Hello Aspirants. Here we are posting some of the questions of Quant section from Mock Test-2 along with solutions.

**5, 13, 41, 85, 257, ?**

A) 736

B) 516

C) 773

D) 716

E) 517E) 517

Explanation:

5*2 + 3, 13*3 + 2, 41*2 + 3, 85*3 + 2, ….**440, 360, 288, 224, ?**

A) 170

B) 169

C) 168

D) 171

E) 159C) 168

Explanation:

21^2 – 1, 19^2 – 1, 17^2 – 1, 15^2 – 1,….

Consecutive odd numbers**2, 10, 30, 68, 130, ?**

A) 222

B) 210

C) 209

D) 216

E) 228A) 222

Explanation:

1^3 + 1, 2^3 + 2, 3^3 + 3, 4^3 + 4, 5^3 + 5,….**A boy walking at a speed of 10 km/hr reaches his school 15 minutes late. Next time he increases his speed by 2 km/hr, but then also he is late by 5 minutes. Find the distance between school and his home.**

A) 8 km

B) 9 km

C) 10 km

D) 12 km

E) 13 kmC) 10 km

Explanation:

Speed 1= 10, speed 2 = 10+2 = 12

Difference in time = 15 – 5 = 10 minutes = 1/6 hours

Required distance = 12*10/(12-10) * 1/6**A committee of 4 is to be formed from among 4 girls and 5 boys. What is the probability that the committee will have number of boys less than number of girls?**

A) 1/12

B) 1/6

C) 1/10

D) 2/13

E) 1/13B) 1/6

Explanation:

Case 1: 4 girls and 0 boys

4C4/9C4

Case 2: 3 girls and 1 boy

4C3*5C1/9C4

Total probability = 4C4/9C4 + 4C3*5C1/9C4**There are 35 students in a hostel. If the number of student increases by 7, the expenses of the mess increase by Rs 42 per day while average expenditure per head diminishes by Re 1. Find the original expenditure of the mess.**

A) Rs 380

B) Rs 415

C) Rs 420

D) Rs 450

E) Rs 455C) Rs 420

Explanation:

Let total expenditure with 35 students = x, so their average = x/35

When 7 students increase, total 42 students, average decreases by 1 i.e. becomes x/35 – 1 and expenditure increases by 42 i.e. becomes (x+42), so average for 42 students now

(x+42)/42 = x/35 – 1

Solve for x**How many bullets can be made out of a cylinder, 28 cm high and 6 cm radius, each bullet being 1.5 cm in diameter?**

A) 1582

B) 1600

C) 1678

D) 1790

E) None of theseE) None of these

Explanation:

Volume of cylinder = πr^{2}h = 22/7 * 6^{2}* 28

Volume of 1 bullet = 4/3*πr^{3}= 4/3 * 22/7 * 1.5^{3}

Number of bullets = Volume of cylinder / Volume of 1 bullet**A man can row 7 km/hr in still water. When the river is running at 3 km/hr, it takes him 7 hr to row to a place and come back. How far is the place?**

A) 26 km

B) 20 km

C) 17 km

D) 22 km

E) 28 kmB) 20 km

Explanation:

Time is total time to go upstream and downstream

B is speed of boat in still water, R is speed of river/stream

Distance = time * [B^2 – R^2] / 2*B

=1 * [7^2 – 3^2] / 2*6**Two pipes can fill a cistern in 14 hours and 16 hours respectively. The pipes are opened simultaneously and it is found that due to leakage in the bottom, it took 32 minutes more to fill the cistern. When the cistern is full, in what time will the leak empty it?**

A) 118 hrs

B) 110 hrs

C) 115 hrs

D) 112 hrs

E) 120 hrsD) 112 hrs

Explanation:

Part filled in 1 hr without leakage = 1/14 + 1/16 = 15/112, so time taken to fill = 112/15 hrs

Due to leakage it took 32 minutes = 32/60 = 8/15 hrs more

So now time taken with leakage is 112/15 + 8/15 = 8 hrs

Let x hrs taken by leak to empty the whole cistern

So 15/112– 1/x = 1/8

Solve for x**In an alloy weighing 5 kg, 1/3rd is brass and the rest is copper. It is mixed with an alloy weighing 2 kg in which 1/4th is brass and the rest is copper. What is the ratio of brass to copper in the final mixture?**

A) 19 : 13

B) 13 : 29

C) 20 : 21

D) 19 : 15

E) 13 : 17B) 13 : 29

Explanation:

Copper in first alloy = 1 – 1/3 = 2/3

Copper in second alloy = 1 – 1/4 = 3/4

New ratio = (1/3 * 5 + 1/4 * 2) : (2/3 * 5 + 3/4 * 2)

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