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Question 1 of 10
1. Question
1 pointsCategory: Quantitative Aptitude65536, 32768, 49152, 49152, ?
Correct
Solution:
65536/2 = 32768
32768*1.5 = 49152
49152/1 = 49152
49152*0.5 = 24576Incorrect
Solution:
65536/2 = 32768
32768*1.5 = 49152
49152/1 = 49152
49152*0.5 = 24576 -
Question 2 of 10
2. Question
1 pointsCategory: Quantitative Aptitude6,6,8,14,26,?
Correct
Solution:
6+12-1 = 6
6+22-2 = 8
8+32– 3 =14
14+42-4 = 26
26+52-5 = 46Incorrect
Solution:
6+12-1 = 6
6+22-2 = 8
8+32– 3 =14
14+42-4 = 26
26+52-5 = 46 -
Question 3 of 10
3. Question
1 pointsCategory: Quantitative Aptitude- 21X2 +X-2 = 0
- 6Y2 -5Y+1 = 0
Correct
Solution:
X = 2/7, -1/3
Y = 1/3, 1/2Incorrect
Solution:
X = 2/7, -1/3
Y = 1/3, 1/2 -
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeIn 120litres of Mixture ratio of ratio of Milk to Water is 4:1. Now 24litres of Mixture is taken out and replaced by same quantity of water then what is the % of Milk in final mixture?
Correct
Solution:
120litres = Milk+water
Milk = 96litres Water= 24litres
24litres replaced means by water then
Milk = 76.8 in final mixture
% = 76.8/120*100 = 64%Incorrect
Solution:
120litres = Milk+water
Milk = 96litres Water= 24litres
24litres replaced means by water then
Milk = 76.8 in final mixture
% = 76.8/120*100 = 64% -
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeA box contains 4 Apples and 5 Oranges if two of them are drawn at random then what is the probability that one is Apple and other is Orange ?
Correct
Solution:
4*5/9c2 = 5/9
Incorrect
Solution:
4*5/9c2 = 5/9
-
Question 6 of 10
6. Question
1 pointsCategory: Quantitative Aptitude√32041 X √3481 – (58)2 = (?)3+ 338 What value will come in place of question Mark
Correct
Solution:
179*59 – 3364 = 338+ (?)3
? =19Incorrect
Solution:
179*59 – 3364 = 338+ (?)3
? =19 -
Question 7 of 10
7. Question
1 pointsCategory: Quantitative Aptitude76% of √18225 + 72% of √9025 = ?
Correct
Solution:
(76*135 + 72*95)/100 = 171
Incorrect
Solution:
(76*135 + 72*95)/100 = 171
-
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeThe ratio of Asha and Trsiha age is 3:5. Three years hence the difference of their ages is 10 years. Then sum of their ages 5 years ago is ?
Correct
Solution:
5x-3x = 10
X = 5
Asha = 15
Trisha = 25
Sum of ages five years ago =10+20 =30Incorrect
Solution:
5x-3x = 10
X = 5
Asha = 15
Trisha = 25
Sum of ages five years ago =10+20 =30 -
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeIf Ramesh drives at 10Km/hr reaches railway station which is 6Kms away from house at 10:00AM. He started from his house at 10Km/hr but he forgot his train ticket he realized it after travelling 12mins. Then he returned back to home at double speed and wasted 3 minutes to get his ticket. Now at what speed he has to start from home to reach station at 10:00AM.
Correct
Solution:
If he drives at 10Km/hr he reaches 6kms in 36 min
In 12 mins he travelled 2 kms and doubled his speed i.e., 20Km/hr then he travels his back in 6 minutes
Ticket delay time 3 mins
Now he is left with only 15 mins to reach station
S = 6*4 = 24Incorrect
Solution:
If he drives at 10Km/hr he reaches 6kms in 36 min
In 12 mins he travelled 2 kms and doubled his speed i.e., 20Km/hr then he travels his back in 6 minutes
Ticket delay time 3 mins
Now he is left with only 15 mins to reach station
S = 6*4 = 24 -
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeA square shaped house having diagonal length of 54m is surrounded by a four sided square wall having length of 39m then what would be the cost of gardening outside house but inside wall if cost of gardening is Rs. 27/m2 .
Correct
Solution:
Inside House: 542/2 = 1458
Wall : 39*39 = 1521
Area of Outside house and inside wall is 1521-1458 = 63
Cost of gardening = 63*27 = 1701Incorrect
Solution:
Inside House: 542/2 = 1458
Wall : 39*39 = 1521
Area of Outside house and inside wall is 1521-1458 = 63
Cost of gardening = 63*27 = 1701
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