# IBPS PO 2017 Practice Test – Quant Day 6

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Welcome to Online Reasoning Section with explanation in AffairsCloud.com. Here we are creating Best question samples for IBPS PO 2017. We have included Some questions that are repeatedly asked in bank exams !!!

IBPS PO 2017 : Reasoning Test– 6 PM Every Day
IBPS PO 2017 : Quants Test– 7 PM Every Day

Q(1-5). Study the following Table containing shapes and dimensions of the field. 1. What is the difference between the cost of fencing for square and Right angled triangle?
A. Rs. 3052
B. Rs. 3092
C. Rs. 2052
D. Rs. 2592
E. None
Solution:
Square = 260 * 111 = 28860
Perimeter of Right angled triangle = 92+69+ sqrt (92 2 + 69 2 ) = 276
Cost of fencing = 276* 112 = 30912
Difference = 30912-28860= 2052

2. Sum of Cost of fencing of all fields together is ?
A. Rs 144350
B. Rs 150210
C. Rs 161280
D. Rs 174660
E. None
Solution:
Square = 260 * 111 = 28860
Rectangle = 264 * 113 = 29832
Right Angled Triangle = 276 * 112 =30912
Parallelogram = 270 * 113 = 30510
Circle = 264 * 114 = 30096
Sum = 28860+29832+30912+30510+30096 = 150210

3. What is the difference between cost of fencing for Rectangle and Parallelogram?
A. Rs 378
B. Rs 468
C. Rs 598
D. Rs 678
E. None
None
Solution :
Rs (30510-29832) = Rs 678

4. The perimeter of the Right angled triangle is what percent more than Perimeter of Circle?
A. 7.23
B. 6.25
C. 4.54
D. 3.33
E. None
Solution:
276-264/264 * 100 = 4.54

5. Cost of fencing for which of the following fields will be highest?
A. Right Angle Triangle
B. Parallelogram
C. Circle
D. Square
E. Rectangle
Answer – A. Right Angle Triangle
Solution:
Square = 260 * 111 = 28860
Rectangle = 264 * 113 = 29832
Right Angled Triangle = 276 * 112 =30912
Parallelogram = 270 * 113 = 30510
Circle = 264 * 114 = 30096

Q(6-10). Each question contains statement followed Quantity I and Quantity II. Find relationship between both the quantities.

1. Find the Volume
Quantity I: If the side of cube is 68 metre
Quantity II: If the diameter of sphere is 84 metre
A. Quantity I > Quantity II
B. Quantity I < Quantity II
C. Quantity I ≥ Quantity II
D. Quantity I ≤ Quantity II
E. Quantity I = Quantity II or relationship cannot be established
Answer – A. Quantity I > Quantity II
Solution:
Quantity I:
V = 68*68*68 = 314432
Quantity II: 4/3 * 22/7 * 42*42*42 = 310464

2. No of Days in which A alone can complete work
Quantity I: B alone can complete a work in 12 days. C can complete it in 24 days. A and B started work and worked for 3 days. They both left now C finished the remaining work in 9 days.
Quantity II: A and B complete work in 8 days, B and C can complete work in 12 days, C and A can complete work in 8 days.
A. Quantity I > Quantity II
B. Quantity I < Quantity II
C. Quantity I ≥ Quantity II
D. Quantity I ≤ Quantity II
E. Quantity I = Quantity II or relationship cannot be established
Answer – B. Quantity I < Quantity II
Solution :
Quantity I:
3(1/A+1/12) + 9/24 = 1
A = 8 days
Quantity II:
A+B = 8 days
B+C = 12 days
A+C = 8 days
2(1/A+ 1/B+1/C) = 1/8 + 1/12 + 1/8
A = 12 days

3. Find profit percentage
Quantity I: If CP is 39,900 and MP is 46200 and discount offered on MP is 5%
Quantity II: If difference between MP and SP is 4840 and discount offered is 10% and CP is 39600
A. Quantity I > Quantity II
B. Quantity I < Quantity II
C. Quantity I ≥ Quantity II
D. Quantity I ≤ Quantity II
E. Quantity I = Quantity II or relationship cannot be established
Answer – E. Quantity I = Quantity II or relationship cannot be established
Solution:
For Quantity I
SP = 46200 * 95 /100 = 43890
43890 = 39900 * (100+x)/100 = 10%
For Quantity II
MP –SP =4840
SP = 43560 since discount is 10%
Then profit percent is 10%

4. Find Interest
Quantity I: If Sum is Rs 1632 lent at simple interest at 5% rate for 2 years
Quantity II: If sum is Rs 2000 lent at Compound interest at 4% for 2 years
A. Quantity I > Quantity II
B. Quantity I < Quantity II
C. Quantity I ≥ Quantity II
D. Quantity I ≤ Quantity II
E. Quantity I = Quantity II or relationship cannot be established
Answer – E. Quantity I = Quantity II or relationship cannot be established
Solution:
Simple Interest rate = 1632* 5*2 /100 = 163.2
Compound Interest rate = 2000(1+4/100) 2 – 2000 = 163.2

5. Find X
Quantity I : X 2 – 84X + 1764 = 0
Quantity II : X 2 – 86X + 1849 = 0
A. Quantity I > Quantity II
B. Quantity I < Quantity II
C. Quantity I ≥ Quantity II
D. Quantity I ≤ Quantity II
E. Quantity I = Quantity II or relationship cannot be established
Answer – B. Quantity I < Quantity II
Solution:
Solving equations X = 42
X = 43

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