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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

Q (1-5)There are three sections in a library for students – Management, Technical and Medical. 18% and 8% of students visit only Technical and Medical section respectively. Total 60% of students visit the Management section. 168 students visit the Technical and Management section but not the Medical section. These are thrice the number of students who visit the Technical and Medical section but not the Management section.

Find the total number of students who visited only technical section.

Overall Explanation:
168 students visit Technical and Management section but not Medical section.
Therefore, the number of students who visit technical and medical section but not management section = 168/3 = 56
The total number of students in Management section = 60%
Therefore, the number of students who are in only technical, only medical and in technical and medical but not management will be 40%

Only medical + Only technical + technical and medical but not management = 40%
8% + 18% + 56 = 40%
14% = 56
1% = 4
100% = 400
Therefore, total number of students who visited library = 400

Overall Explanation:
168 students visit Technical and Management section but not Medical section.
Therefore, the number of students who visit technical and medical section but not management section = 168/3 = 56
The total number of students in Management section = 60%
Therefore, the number of students who are in only technical, only medical and in technical and medical but not management will be 40%

Only medical + Only technical + technical and medical but not management = 40%
8% + 18% + 56 = 40%
14% = 56
1% = 4
100% = 400
Therefore, total number of students who visited library = 400

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

Q (1-5)There are three sections in a library for students – Management, Technical and Medical. 18% and 8% of students visit only Technical and Medical section respectively. Total 60% of students visit the Management section. 168 students visit the Technical and Management section but not the Medical section. These are thrice the number of students who visit the Technical and Medical section but not the Management section.

Find the total number of students who visited the library?

Correct

Answer: 1) 400
Explanation:
1% = 4
100% = 400

Incorrect

Answer: 1) 400
Explanation:
1% = 4
100% = 400

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

Q (1-5)There are three sections in a library for students – Management, Technical and Medical. 18% and 8% of students visit only Technical and Medical section respectively. Total 60% of students visit the Management section. 168 students visit the Technical and Management section but not the Medical section. These are thrice the number of students who visit the Technical and Medical section but not the Management section.

What can be the maximum number of students who visited only management section?

Correct

Answer: 5) 72
Explanation:
When none of the students visited all three sections and also no student visited management and medical section but not technical section.
60% – 168
4*60 – 168
240 – 168
72

Incorrect

Answer: 5) 72
Explanation:
When none of the students visited all three sections and also no student visited management and medical section but not technical section.
60% – 168
4*60 – 168
240 – 168
72

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

Q (1-5)There are three sections in a library for students – Management, Technical and Medical. 18% and 8% of students visit only Technical and Medical section respectively. Total 60% of students visit the Management section. 168 students visit the Technical and Management section but not the Medical section. These are thrice the number of students who visit the Technical and Medical section but not the Management section.

Q (1-5)There are three sections in a library for students – Management, Technical and Medical. 18% and 8% of students visit only Technical and Medical section respectively. Total 60% of students visit the Management section. 168 students visit the Technical and Management section but not the Medical section. These are thrice the number of students who visit the Technical and Medical section but not the Management section.

The number of students who visited both medical and technical section but not the management section is what percent of the number of students who visited only the medical section?

Correct

Answer: 3) 175%
Explanation:
The number of students who visited both medical and technical section but not management section = 168/3 = 56
The number of students who visited only medical section = 8% = 4*8 = 32
Required percentage = (56/32)*100 = (7/4)*100 = 175%

Incorrect

Answer: 3) 175%
Explanation:
The number of students who visited both medical and technical section but not management section = 168/3 = 56
The number of students who visited only medical section = 8% = 4*8 = 32
Required percentage = (56/32)*100 = (7/4)*100 = 175%

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

The average age of A, B, and C is 28 years and after 5 years, the average age of A and C will be 35 years. Then what will be the age of B 4 years from now?

