstream = x-4, and speed downstream = x+4
Now given:
Time to travel 10 km downstream + 20/60= time to travel 10 km upstream
So 10/(x+4) + 1/3 = 10/(x-4)
10/(x-4) – 10/(x+4) = 1/3
10x+40 – (10x-40)/(x^{2} – 16) = 1/3
80/(x^{2} – 16) = 1/3
x^{2} – 16 = 240
solve, x = 16
so downstream speed = 16+4

Question 3 of 15

3. Question

1 points

Category: Quantitative Aptitude

From a vessel containing milk, 4 litres is drawn out and at the same time 6 litres of water poured. Now 6 l of the mixture formed is taken out. If the initial quantity of milk in the vessel is 34 litres, what is the remaining quantity of milk in the mixture?

Correct

Explanation:
4 l drawn, milk = 34-4 = 30 l, water added 6 l
So ratio of milk to water is 30 : 6 = 5 : 1
Now 6 l of mixture taken out, so remaining milk is = 30 – (5/6) * 6 = 25

Incorrect

Explanation:
4 l drawn, milk = 34-4 = 30 l, water added 6 l
So ratio of milk to water is 30 : 6 = 5 : 1
Now 6 l of mixture taken out, so remaining milk is = 30 – (5/6) * 6 = 25

Rs 5800 is to be invested in two schemes such that interest after 5 years and 4 years is same on respective parts. If scheme A offers 12% rate of interest and scheme B offers 14% rate of interest, what is the amount invested in scheme A?

Correct

Explanation:
Shortcut when interests are equal:
1/(5*12) : 1/((4*14)
14 : 15
So amount invested in scheme A = (14/29) * 5800 = 2800

Incorrect

Explanation:
Shortcut when interests are equal:
1/(5*12) : 1/((4*14)
14 : 15
So amount invested in scheme A = (14/29) * 5800 = 2800

Question 7 of 15

7. Question

1 points

Category: Quantitative Aptitude

How many kg of wheat costing Rs 10 per kg must be mixed with 16 Kg of wheat costing Rs 15 per Kg, so that there may be gain of 30% by selling the mixture of Rs 15.6 per Kg?

Correct

Explanation:
With 30% gain and SP = 15.6, CP = (100/130)*15.6 = 12
By method of allegation:
1st wheat (x kg)…………..2nd wheat (16 kg)
10……………………………..…….15
.,…………………..12
3………………………………………2
3 : 2
So x/16 = 3/2

Incorrect

Explanation:
With 30% gain and SP = 15.6, CP = (100/130)*15.6 = 12
By method of allegation:
1st wheat (x kg)…………..2nd wheat (16 kg)
10……………………………..…….15
.,…………………..12
3………………………………………2
3 : 2
So x/16 = 3/2

Question 8 of 15

8. Question

1 points

Category: Quantitative Aptitude

A trader bought an article at 10% discount. The same article is sold at 20% above the marked price. What will be the actual profit percent of trader in this transaction?

Correct

Explanation:
Let MP = 100, so CP for trader = Rs 90 (at 10% discount)
And he sold at 20% above MP, so SP for trader = 120
So profit% = (120-90)/90 * 100

Incorrect

Explanation:
Let MP = 100, so CP for trader = Rs 90 (at 10% discount)
And he sold at 20% above MP, so SP for trader = 120
So profit% = (120-90)/90 * 100

Question 9 of 15

9. Question

1 points

Category: Quantitative Aptitude

There are 4 boys and 5 girls from which 5 people are to be selected. Find the number of ways in which they can be selected so that a particular girl is always selected.

Correct

Explanation:
A particular girl is already selected from the 5 girls
This means now 4 girls left and 4 boys. From these 8 people, 4 are to be selected.
So ^{8}C_{4}

Incorrect

Explanation:
A particular girl is already selected from the 5 girls
This means now 4 girls left and 4 boys. From these 8 people, 4 are to be selected.
So ^{8}C_{4}

Question 10 of 15

10. Question

1 points

Category: Quantitative Aptitude

A and B can complete a work in 40 and 60 days respectively. They started a work which is to be completed in 20 days. But it was found that they will not be able to complete work on time, so a third person C was appointed after 12 days. In how many days C can alone complete the work?

