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Question 1 of 15
1. Question
1 pointsCategory: Quantitative AptitudeDirections (1 – 5): Study the given table carefully and answer the questions that follow.
What are the total marks obtained by Veena in all the subjects?
Correct
Explanation:
100+80+50+90+90+60Incorrect
Explanation:
100+80+50+90+90+60 
Question 2 of 15
2. Question
1 pointsCategory: Quantitative AptitudeDirections (1 – 5): Study the given table carefully and answer the questions that follow.
What are the average marks obtained by these seven students in Math? (rounded off to two digits)
Correct
Explanation:
(80+70+70+60+90+60+80)/7Incorrect
Explanation:
(80+70+70+60+90+60+80)/7 
Question 3 of 15
3. Question
1 pointsCategory: Quantitative AptitudeDirections (1 – 5): Study the given table carefully and answer the questions that follow.
How many students have got 60% or more marks in all the subjects?
Correct
Explanation:
Akshay and SonuIncorrect
Explanation:
Akshay and Sonu 
Question 4 of 15
4. Question
1 pointsCategory: Quantitative AptitudeDirections (1 – 5): Study the given table carefully and answer the questions that follow.
What is the overall percentage of Akshay?
Correct
Explanation:
Total marks of Akshay = 90+70+60+90+70+70 = 450
So % = 450/600 * 100Incorrect
Explanation:
Total marks of Akshay = 90+70+60+90+70+70 = 450
So % = 450/600 * 100 
Question 5 of 15
5. Question
1 pointsCategory: Quantitative AptitudeDirections (1 – 5): Study the given table carefully and answer the questions that follow.
In which subject is the overall percentage the best?
Correct
Explanation:
Calculate totals for all the subjects and the one having highest.Incorrect
Explanation:
Calculate totals for all the subjects and the one having highest. 
Question 6 of 15
6. Question
1 pointsCategory: Quantitative AptitudeA shopkeeper sells an item at 30% profit but uses a weight of 750 gm instead of 1 kg. What is his net profit/loss %?
Correct
Explanation:
Uses 750 gm in place of 1 kg.
So profit in this = (1000750)/750 * 100 = 100/3%
Now profit of 30% and successive profit of 100/3%.
So overall profit/loss = 30 + 100/3 + (30)(100/3)/100 = 220/3%Incorrect
Explanation:
Uses 750 gm in place of 1 kg.
So profit in this = (1000750)/750 * 100 = 100/3%
Now profit of 30% and successive profit of 100/3%.
So overall profit/loss = 30 + 100/3 + (30)(100/3)/100 = 220/3% 
Question 7 of 15
7. Question
1 pointsCategory: Quantitative AptitudeA train starts from station A at 7:00 AM and reaches station B at 9:00 AM. Another train starts from station B at 7:30 AM and reaches station A at 10:30 AM. At what time the two trains will meet?
Correct
Explanation:
Let the distance from A to B is ‘d’ km.
First train reaches destination in 2 hrs, so speed of first train = d/2 km/hr.
Speed of second train = d/3 km/hr
Speed of first train = d/2 km/hr, so after 1/2 hr, i.e. at 7:30 AM, the first train has covered d/4 km.
The distance left = (d – d/4) km = 3d/4 km. relative speed = d/2 + d/3.
So time they will meet at = 7:30 AM + (3d/4) / (d/2 + d/3)
= 7:30 AM + (9/10)*60 = 8:24 AMIncorrect
Explanation:
Let the distance from A to B is ‘d’ km.
First train reaches destination in 2 hrs, so speed of first train = d/2 km/hr.
Speed of second train = d/3 km/hr
Speed of first train = d/2 km/hr, so after 1/2 hr, i.e. at 7:30 AM, the first train has covered d/4 km.
The distance left = (d – d/4) km = 3d/4 km. relative speed = d/2 + d/3.
So time they will meet at = 7:30 AM + (3d/4) / (d/2 + d/3)
= 7:30 AM + (9/10)*60 = 8:24 AM 
Question 8 of 15
8. Question
1 pointsCategory: Quantitative AptitudeMixture A contains milk and water in the ratio 4 : 1. Mixture B contains milk and water in the ratio 7 : 3. From both the mixtures, the mixtures are taken and mixed and the final mixture contain milk to water in the ratio 47 : 13. If a total of 60 litres mixture is obtained, then what was the quantity of mixture A taken?
Correct
Explanation:
Let x l form A is taken, and y litres from B, so x+y = 60
Now milk will be 4/(4+1) * x = 4x/5 and from B milk = 7/(7+3) * y = 7x/10. Total milk = 4x/5 + 7x/10
Similarly water from A will be 1/(4+1) * x = x/5 and from B milk = 3/(7+3) * y = 3x/10. Total water = x/5 + 3x/10
Their ratio is 47 : 13
So [4x/5 + 7x/10]/[ x/5 + 3x/10] = 47/13
Solve, x = 5y
Also x+y = 60
Solve both , x= 50Incorrect
Explanation:
Let x l form A is taken, and y litres from B, so x+y = 60
Now milk will be 4/(4+1) * x = 4x/5 and from B milk = 7/(7+3) * y = 7x/10. Total milk = 4x/5 + 7x/10
Similarly water from A will be 1/(4+1) * x = x/5 and from B milk = 3/(7+3) * y = 3x/10. Total water = x/5 + 3x/10
Their ratio is 47 : 13
So [4x/5 + 7x/10]/[ x/5 + 3x/10] = 47/13
Solve, x = 5y
Also x+y = 60
Solve both , x= 50 
Question 9 of 15
9. Question
1 pointsCategory: Quantitative AptitudeP and Q start at the same point on a circular track with speeds 18 km/hr and 27 km/hr respectively in opposite directions. If the circular track is 700 m long, then after how much time both mill meet again?
