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Quantitative Aptitude0%

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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

The speed of boat is 9 km/hr and speed of stream is 5 km/hr. A person goes 112 km downstream from point A to B and same distance upstream from point B to C. In how much total time will he cover his journey?

The sum of money invested at compound interest amounts to Rs 6840 in 2 years and to Rs 8208 in 3 years. What was the amount of sum invested?

Correct

Explanation:
SI on 6840 for 1 yr = 8208 – 6840 = 1368
So rate = (100*1368/6840*1) = 20
So P (1 + 20/100)^{2} = 6840
Solve, P = 4750

Incorrect

Explanation:
SI on 6840 for 1 yr = 8208 – 6840 = 1368
So rate = (100*1368/6840*1) = 20
So P (1 + 20/100)^{2} = 6840
Solve, P = 4750

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

The rectangle whose sides are 8 cm and 6cm has perimeter equal to half of the perimeter of a square. If the diameter of a circle is equal to the side of the square, find the circumference of the semicircle?

Correct

Explanation:
Perimeter of square = 2 * peri. of rect = 2 * 2(8+6) = 56
So side of square = 56/4 = 14
So diameter of circle = 14, radius = 14/2 = 7
So circumference of circle = ᴨr + d = (22/7)*7 + 14

Incorrect

Explanation:
Perimeter of square = 2 * peri. of rect = 2 * 2(8+6) = 56
So side of square = 56/4 = 14
So diameter of circle = 14, radius = 14/2 = 7
So circumference of circle = ᴨr + d = (22/7)*7 + 14

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

The train goes from station A to B and back to station A in 17 hours where total distance covered by train is 1800 km. The train halted for two hours after reaching station B. If the average speed of train from A to B is 20% more than that from B to A, what is the speed of train from A to B station?

Correct

Explanation:
Let speed in return journey is x, then in A to B is (120/100)*x = 6x/5
So 900/x + 900/(6x/5) = 15
Solve, x = 110
So from A to B is 6*110/5

Incorrect

Explanation:
Let speed in return journey is x, then in A to B is (120/100)*x = 6x/5
So 900/x + 900/(6x/5) = 15
Solve, x = 110
So from A to B is 6*110/5

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

The number of students in school A is 5,500 and that in school B is 8,000. The ratio of boys in schools A and B is 2 : 3 respectively. If the number of girls in school B is 2000, find the number of girls in school A.

Correct

Explanation:
Boys in school B = 8000-2000 = 6000
So x/6000 = 2/3
Solve, x = 4000
So girls in school A = 5500-4000 = 1500

Incorrect

Explanation:
Boys in school B = 8000-2000 = 6000
So x/6000 = 2/3
Solve, x = 4000
So girls in school A = 5500-4000 = 1500

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

4x^{2} + 13x + 3 = 0, 5y^{2} – 11y + 2 = 0

Correct

Explanation:
4x^{2} + 13x + 3 = 0
4x^{2} + 12x + x + 3 = 0
Gives x = -3, -1/4
5y^{2} – 11y + 2 = 0
5y^{2} – 10y – y + 2 = 0
Gives y = 1/5, 2
Put on number line
-3… -1/4……. 1/5…… 2

Incorrect

Explanation:
4x^{2} + 13x + 3 = 0
4x^{2} + 12x + x + 3 = 0
Gives x = -3, -1/4
5y^{2} – 11y + 2 = 0
5y^{2} – 10y – y + 2 = 0
Gives y = 1/5, 2
Put on number line
-3… -1/4……. 1/5…… 2

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

20x^{2} – 3x – 2 = 0, 5y^{2} – 21y + 4 = 0

Correct

Explanation:
20x^{2} – 3x – 2 = 0
20x^{2} + 5x – 8x – 2 = 0
Gives x = -1/4, 2/5
5y^{2} – 21y + 4 = 0
5y^{2} – 20y – y + 4 = 0
Gives y = 1/5, 4
Put on number line
-1/4… 1/5……. 2/5…… 4

Incorrect

Explanation:
20x^{2} – 3x – 2 = 0
20x^{2} + 5x – 8x – 2 = 0
Gives x = -1/4, 2/5
5y^{2} – 21y + 4 = 0
5y^{2} – 20y – y + 4 = 0
Gives y = 1/5, 4
Put on number line
-1/4… 1/5……. 2/5…… 4

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

12x^{2} + 23x + 10 = 0, 4y^{2} – 7y – 15 = 0

Correct

Explanation:
12x^{2} + 23x + 10 = 0
12x^{2} + 8x + 15x + 10 = 0
Gives x = -5/4, -2/3
4y^{2} – 7y – 15 = 0
4y^{2} – 12y + 5y – 15 = 0
Gives y = -5/4, 3
Put on number line
-5/4… -2/3…… 3

Incorrect

Explanation:
12x^{2} + 23x + 10 = 0
12x^{2} + 8x + 15x + 10 = 0
Gives x = -5/4, -2/3
4y^{2} – 7y – 15 = 0
4y^{2} – 12y + 5y – 15 = 0
Gives y = -5/4, 3
Put on number line
-5/4… -2/3…… 3

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

3x^{2} + 4x – 4 = 0, 3y^{2} – 11y + 6 = 0

Correct

Explanation:
3x^{2} + 4x – 4 = 0
3x^{2} + 6x – 2x – 4 = 0
Gives x = -2, 2/3
3y^{2} – 11y + 6 = 0
3y^{2} – 9y – 2y + 6 = 0
Gives y = 3, 2/3
Put on number line
-2… 2/3…… 3

Incorrect

Explanation:
3x^{2} + 4x – 4 = 0
3x^{2} + 6x – 2x – 4 = 0
Gives x = -2, 2/3
3y^{2} – 11y + 6 = 0
3y^{2} – 9y – 2y + 6 = 0
Gives y = 3, 2/3
Put on number line
-2… 2/3…… 3

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

30x^{2} + 17x + 2 = 0, 3y^{2} + 8y + 4 = 0

Correct

Explanation:
30x^{2} + 17x + 2 = 0
30x^{2} + 5x + 12x + 2 = 0
Gives x = -1/6, -2/5
3y^{2} + 8y + 4 = 0
3y^{2} + 6y + 2y + 4 = 0
Gives y = -2, -2/3
Put on number line
-2…………. -2/3………. -2/5……… -1/6

Incorrect

Explanation:
30x^{2} + 17x + 2 = 0
30x^{2} + 5x + 12x + 2 = 0
Gives x = -1/6, -2/5
3y^{2} + 8y + 4 = 0
3y^{2} + 6y + 2y + 4 = 0
Gives y = -2, -2/3
Put on number line
-2…………. -2/3………. -2/5……… -1/6