Correct

Answer: 5) 28 years
Explanation:
Given, average age of A, B and C is 28 years
Sum of ages of A, B and C will be 2*28 = 84 years
Since after 5 years the average age of A and C = 35 years
Present average age of A and C = 35-5 = 30 years
Sum of age of A and C = 2*30 = 60 years
Present age of B = 84-60 = 24 years
Age of B after 4 years = 24+4 = 28

Incorrect

Answer: 5) 28 years
Explanation:
Given, average age of A, B and C is 28 years
Sum of ages of A, B and C will be 2*28 = 84 years
Since after 5 years the average age of A and C = 35 years
Present average age of A and C = 35-5 = 30 years
Sum of age of A and C = 2*30 = 60 years
Present age of B = 84-60 = 24 years
Age of B after 4 years = 24+4 = 28

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

The ratio of the speed of the boat in still water and speed of the stream is 9:1. If the upstream distance of 187.5km is covered in 3.75 hours. Then find downstream speed.

Correct

Answer: 1) 62.5km/hr
Explanation:
Let the speed of boat in still water = 9x and speed of stream = x
Upstream speed = 9x-x = 8x
Downstream speed = 9x+x = 10x
ATQ,
(187.5)/8x = 3.75
(187.5)/3.75 = 8x
50 = 8x
x = 6.25
Downstream speed = 10x = 10*6.25 = 62.5km/hr

Incorrect

Answer: 1) 62.5km/hr
Explanation:
Let the speed of boat in still water = 9x and speed of stream = x
Upstream speed = 9x-x = 8x
Downstream speed = 9x+x = 10x
ATQ,
(187.5)/8x = 3.75
(187.5)/3.75 = 8x
50 = 8x
x = 6.25
Downstream speed = 10x = 10*6.25 = 62.5km/hr

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

The difference between the marked price and selling price of a certain product is Rs. 50. The profit obtained from the sale of that item is Rs. 30. If a discount of 10% was given, calculate the cost price of that item.

Correct

Answer: 5) Rs. 420
Explanation:
Let the marked price of the product = 100x
Selling price after a discount of 10% = (90/100)*100x = 90x
ATQ,
100x-90x = 50
10x = 50
x = 5
Selling price = 90x = 90*5 = 450
Since, the profit obtained = 30
Cost price = selling price – profit = 450 – 30 = 420
Cost price = 450 – 30 = 420

Incorrect

Answer: 5) Rs. 420
Explanation:
Let the marked price of the product = 100x
Selling price after a discount of 10% = (90/100)*100x = 90x
ATQ,
100x-90x = 50
10x = 50
x = 5
Selling price = 90x = 90*5 = 450
Since, the profit obtained = 30
Cost price = selling price – profit = 450 – 30 = 420
Cost price = 450 – 30 = 420

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

The perimeter of 2 equilateral triangles is 72 and 48 meter respectively. Find the perimeter of the third equilateral triangle, whose area is equal to the difference between the areas of the first 2 equilateral triangles?

Correct

Incorrect

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

The price of 5 bats and 25 balls is Rs. 2500. If the price of 5 balls is equal to 1/9th of the price of 1 bat, then find the price of 1 bat and 1 ball?

Correct

Answer: 4) Rs. 460
Explanation:
Given,
The price of 5 balls = (1/9)* Price of 1 bat
Price of 1 bat = Price of 45 balls
Price of 5 bats = price of 5*45 (225)balls
The price of 5 bats and 25 balls = Rs. 2500
The price of (225 + 25) balls = Rs. 2500
The price of 250 balls = 2500
Price of one ball = 10
Price of 1 bat = 10*45 = 450
Therefore, the price of 1 bat and 1 ball = 450+10 = 460

Incorrect

Answer: 4) Rs. 460
Explanation:
Given,
The price of 5 balls = (1/9)* Price of 1 bat
Price of 1 bat = Price of 45 balls
Price of 5 bats = price of 5*45 (225)balls
The price of 5 bats and 25 balls = Rs. 2500
The price of (225 + 25) balls = Rs. 2500
The price of 250 balls = 2500
Price of one ball = 10
Price of 1 bat = 10*45 = 450
Therefore, the price of 1 bat and 1 ball = 450+10 = 460

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