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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeArun drives and goes to his office. He has to reach office at 9 am. On the first day, he drove at a speed of 10 km/h and reached office at 10 am and was late. So next day he drove with a speed of 15 km/h and reached office 1 hr early i.e. at 8 am. At what speed he should drive to reach on exact time?
Correct
Explanation
We know if the speed is increased by 50% which is happening in this case 10 + (50% of 10) = 15
The speed is increased by 33.33% (According to product stability ratio)
So, 33.33% of time = 2 hour
Hence total time = 6 hour
⇒ so, distance = 10 × 6 = 60km
Thus, distance is to be covered in 5 hours
So, Speed = 60 / 5 = 12 km/hIncorrect
Explanation
We know if the speed is increased by 50% which is happening in this case 10 + (50% of 10) = 15
The speed is increased by 33.33% (According to product stability ratio)
So, 33.33% of time = 2 hour
Hence total time = 6 hour
⇒ so, distance = 10 × 6 = 60km
Thus, distance is to be covered in 5 hours
So, Speed = 60 / 5 = 12 km/h 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeA and B started a partnership business. A invested 15000 and B invested 30000. After 6 months A invested some more so that they divide the profit equally in the year end. How much did A invest additionally?
Correct
Incorrect

Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeTanya’s grandfather was 8 times older to her 16 years ago. He would be 3 times of her age 8 years from now. What was ratio of ages of Tanya and her grandfather 8 years ago?
Correct
Incorrect

Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeSeven delegates are to address a meeting. If a particular speaker is to speak before another particular speaker, find the number of ways in which this can be arranged.
Correct
Explanation
Total no. of ways = 7!
Let A to speak before B
Now since half of the total cases in which A speaks before B
(Similarly, in half of the total cases B speaks before A)
Reqd. no. of ways =12×7! =2520Incorrect
Explanation
Total no. of ways = 7!
Let A to speak before B
Now since half of the total cases in which A speaks before B
(Similarly, in half of the total cases B speaks before A)
Reqd. no. of ways =12×7! =2520 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeThere were 35 students in a hostel. Due to the admission of 7 new students the expenses of the mess were increased by Rs.42 per day while the average expenditure per head diminished by Re 1. What was the original expenditure of the mess?
Correct
Incorrect

Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeQ. (610) In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly
 2x^{2} – 27x + 81 = 0,
 3y^{2} – 50y + 168 = 0
Correct
explanation
2x^{2} – 27x + 81 = 0
2x^{2} – 18x – 9x + 81 = 0
Gives x = 9/2, 9
3y^{2} – 50y + 168 = 0
3y^{2} – 36y – 14y + 168 = 0
Gives y = 14/3, 12Incorrect
explanation
2x^{2} – 27x + 81 = 0
2x^{2} – 18x – 9x + 81 = 0
Gives x = 9/2, 9
3y^{2} – 50y + 168 = 0
3y^{2} – 36y – 14y + 168 = 0
Gives y = 14/3, 12 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeQ. (610) In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly
 3x^{2} – 14x – 24 = 0,
 3y^{2} + 32y + 64 = 0
Correct
explanation
3x^{2} – 14x – 24 = 0
3x^{2} – 18x + 4x – 24 = 0
Gives x = 4/3, 6
3y^{2} + 32y + 64 = 0
3y^{2} + 24y + 8y + 64 = 0
Gives y= 8, 8/3Incorrect
explanation
3x^{2} – 14x – 24 = 0
3x^{2} – 18x + 4x – 24 = 0
Gives x = 4/3, 6
3y^{2} + 32y + 64 = 0
3y^{2} + 24y + 8y + 64 = 0
Gives y= 8, 8/3 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeQ. (610) In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly
 3x^{2} – 8x – 35 = 0,
 3y^{2} + 37y + 104 = 0
Correct
explanation
3x^{2} – 8x – 35 = 0
3x^{2} – 15x + 7x – 35 = 0
Gives x = 5, 7/3
3y^{2} + 37y + 104 = 0
3y^{2} + 24y + 13y + 104 = 0
Gives y= 8, 13/3Incorrect
explanation
3x^{2} – 8x – 35 = 0
3x^{2} – 15x + 7x – 35 = 0
Gives x = 5, 7/3
3y^{2} + 37y + 104 = 0
3y^{2} + 24y + 13y + 104 = 0
Gives y= 8, 13/3 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeQ. (610) In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly
 3x^{2} – 5x – 78 = 0,
 3y^{2} + 28y + 65 = 0
Correct
explanation
3x^{2} – 5x – 78 = 0
3x^{2} – 18x + 13x – 78 = 0
Gives x = 13/3, 6
3y^{2} + 28y + 65 = 0
3y^{2} + 15y + 13y + 65 = 0
Gives y = 5, 13/3Incorrect
explanation
3x^{2} – 5x – 78 = 0
3x^{2} – 18x + 13x – 78 = 0
Gives x = 13/3, 6
3y^{2} + 28y + 65 = 0
3y^{2} + 15y + 13y + 65 = 0
Gives y = 5, 13/3 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeQ. (610) In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly
 5x^{2} – 23x + 12 = 0,
 5y^{2} – 28y + 15 = 0
Correct
explanation
x = 3/5, 4
y = 3/5, 5Incorrect
explanation
x = 3/5, 4
y = 3/5, 5
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