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Welcome to Online Reasoning Section with explanation in AffairsCloud.com. Here we are creating Best question samples for **IBPS PO 2017**. We have included Some questions that are repeatedly asked in bank exams !!!

**Q(1-5). Study the following data and answer the questions**

In the given below table the roots of the equations are radius of the circles C 1, C 2, C 3, C 4, C 5. Radius of the circles are R1, R2, R3, R4, R5 not necessarily in the same order. Below figure depicts the picture of circles with their radius and having common centre O.

**What is the difference between the area of circles having radius R1 and R2?**

A. 11

B. 22

C. 33

D. 44

E. None

Answer –**D. 44**

Solution:

For Circle C 1 equation X= 6v2, -4v2

C 2 : Y = 5v3, -7v3

C 3 : Z = 4v5, -2v5

C 4 : A = 3v6 , -4v6

C 5 : B = 2v10, -3v10

Since radius is always positive so we have to consider only positive rots

Based on figure R5>R4>R3>R2>R1

Radius of Circles C 1, C 2, C 3, C 4,, C 5 are (6v2=8.485), (5v3 = 8.666),(4v5 = 8.944), (3v6 = 7.348), (2v10 =6.324)

respectively

Then raidus of the circles C 1, C 2, C 3, C 4,, C 5 will be R3,R4,R5,R2,R1 respectively

For question difference of areas p(2v10) 2 – p(3v10) 2 = 44 units**What is the ratio of perimeters of smallest circle to largest circle ?**

A. 1:2

B. 1:v2

C. 1:v3

D. 2:v5

E. None of these

Answer –**B. 1:v2**

Solution : 2v10: 4v5 =1:v2**What is the area of the largest square that can be inscribed in the smallest circle?**

A. 80

B. 40

C. 20

D. 10

E. None of these

Answer –**A. 80**

Solution: Largest square that can be inscribed in a circle will have diagonal of 2R

Side of square will be v2 R

R = 2v10 for smallest circle

Area of square = (v2 * 2v10) 2 = 80**Which circle is having the maximum diameter?**

A. Circle C 1

B. Circle C 2

C. Circle C 3

D. Circle C 4

E. Circle C 5

Answer –**C. Circle C 3**

Circle C 3 is having bigger radius 4v5**Area of Circle having radius R5 is how many times the area of circle having radius R1?**

A. 1

B. 2

C. 3

D. 4

E. None

Answer – B. 2

Area of Circle C 3 = p * (4v5) 2 = 80p

Area of Circle C 5 = p* (2v10) 2 = 40p (means 2 times)

**Q(6-10). Study the following and answer the questions**

In the given table contains selling prices of items on different days and also no of items sold by two shopkeepers M & N. Cost price ’A’ of one item is same for both shop keepers which is the difference of total items sold by Shopkeeper M & N in rupees.

**Which shopkeeper has earned the total profit?**

A. Shopkeeper M

B. Shopkeeper N

C. Both Equal

D. Cannot be determined

E. None

Answer –**B. Shopkeeper N**

Solution: Cost Price = A =110 = difference of items sold by M & N

(253+440+649+407+363) – (231+418+627+385+341) = 2112 – 2002 = 110

Profit: SP- CP based on table

Calculating SP on all days

Then Total Profit earned by M is 5060 and N is 6710**The difference between total profit earned by the shopkeepers is?**

A. 1650

B. 1680

C. 1860

D. 1720

E. None

Answer –**A. 1650**

Solution:

6710-5060 = 1650**What is the approximate total profit percentage earned by shopkeeper M?**

A. 1%

B. 2%

C. 3%

D. 4%

E. None

Answer –**B. 2%**

Solution:

CP = total items * 110 =2112*110 = 2323220

SP =(649*120+440*110+253*90+407*110+363*120) = 237380

% = (237380-232320)/232320*100 = 2.17%**The difference between the profit earned by shopkeepers on Monday is?**

A. 6050

B. 6490

C. 6270

D. 6660

E. None

Answer –**A. 6050**

Solution: 627*20 – 649*10 = 6050**What is the Selling price offered by Shopkeeper N on Thursday?**

A. 110

B. 120

C. 100

D. 90

E. None

Answer –**D. 90**

Solution: 110- 2 *10 =90

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