Hello Aspirants. Here we are posting some of the questions of Quant section from Mock Test-1 along with solutions.

**0, 6, 24, 60, 120, ?**

A) 210

B) 240

C) 320

D) 340

E) 350

A) 210

Explanation:

1^3 – 1, 2^3 – 2, 3^ – 3, …., 6^3 – 6

**10, 8, 13, 35, 135, 669, ?**

A) 1500

B) 1890

C) 3678

D) 4007

E) 4070

D) 4007

Explanation:

10*1 – 2, 8*2 – 3, 13*3 – 4, 35*4 – 5,…., 669*6 – 7

**6, 18, 21, 63, 66, 198, ?**

A) 201

B) 205

C) 209

D) 222

E) 228

A) 201

Explanation:

x 3, + 3, x 3, + 3, x 3, + 3, ….

**5, 8, 14, 26, 50, 98, ?**

A) 194

B) 196

C) 202

D) 302

E) 396

A) 194

Explanation:

*2 – 2, *2 – 2, *2 – 2, *2 – 2, ….

**Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:**

A) 3 : 2

B) 2 : 3

C) 1 : 4

D) 4 : 1

E) 3 : 4

A) 3 : 2

Explanation:

s1-speed of first train, l1- length of first train

s1 = l1/27

s2 = l2/17

s1+s2 = (l1+l2)/23, put value of l1 and l2 from above and find s1 : s2**A can do a piece of work in the same time in which B and C can together do it. If A and B can together do it in 10 days and C alone in 50 days, then B alone could do it in:**

A) 20 days

B) 22 days

C) 25 days

D) 28 days

E) None of these

C) 25 days

Explanation:

(A+B+C)’s 1 day’s work: 1/A + 1/B + 1/C = 1/10 + 1/50 = 3/25

Given 1/A = 1/B +1/C

So, 1/A +1/A = 3/25 gives 1/A = 3/50

1/A + 1/B = 1/10, so 1/B = 1/10 – 3/50 = 1/25

So B can do in 25 days

**Mr Shamin’s salary increases every year by 10% in June. If there is no other increase or reduction in the salary and his salary in June 2011 was Rs 22,385, what was his salary in June 2009?**

A) Rs 18,650

B) Rs 18,000

C) Rs 19,250

D) Rs 18,500

E) None of these

D) Rs 18,500

Explanation:

Let salary in June 2009 = x

There is increase of 10% each year.

So, x * 110/100 * 110/100 = 22385

**Inside a square plot, a circular garden is developed which exactly fits in the square plot and the diameter of the garden is equal to the side of the square plot which is 28 metres. What is the area of the space left out in the square plot after developing the garden?**

A) 98 m2

B) 146 m2

C) 84 m2

D) 168 m2

E) None of these

D) 168 m2

Explanation:

Side of square = 28

Diameter of circular garden = 28, so radius = 14

Area of space left out = area of square – area of circle

= 28*28 – 22/7 * 14 *14

**A man can row 6 km/hr in still water. When the river is running at 1.2 km/hr, it takes him 1 hr to row to a place and come back. How far is the place?**

A) 2.67 km

B) 1.20 km

C) 1. 78 km

D) 2. 22 km

E) 2.88 km

E) 2.88 km

Explanation:

B is the speed of boat in still water

R is speed of river/stream

time is the total time to go upstream and downstream

Distance = time * [B^2 – R^2] / 2*B

=1 * [6^2 – 1.2^2] / 2*6

**A jar contains a mixture of two liquids A and B in the ratio 3 : 2. When 10 litres of this mixture is taken out and 10 litres of liquid A is poured into the jar, the ratio becomes 11 : 4. How many litres of liquid A was contained in the jar?**

A) 18 litres

B) 15 litres

C) 12 litres

D) 10 litres

E) 18.3 litres

A) 18 litres

Explanation:

A is 3x litres and B is 2x litres

10 litres taken out

A left in mixture = 3x – 3/5 * 10 = (3x – 6) litres

B left in mixture = 2x – 2/5 * 10 = (2x – 4) litres

Now 10 litres poured, A becomes (3x – 6) +10 = (3x + 4) litres

New ratio is 11 : 4

So, 3x+4 / 2x-4 = 11/4, solve: x = 6

So A contained in jar = 3x = 3*6 = 18 litres

**The sum of three consecutive odd numbers and three consecutive even numbers together is 231. Also, the smallest odd number is 11 less than the smallest even number. What is the sum of the largest odd number and the largest even number?**

A. 82

B. 83

C. 74

D. Cannot be determined

E. None of these

E. None of these

Explanation:

Let a smallest odd number and b smallest even number. This gives

a + a+2 + a+4 + b + b+2 + b+4 = 231

a + b = 73

Given, a = b – 11

solve both equations

answer is a+4 + b+4 = 81

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