Correct

Explanation:
A and B worked for 20 days. In 1 days they could have completed work (1/40 + 1/60) = 1/24
So in 20 days, they did (1/24)*20 = 5/6
This means C did 1 – 5/6 = 1/6 of work in 8 days
So he can do 1 work in 48 days

Incorrect

Explanation:
A and B worked for 20 days. In 1 days they could have completed work (1/40 + 1/60) = 1/24
So in 20 days, they did (1/24)*20 = 5/6
This means C did 1 – 5/6 = 1/6 of work in 8 days
So he can do 1 work in 48 days

Question 11 of 15

11. Question

1 points

Category: Quantitative Aptitude

A sum of rupees is divided between three people A, B and C in such a way that after 2 years, 3 years and 4 years respectively the amount they get is equal. If the rate of interest is 5 percent, what is the ratio in which the amount is divided?

Correct

Incorrect

Question 12 of 15

12. Question

1 points

Category: Quantitative Aptitude

A rectangular park has dimensions 100m × 40m. A circular lawn is in the middle of park. If the area of rectangular park leaving the circular lawn is 1536 m^{2}, what is the circumference of the circular lawn?

Correct

Explanation:
Area of park = 100*40 = 4000
So area of circular lawn = 4000-1536 = 2464
So ᴨr^{2} = 2464
Solve, r = 28
So circumference = 2ᴨr

Incorrect

Explanation:
Area of park = 100*40 = 4000
So area of circular lawn = 4000-1536 = 2464
So ᴨr^{2} = 2464
Solve, r = 28
So circumference = 2ᴨr

Question 13 of 15

13. Question

1 points

Category: Quantitative Aptitude

20 men can complete a work in 48 days. 12 men start the work and after working for 20 days, 4 more men join. After working for 30 days more, how many more men are needed to be joined so that the remaining work gets completed in 10 days?

Correct

Explanation:
Shortcut:
20*48 = 12*20 + 16*30 + (16+x)*10
Solve, x = 8
OR
20 men in 48 days, so 12 in (20*48)/12 = 80
They worked for 20 days, so did (1/80)*20 = 1/4 of work
Now 4 more men joined, so 16 men can do in (20*48)/16 = 60 days
They worked for 30 days, so they did (1/60)*30 = 1/2 of work
Now work done = (1/4) +(1/2) = 3/4, so remaining work = 1 – 3/4 = 1/4
This 1/4 work is to be completed in 10 days.
20 men do 1 work in 48 days, so let (16+x) men do 1/4 work in 10 days
So 20*48*(1/4) = (16+x)*10*1
Solve, x = 8

Incorrect

Explanation:
Shortcut:
20*48 = 12*20 + 16*30 + (16+x)*10
Solve, x = 8
OR
20 men in 48 days, so 12 in (20*48)/12 = 80
They worked for 20 days, so did (1/80)*20 = 1/4 of work
Now 4 more men joined, so 16 men can do in (20*48)/16 = 60 days
They worked for 30 days, so they did (1/60)*30 = 1/2 of work
Now work done = (1/4) +(1/2) = 3/4, so remaining work = 1 – 3/4 = 1/4
This 1/4 work is to be completed in 10 days.
20 men do 1 work in 48 days, so let (16+x) men do 1/4 work in 10 days
So 20*48*(1/4) = (16+x)*10*1
Solve, x = 8

Question 14 of 15

14. Question

1 points

Category: Quantitative Aptitude

A and B entered into a partnership with A invested Rs 5000 for 8 months and B invested Rs 5500 for 6 months. In the last 4 months, both invested Rs 7000 and Rs 8000 respectively. If after a year, a total of Rs 31,920 is gained as a profit, what is A’s share in the profit?

Correct

Explanation:
5000*8 + 7000*4 : 5500*6 + 8000*4
68 : 65
So A got = (68/133)*31920

Incorrect

Explanation:
5000*8 + 7000*4 : 5500*6 + 8000*4
68 : 65
So A got = (68/133)*31920

Question 15 of 15

15. Question

1 points

Category: Quantitative Aptitude

A starts from point P at 20 km/hr towards point Q. After 2 hours B starts from point Q at some speed towards A. They both meet when they reach half the distance between points P and Q. If A covered one-fourth of total distance in 2 hours, what is the speed of B?

Correct

Explanation:
A covered one-fourth of total distance in 2 hours, so 1/2 distance in 4 hours
Now B has covered that same distance that A covered in (4-2) = 2 hours [B started after 2 hrs]
And since distances are same
So distance by A = distance covered by B gives
20*4 = x*2
Solve, x = 40km/hr

Incorrect

Explanation:
A covered one-fourth of total distance in 2 hours, so 1/2 distance in 4 hours
Now B has covered that same distance that A covered in (4-2) = 2 hours [B started after 2 hrs]
And since distances are same
So distance by A = distance covered by B gives
20*4 = x*2
Solve, x = 40km/hr