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**Q(1-5). Study the following Table containing shapes and dimensions of the field.**

**What is the difference between the cost of fencing for square and Right angled triangle?**

A. Rs. 3052

B. Rs. 3092

C. Rs. 2052

D. Rs. 2592

E. None

Answer –**C. Rs. 2052**

Solution:

Square = 260 * 111 = 28860

Perimeter of Right angled triangle = 92+69+ sqrt (92 2 + 69 2 ) = 276

Cost of fencing = 276* 112 = 30912

Difference = 30912-28860= 2052**Sum of Cost of fencing of all fields together is ?**

A. Rs 144350

B. Rs 150210

C. Rs 161280

D. Rs 174660

E. None

Answer –**B. Rs 150210**

Solution:

Square = 260 * 111 = 28860

Rectangle = 264 * 113 = 29832

Right Angled Triangle = 276 * 112 =30912

Parallelogram = 270 * 113 = 30510

Circle = 264 * 114 = 30096

Sum = 28860+29832+30912+30510+30096 = 150210**What is the difference between cost of fencing for Rectangle and Parallelogram?**

A. Rs 378

B. Rs 468

C. Rs 598

D. Rs 678

E. None

Answer –**D. Rs 678**

None

Solution :

Rs (30510-29832) = Rs 678**The perimeter of the Right angled triangle is what percent more than Perimeter of Circle?**

A. 7.23

B. 6.25

C. 4.54

D. 3.33

E. None

Answer –**C. 4.54**

Solution:

276-264/264 * 100 = 4.54**Cost of fencing for which of the following fields will be highest?**

A. Right Angle Triangle

B. Parallelogram

C. Circle

D. Square

E. Rectangle

Answer –**A. Right Angle Triangle**

Solution:

Square = 260 * 111 = 28860

Rectangle = 264 * 113 = 29832

Right Angled Triangle = 276 * 112 =30912

Parallelogram = 270 * 113 = 30510

Circle = 264 * 114 = 30096

**Q(6-10). Each question contains statement followed Quantity I and Quantity II. Find relationship between both the quantities.**

**Find the Volume**

**Quantity I: If the side of cube is 68 metre**

**Quantity II: If the diameter of sphere is 84 metre**

A. Quantity I > Quantity II

B. Quantity I < Quantity II

C. Quantity I ≥ Quantity II

D. Quantity I ≤ Quantity II

E. Quantity I = Quantity II or relationship cannot be established

Answer –**A. Quantity I > Quantity II**

Solution:

Quantity I:

V = 68*68*68 = 314432

Quantity II: 4/3 * 22/7 * 42*42*42 = 310464**No of Days in which A alone can complete work**

**Quantity I: B alone can complete a work in 12 days. C can complete it in 24 days. A and B started work and worked for 3 days. They both left now C finished the remaining work in 9 days.**

**Quantity II: A and B complete work in 8 days, B and C can complete work in 12 days, C and A can complete work in 8 days.**

A. Quantity I > Quantity II

B. Quantity I < Quantity II

C. Quantity I ≥ Quantity II

D. Quantity I ≤ Quantity II

E. Quantity I = Quantity II or relationship cannot be established

Answer –**B. Quantity I < Quantity II**

Solution :

Quantity I:

3(1/A+1/12) + 9/24 = 1

A = 8 days

Quantity II:

A+B = 8 days

B+C = 12 days

A+C = 8 days

2(1/A+ 1/B+1/C) = 1/8 + 1/12 + 1/8

A = 12 days**Find profit percentage**

**Quantity I: If CP is 39,900 and MP is 46200 and discount offered on MP is 5%**

**Quantity II: If difference between MP and SP is 4840 and discount offered is 10% and CP is 39600**

A. Quantity I > Quantity II

B. Quantity I < Quantity II

C. Quantity I ≥ Quantity II

D. Quantity I ≤ Quantity II

E. Quantity I = Quantity II or relationship cannot be established

Answer –**E. Quantity I = Quantity II or relationship cannot be established**

Solution:

For Quantity I

SP = 46200 * 95 /100 = 43890

43890 = 39900 * (100+x)/100 = 10%

For Quantity II

MP –SP =4840

SP = 43560 since discount is 10%

Then profit percent is 10%**Find Interest**

**Quantity I: If Sum is Rs 1632 lent at simple interest at 5% rate for 2 years**

**Quantity II: If sum is Rs 2000 lent at Compound interest at 4% for 2 years**

A. Quantity I > Quantity II

B. Quantity I < Quantity II

C. Quantity I ≥ Quantity II

D. Quantity I ≤ Quantity II

E. Quantity I = Quantity II or relationship cannot be established

Answer –**E. Quantity I = Quantity II or relationship cannot be established**

Solution:

Simple Interest rate = 1632* 5*2 /100 = 163.2

Compound Interest rate = 2000(1+4/100) 2 – 2000 = 163.2**Find X**

**Quantity I : X 2 – 84X + 1764 = 0**

**Quantity II : X 2 – 86X + 1849 = 0**

A. Quantity I > Quantity II

B. Quantity I < Quantity II

C. Quantity I ≥ Quantity II

D. Quantity I ≤ Quantity II

E. Quantity I = Quantity II or relationship cannot be established

Answer –**B. Quantity I < Quantity II**

Solution:

Solving equations X = 42

X = 43

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