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**Q(1-5) Study the Pie Charts and answer the following information.**

**What is the average no of boys in School A, B, and C?**

A. 23140

B. 23440

C. 23580

D. 23700

E. 24130**E. 24130**

Solution:

Total no of students:

A = 25300*19/100 = 48070

B = 25300*22/100 = 55660

C = 25300* 18/100 = 45540

D = 25300*21/100 = 53130

E = 25300*20/100 = 50600

No of Girls:

A = 124000*21/100 = 26040

B = 124000*22/100 = 27280

C = 124000*19/100 = 23560

D= 124000*21/100 = 26040

E = 124000*17/100 = 21080

No of Boys: Total Students – Girls

48070-26040 = 22030

55660-27280 = 28380

45540- 23560 = 21980

53130- 26040 = 27090

50600- 21080 = 29520

Average = (22030+28380+21980)/3 = 24130**Which School accounts for the highest no of Boys?**

A. School A

B. School B

C. School C

D. School D

E. School E**E. School E**

Solution:

No of Boys: Total Students – Girls

48070-26040 = 22030

55660-27280 = 28380

45540- 23560 = 21980

53130- 26040 = 27090

50600- 21080 = 29520**What is the average no of Boys in all schools together?**

A. 24600

B. 24800

C. 25300

D. 25800

E. None**D. 25800**

Solution:

No of boys 253000-124000 = 129000. Average = 129000/5 = 25800**What is the average of Boys from A,C,D and E together?**

A. 23125

B. 24655

C. 25155

D. 26155

E. None**C. 25155**

Solution:

Total Boys = 129000

Boys in B = 28380

Then Total Boys in B,C,D,E is 129000-22030 = 100620

Average = 100620/4 = 25155**Difference between no of Boys and Girls in which school is Maximum?**

A. School A

B. School B

C. School C

D. School D

E. School E**E. School E**

Solution:

Total no of students:

A = 25300*19/100 = 48070

B = 25300*22/100 = 55660

C = 25300* 18/100 = 45540

D = 25300*21/100 = 53130

E = 25300*20/100 = 50600

No of Girls:

A = 124000*21/100 = 26040

B = 124000*22/100 = 27280

C = 124000*19/100 = 23560

D= 124000*21/100 = 26040

E = 124000*17/100 = 21080

No of Boys: Total Students – Girls

A:48070-26040 = 22030

B:55660-27280 = 28380

C: 45540- 23560 = 21980

D:53130- 26040 = 27090

E:50600- 21080 = 29520

Difference:

A: 26040 – 22030 =4010

B: 28380-27280 = 1100

C: 23560-21980 = 1580

D: 27090 -26040 = 1050

E: 29520 – 21080 = 8440**The cost painting a Square wall is directly proportional to its area. Painter charged Rs 10,000 of 10m x 10m. How many walls of 5m x 5m can be Painted for the same cost?**A. 2

B. 4

C. 5

D. 10

E. None

Solution:**B. 4**

Cost α Area 2

10,000 = K* 10 2

K = 100

Then 10000 = N*100*5*5

N = 4**A can do a piece of work in 12 days. B can do a piece of work in 8 days. C takes 5/4 th time of which A and B together take. A Worked for 3 hours. B worked 2 Hours. Then C can complete the remaining work**A. 2 Days

in how many days?

B. 3 Days

C. 4 Days

D. 6 Days

E. None

A and B together work =1/ (1/12 +1/8) = 96/20**B. 3 Days**

Solution:

C = 5/4*96/20 =6 days

3/12 + 2/8+ x/6 = 1

X =3 days**A and B are 300 Kms apart. Speed of B is 50% more than A. They travel in opposite direction, A started at 8:00AM and B started 9:00AM and they meet at 11:00 AM then speed of B would be?**A. 50 Km/hr

B. 75 km/hr

C. 100 Km/hr

D. 120 Km/hr

E. None

Solution:**B. 75 km/hr**

300 = S*3 + S*150/100 *2

S = 50

Speed of B = 75**In How many ways Eight Rooks can be placed on a standard chess board without attacking each other?**

A. 10080

B. 20160

C. 40320

D. 80640

E. None**C. 40320**

Solution:

No of ways = (8!) 2 /8! = 40320**PIN of Ramesh Bank Locker is 5 digit number. Right most digit in that number is the first digit. Third digit is four times of 1 st digit. Sum of First and 2 nd digit is equal to 3 rd digit.5 th digit is greater than 2 nd digit and less than 3 rd digit. 5 th digit is two more than 4 th digit. Then Ramesh PIN would be?**

A. 53431

B. 75431

C. 75862

D. 53862

E. Cannot be determined**C. 75862**

Soluition:

Easy way verification process

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