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**Q(1-5). Study the following Bar chart and answer the following questions**

**Given Bar chart represents no of workers joining and leaving a company from 2001 to 2007. No of workers at the end of the year of 2000 is 2000.Line Graph represents no of Male workers more than Female workers at end of the years from 2001 to 2007.**

**At end of which year no of Maximum no of Male worked?**

A. 2001

B. 2004

C. 2005

D. 2006

E. 2007

**E. 2007**

Solution:

At end of Year 2001:

No of workers : 2000+229-212 = 2017 = M+F

M-F = 101

Males = 1059 Females = 958

At end of Year 2002:

No of workers : 2017+225-244 = 1998 = M+F

M-F = 90

Males = 1044 Females = 954

At end of Year 2003:

No of workers : 1998+232-249 = 1981 = M+F

M-F = 111

Males = 1046 Females = 935

At end of Year 2004:

No of workers : 1981+236-228 = 1989 = M+F

M-F = 103

Males= 1046 Females = 943

At end of Year 2005:

No of workers : 1989+237-222 = 2004 = M+F

M-F = 100

Males = 1052 Females = 952

At end of Year 2006:

No of workers : 2004+ 219-221 =2002 =M+F

M-F = 98

Males = 1050 Females =952

At end of Year 2007:

No of workers : 2002+246-236 = 2012 = M+F

M-F = 110

Males = 1061 Females = 951**At the end of how many years no of workers in company is less than 2000?**

A. One

B. Two

C. Three

D. Four

E. None

**C. Three****Maximum no of employees are working at end of which year?**

A. 2001

B. 2005

C. 2006

D. 2007

E. None

**A. 2001****At end of which year minimum no of females are working?**

A. 2002

B. 2003

C. 2004

D. 2005

E. 2006

**B. 2003****How many no of Females left at end of year 2004?**

A. 16

B. 23

C. 24

D. 27

E. Cannot be determined

**E. Cannot be determined**

**Q(6-10). Each question contains statement followed Quantity I and Quantity II. Find the relationship between both the quantities.**

**Find the initial quantity of milk in the container**

**Quantity I : If pure milk contained in container is 125 litres after replacing 36 litres of water for three times**

**Quantity II: If pure milk contained in container is 64 litres after replacing 72 litres of water for three times**

A. Quantity I > Quantity II

B. Quantity I < Quantity II

C. Quantity I ≥ Quantity II

D. Quantity I ≤ Quantity II

E. Quantity I = Quantity II or relationship cannot be established

**E. Quantity I = Quantity II or relationship cannot be established**

Solution:

In both statements initial mixture is 216 litres.**Ram and Rahim invested a total sum of Rs.20,000 for 6 & 8 months respectively. They divided the profits in the ratio of 3:2.**

**Quantity I: Ram’s Investment**

**Quantity II : Rahim’s investment**

A. Quantity I > Quantity II

B. Quantity I < Quantity II

C. Quantity I ≥ Quantity II

D. Quantity I ≤ Quantity II

E. Quantity I = Quantity II or relationship cannot be established

**A. Quantity I > Quantity II**

Solution:

Since profit made by Ram is more than Rahim despite of his investment period less than Rahim.**From a pack of 52 cards a card is drawn at random**

**Quantity I : The probability of card being Heart or Queen?**

**Quantity II : The probability of card being Black or Queen?**

A. Quantity I > Quantity II

B. Quantity I < Quantity II

C. Quantity I ≥ Quantity II

D. Quantity I ≤ Quantity II

E. Quantity I = Quantity II or relationship cannot be established

**B. Quantity I < Quantity II**

Solution:

4/13 < 7/13**What is the compound interest?**

**Quantity I . Rs 5000 is lent at 10% interest for 3 years compounded annually**

**Quantity II. Rs 3800 is lent at 20% interest for 2 years compounded annually**

A. Quantity I > Quantity II

B. Quantity I < Quantity II

C. Quantity I ≥ Quantity II

D. Quantity I ≤ Quantity II

E. Quantity I = Quantity II or relationship cannot be established

**B. Quantity I < Quantity II**

Solution:

Quantity I : 5000(1+10/100) 3 – 5000 = 1655

Quantity II : 3800(1+20/100) 2 – 3800 = 1672**A shopkeeper sold two articles for Rs 3000. He gained 20% in total then what is cost price ?**

**Quantity I : If profit % on article 1 is 10%**

**Quantity I : If profit % on article 2 is 25%**

A. Quantity I > Quantity II

B. Quantity I < Quantity II

C. Quantity I ≥ Quantity II

D. Quantity I ≤ Quantity II

E. Quantity I = Quantity II or relationship cannot be established

**B. Quantity I < Quantity II**

Solution:

3000*120/100 = x(110/100) + (3000-x)* 125/100

X = 1000

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