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Quantitative Aptitude0%
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Question 1 of 15
1. Question
1 points
Category: Quantitative Aptitude
Directions (1 – 5): Study the following table and answer the questions that follow:
The table shows the number of employees in 5 departments of a company.
Departments
Total employees
Males to females ratio
Graduates to post graduates ratio
A
450
8
7
4
5
B
270
5
4
7
2
C
360
3
1
5
7
D
220
6
5
1
1
E
400
3
7
5
3
What is the total number of post graduates in departments B and C?
Correct
Explanation:
Post grads in B + post grads in C = (2/9)*270 + (7/12)*360 = 60 + 210
Incorrect
Explanation:
Post grads in B + post grads in C = (2/9)*270 + (7/12)*360 = 60 + 210
Question 2 of 15
2. Question
1 points
Category: Quantitative Aptitude
Directions (1 – 5): Study the following table and answer the questions that follow:
The table shows the number of employees in 5 departments of a company.
Departments
Total employees
Males to females ratio
Graduates to post graduates ratio
A
450
8
7
4
5
B
270
5
4
7
2
C
360
3
1
5
7
D
220
6
5
1
1
E
400
3
7
5
3
Total graduates in department C is what percent of total post graduates in department A?
Correct
Explanation:
Grads in C = (5/12)*360 = 150, post grads in A = (5/9)*450 = 250
So required % = (150/250)*100
Incorrect
Explanation:
Grads in C = (5/12)*360 = 150, post grads in A = (5/9)*450 = 250
So required % = (150/250)*100
Question 3 of 15
3. Question
1 points
Category: Quantitative Aptitude
Directions (1 – 5): Study the following table and answer the questions that follow:
The table shows the number of employees in 5 departments of a company.
Departments
Total employees
Males to females ratio
Graduates to post graduates ratio
A
450
8
7
4
5
B
270
5
4
7
2
C
360
3
1
5
7
D
220
6
5
1
1
E
400
3
7
5
3
What is the ratio of total number of males in departments B and C to that of the total number of females in departments A and D?
Correct
Explanation:
Males in B + males in C = (5/9)*270 + (3/4)*360 = 150 + 270 = 420
Females in A + females in D = (7/15)*450 + (5/11)*220 = 210 + 100 = 310
42 : 31
Incorrect
Explanation:
Males in B + males in C = (5/9)*270 + (3/4)*360 = 150 + 270 = 420
Females in A + females in D = (7/15)*450 + (5/11)*220 = 210 + 100 = 310
42 : 31
Question 4 of 15
4. Question
1 points
Category: Quantitative Aptitude
Directions (1 – 5): Study the following table and answer the questions that follow:
The table shows the number of employees in 5 departments of a company.
Departments
Total employees
Males to females ratio
Graduates to post graduates ratio
A
450
8
7
4
5
B
270
5
4
7
2
C
360
3
1
5
7
D
220
6
5
1
1
E
400
3
7
5
3
How many post graduate females are there in department E?
Correct
Explanation:
in E, females are (7/10)*400 = 280, males are 400-280 = 120
total postgrads = (3/8)*400 = 150, but we are not given grads to postgrads ratio in females.
Incorrect
Explanation:
in E, females are (7/10)*400 = 280, males are 400-280 = 120
total postgrads = (3/8)*400 = 150, but we are not given grads to postgrads ratio in females.
Question 5 of 15
5. Question
1 points
Category: Quantitative Aptitude
Directions (1 – 5): Study the following table and answer the questions that follow:
The table shows the number of employees in 5 departments of a company.
Departments
Total employees
Males to females ratio
Graduates to post graduates ratio
A
450
8
7
4
5
B
270
5
4
7
2
C
360
3
1
5
7
D
220
6
5
1
1
E
400
3
7
5
3
What is the number of total graduates in the company?
A gives 45% of his salary to B. From this amount, B spends 25% on his food items and 5% on repair of furniture and the remaining Rs 16,380 puts in the saving account. What is the salary of A?
Correct
Explanation:
Salary of A = x
B gets = (45/100)*x
He spends 25% + 5% = 30%, i.e. left with 70% of (45/100)*x
So (70/100) *(45/100) * x = 16380
Solve, x = 52000
Incorrect
Explanation:
Salary of A = x
B gets = (45/100)*x
He spends 25% + 5% = 30%, i.e. left with 70% of (45/100)*x
So (70/100) *(45/100) * x = 16380
Solve, x = 52000
Question 7 of 15
7. Question
1 points
Category: Quantitative Aptitude
5 men started the work and worked for 4 days. Now they are replaced by 12 women where 1 man can do as much work as 2 women do in 1 day. If the works gets completed in a total of 10 days, in how many days 7 women can complete the entire work?
Correct
Explanation:
Given 1 m = 2w, so 12 women = 6 men
Let 1 man do work in x days, so 1 man’s 1 day work = 1/x, so 5 men 1 day’s work = (1/x)*5
And since they did work for 4 days, so there work becomes (5/x)* 4 = 20/x
Now total work completed in 10 days, this mean that 12 women or 6 men did in (10-4) = 6 days
So similarly as above, 1 man’s 1 day work = 1/x, so 6 men 1 day’s work = (1/x)*6
And since they did work for 6 days, so there work becomes (6/x)* 6 = 36/x
So (20/x) + (36/x) = 1
Solve, x = 56
1 man do work in 56 days, so 1 woman in 2*56 days, and 7 women in (2*56)/7
Incorrect
Explanation:
Given 1 m = 2w, so 12 women = 6 men
Let 1 man do work in x days, so 1 man’s 1 day work = 1/x, so 5 men 1 day’s work = (1/x)*5
And since they did work for 4 days, so there work becomes (5/x)* 4 = 20/x
Now total work completed in 10 days, this mean that 12 women or 6 men did in (10-4) = 6 days
So similarly as above, 1 man’s 1 day work = 1/x, so 6 men 1 day’s work = (1/x)*6
And since they did work for 6 days, so there work becomes (6/x)* 6 = 36/x
So (20/x) + (36/x) = 1
Solve, x = 56
1 man do work in 56 days, so 1 woman in 2*56 days, and 7 women in (2*56)/7
Question 8 of 15
8. Question
1 points
Category: Quantitative Aptitude
The length and breadth of a rectangle are in the ratio 4 : 5. Both of them are increased by 5 m each and the area of rectangle so formed is 340 m2. Find the perimeter of the original rectangle.
Mixture A contains 60% milk and mixture B contains 80% milk. A milkman takes some mixture from mixture A and mixes it with thrice the amount of mixture from mixture B. What is the percentage of milk in the new mixture?
Correct
Explanation:
Let x from A, 3x form B
So milk from A = (60/100)*x, milk from B = (80/100)*3x
So milk in new mixture is (60x/100) + (240x/100) = 3x
Total mixture in third is x+3x = 4x
So % of milk is (3x/4x)*100
Incorrect
Explanation:
Let x from A, 3x form B
So milk from A = (60/100)*x, milk from B = (80/100)*3x
So milk in new mixture is (60x/100) + (240x/100) = 3x
Total mixture in third is x+3x = 4x
So % of milk is (3x/4x)*100
Question 10 of 15
10. Question
1 points
Category: Quantitative Aptitude
The speed of boat is 10 km/hr and speed of stream is 4 km/hr. A person goes 84 km downstream from point A to B and same distance upstream from point B to C. In how much total time will he cover his journey?