Correct
Explanation:
18 km/hr = 18 * (5/18) = 5 m/s
27 km/hr = 27 * (5/18) = 15/2 m/s
In opposite direction, relative speed is 5 + 15/2 = 25/2 m/s
Time = 700/ (25/2) = 56 secIncorrect
Explanation:
18 km/hr = 18 * (5/18) = 5 m/s
27 km/hr = 27 * (5/18) = 15/2 m/s
In opposite direction, relative speed is 5 + 15/2 = 25/2 m/s
Time = 700/ (25/2) = 56 sec 
Question 10 of 15
10. Question
1 pointsCategory: Quantitative AptitudeA profit of 12% is made when a discount of 20% is given. If the discount given is 25%, then what will be the profit/loss %?
Correct
Explanation:
We have a direct formula for this:
Profit/Loss % = { (100+12) [(10025)/(10020)] } – 100
= +5%
So profit 5%Incorrect
Explanation:
We have a direct formula for this:
Profit/Loss % = { (100+12) [(10025)/(10020)] } – 100
= +5%
So profit 5% 
Question 11 of 15
11. Question
1 pointsCategory: Quantitative AptitudeAn article is marked 25% above the cost price with marked price being Rs 150. The profit gets increased by Rs 6.9, when the selling price of this article is increased by 5%. What is the original selling price of the article?
Correct
Explanation:
MP = 150, Also given MP = (125/100)*CP, so CP = Rs 120
Now SP – 120 = Profit(P)
Now given that, when SP increased by 5%, CP is same and profit increased by 6.9 i.e. becomes P+6.9, so
(105/100)*SP – 120 = P + 6.9
Put P = SP – 120 in it
(105/100)*SP – 120 = SP – 120 + 6.9
Solve, SP = 138Incorrect
Explanation:
MP = 150, Also given MP = (125/100)*CP, so CP = Rs 120
Now SP – 120 = Profit(P)
Now given that, when SP increased by 5%, CP is same and profit increased by 6.9 i.e. becomes P+6.9, so
(105/100)*SP – 120 = P + 6.9
Put P = SP – 120 in it
(105/100)*SP – 120 = SP – 120 + 6.9
Solve, SP = 138 
Question 12 of 15
12. Question
1 pointsCategory: Quantitative AptitudeIn how many ways all the letters of the word ‘SEQUENCE’ can be arranged?
Correct
Explanation:
Sequence is 8 letters so 8!
And E is 3 times so, 8!/3!Incorrect
Explanation:
Sequence is 8 letters so 8!
And E is 3 times so, 8!/3! 
Question 13 of 15
13. Question
1 pointsCategory: Quantitative AptitudeThree friends A, B and C divide Rs 4600 among them such that A and B get the money in the ratio 3 : 2 and B and C get in the ratio 3 : 4 respectively. If to all their shares, Rs 200 is added, what will be the new ratio of dividing the total money among them?
Correct
Explanation:
A/B = 3/2 and B/C = 3/4
So A : B : C = 3*3 : 2*3 : 2*4 = 9 : 6 : 8
A got = [9/(9+6+8)] * 4600 = 1800, B got = [6/(9+6+8)] * 4600 = 1200, C got = [8/(9+6+8)] * 4600 = 1600
When 200 is added to their shares, A gets=1800+200 = 2000, B = 1400, C =1800
So new ratio is 2000 : 1400 : 1800Incorrect
Explanation:
A/B = 3/2 and B/C = 3/4
So A : B : C = 3*3 : 2*3 : 2*4 = 9 : 6 : 8
A got = [9/(9+6+8)] * 4600 = 1800, B got = [6/(9+6+8)] * 4600 = 1200, C got = [8/(9+6+8)] * 4600 = 1600
When 200 is added to their shares, A gets=1800+200 = 2000, B = 1400, C =1800
So new ratio is 2000 : 1400 : 1800 
Question 14 of 15
14. Question
1 pointsCategory: Quantitative AptitudeA, B and C can alone complete a work in 15, 30 and 40 days respectively. They all started the work. A and B left the work after 5 days and C completed the remaining work. How many extra days will be taken to complete the work now?
Correct
Explanation:
If all worked for all the days, then (1/15 + 1/30 + 1/40) = 1/8
So they would have completed in 8 days.
But they worked for 5 days, so work completed is (1/8)*5
Work left = 1 – 5/8 = 3/8 which is to be completed by C
C completes 1 work in 40 days, so 3/8 work in (3/8)*40 = 15 days
So total work completed in 5+15 = 20 days
Extra days taken = 208 = 12Incorrect
Explanation:
If all worked for all the days, then (1/15 + 1/30 + 1/40) = 1/8
So they would have completed in 8 days.
But they worked for 5 days, so work completed is (1/8)*5
Work left = 1 – 5/8 = 3/8 which is to be completed by C
C completes 1 work in 40 days, so 3/8 work in (3/8)*40 = 15 days
So total work completed in 5+15 = 20 days
Extra days taken = 208 = 12 
Question 15 of 15
15. Question
1 pointsCategory: Quantitative AptitudeIn an application form, a candidate mistakenly filled his age 25% more than his actual age. If his actual age is 40, by how much percent the candidate have to reduce his age in order to get the correct age?
Correct
Explanation:
He filled his age to be (125/100)*40 = 50
Let he must reduce by x%, then
[(100x)/100] * 50 = 40
Solve, x = 20%Incorrect
Explanation:
He filled his age to be (125/100)*40 = 50
Let he must reduce by x%, then
[(100x)/100] * 50 = 40
Solve, x = 20%
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