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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeDirections for questions 15: Study the following graph carefully to answer the given questions.
A boatman rows downstream at 4 km/hr on Friday. Find the upstream speed and speed of the current respectively?
Correct
Solution: Since, (downstream speed + Upstream speed)/2 = Speed of boat in still water, therefore 2*speed of boat in still water downstream speed = upstream speed i.e. upstream speed = 6 4 = 2 km/hr. Also speed of current = (downstream speed – upstream speed)/2 = (42)/2 = 1 km/hr.
Incorrect
Solution: Since, (downstream speed + Upstream speed)/2 = Speed of boat in still water, therefore 2*speed of boat in still water downstream speed = upstream speed i.e. upstream speed = 6 4 = 2 km/hr. Also speed of current = (downstream speed – upstream speed)/2 = (42)/2 = 1 km/hr.

Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeDirections for questions 15: Study the following graph carefully to answer the given questions.
A boatman rows up stream at 4km/hr, 2 km/hr and 8 km/hr on Monday, Wednesday and Thursday respectively. Then find the ratio between the downstream speed of boat on Monday, Wednesday, and Thursday together and the rate of current on the same days together?
Correct
Solution: Downstream speed on Monday = (2* speed of boat in still water) – upstream speed = (2*5) – 4 =6 km/hr, similarly for Wednesday downstream speed is (2* 4) – 2 = 6 km/hr. For Thursday since speed of boat in still water is not known we will use speed of current i.e. (Downstream speed – upstream speed)/2 = Speed of current. Therefore downstream speed = 2* speed of current + upstream speed = (2*4) + 8 = 16 km /hr. Therefore, the downstream speed of boat on Monday, Wednesday, and Thursday together =6+6+16= 28 km / hr. And rate of current on Monday= (downstream speed upstream speed)/2 = (64)/2= 1 km/hr, on Wednesday = (62)/2=2 km/hr, and on Thursday = (168)/2= 4km/hr. Therefore, the rate of current on the same days together = 1+2+4= 7 km/hr. Therefore ratio= 28:7= 4:1.
Incorrect
Solution: Downstream speed on Monday = (2* speed of boat in still water) – upstream speed = (2*5) – 4 =6 km/hr, similarly for Wednesday downstream speed is (2* 4) – 2 = 6 km/hr. For Thursday since speed of boat in still water is not known we will use speed of current i.e. (Downstream speed – upstream speed)/2 = Speed of current. Therefore downstream speed = 2* speed of current + upstream speed = (2*4) + 8 = 16 km /hr. Therefore, the downstream speed of boat on Monday, Wednesday, and Thursday together =6+6+16= 28 km / hr. And rate of current on Monday= (downstream speed upstream speed)/2 = (64)/2= 1 km/hr, on Wednesday = (62)/2=2 km/hr, and on Thursday = (168)/2= 4km/hr. Therefore, the rate of current on the same days together = 1+2+4= 7 km/hr. Therefore ratio= 28:7= 4:1.

Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeDirections for questions 15: Study the following graph carefully to answer the given questions.
What time will be taken by a boat to cover a distance on Thursday along the stream, if the upstream of boat is 2 km/hr?
Correct
Solution: Since, speed of current = (Speed of boat downstream – Speed of boat upstream)/2, therefore speed of boat downstream = (2* speed of current) + speed of boat upstream = (2* 4) + 2= 10km/ hr. Downstream distance covered on Thursday = 20% of 200 = 40 km. Hence, time taken by a boat to cover a distance f 40 km on Thursday along the stream = 40/10 = 4 hr.
Incorrect
Solution: Since, speed of current = (Speed of boat downstream – Speed of boat upstream)/2, therefore speed of boat downstream = (2* speed of current) + speed of boat upstream = (2* 4) + 2= 10km/ hr. Downstream distance covered on Thursday = 20% of 200 = 40 km. Hence, time taken by a boat to cover a distance f 40 km on Thursday along the stream = 40/10 = 4 hr.

Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeDirections for questions 15: Study the following graph carefully to answer the given questions.
What is the sum of total distance travelled by the boat on Monday, Tuesday, Wednesday and Friday together?
Correct
Solution: Total distance travelled on Monday = distance travelled downstream + distance travelled upstream = 24% of 200 + 30% of 300 = 48 + 90 = 138 km. Similarly for Tuesday, total distance travelled = 30 + 60 = 90 km. For Wednesday total distance travelled = 30 + 72 = 102 km. For Friday total distance travelled = 88 km. Hence, total distance travelled by the boat on Monday, Tuesday, Wednesday and Friday together = 138+90+102+88= 418 km
Incorrect
Solution: Total distance travelled on Monday = distance travelled downstream + distance travelled upstream = 24% of 200 + 30% of 300 = 48 + 90 = 138 km. Similarly for Tuesday, total distance travelled = 30 + 60 = 90 km. For Wednesday total distance travelled = 30 + 72 = 102 km. For Friday total distance travelled = 88 km. Hence, total distance travelled by the boat on Monday, Tuesday, Wednesday and Friday together = 138+90+102+88= 418 km

Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeDirections for questions 15: Study the following graph carefully to answer the given questions.
A boatman rows up stream at 16 km/hr on Tuesday. Find the approximate time taken by the boat to cover downstream distance on the same day?
Correct
Solution: downstream speed = (2*6(speed of current)) + 16(upstream speed) = 28 km/hr. Downstream distance on Tuesday = 30 km. Therefore approximate time taken = 30/ 28 ~ 1 hr
Incorrect
Solution: downstream speed = (2*6(speed of current)) + 16(upstream speed) = 28 km/hr. Downstream distance on Tuesday = 30 km. Therefore approximate time taken = 30/ 28 ~ 1 hr

Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeDirections for Question number 68: The questions consist of two/three statements numbered “I, II and III” given below it. You have to decide whether the data provided in the statement are sufficient to answer the questions?
What is the length of the train?
Statement I: If train can cross a platform in 35 second and a pole in 15 sec
Statement II: If the length of platform is 400 m
Statement III: If the speed of train is 70 km/hrCorrect
Solution: From I and III: speed = 70 km/hr and crosses the pole in 15 sec, so length =
speed*time. Also from I and II: (400 + L(T))/Speed = 35 sec.. (i) and L(T)/Speed = 15
sec. Hence, we can find length of the train.Incorrect
Solution: From I and III: speed = 70 km/hr and crosses the pole in 15 sec, so length =
speed*time. Also from I and II: (400 + L(T))/Speed = 35 sec.. (i) and L(T)/Speed = 15
sec. Hence, we can find length of the train. 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeDirections for Question number 68: The questions consist of two/three statements numbered “I, II and III” given below it. You have to decide whether the data provided in the statement are sufficient to answer the questions?
How many books are there on the bookshelf?
Statement I: The bookshelf is 12 feet long.
Statement II: The average weight of each book is 1.2 pounds. And only one layer of books is spread width wise along the length of the bookshelf.
Statement III: The width of each book is 4 inches.Correct
Solution: Since statement I tell us about the length of table. Statement II tells us that only one layer is spread that too width wise across the length of the bookshelf (here, weight is given just to confuse and is irrelevant). Statement II tell width of each book. Hence all the three statements are required to answer the question.
Incorrect
Solution: Since statement I tell us about the length of table. Statement II tells us that only one layer is spread that too width wise across the length of the bookshelf (here, weight is given just to confuse and is irrelevant). Statement II tell width of each book. Hence all the three statements are required to answer the question.

Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeDirections for Question number 68: The questions consist of two/three statements numbered “I, II and III” given below it. You have to decide whether the data provided in the statement are sufficient to answer the questions?
In how many days 6 men and 5 women can complete the work working together?
Statement I: The ratio of efficiency of man to woman is 2 : 1
Statement II: 9 Women can complete threefive of the work in 15 days.
Statement III: 6 Men and a child together can complete 1/4th work in 12 days while 6 women and the child together can complete twothird of the work in 16 daysCorrect
Solution: From I and II: we have number of days in which 9 women can complete the work. So using efficiency we can find the number of days required by man to complete the work and then the required answer. From II and III: we have number of days in which 9 women can complete the work. So days required by child can be find out, and then by men. From I and III: We get 3 equations in 3 variables – man, woman and child. So it can be found too.
Incorrect
Solution: From I and II: we have number of days in which 9 women can complete the work. So using efficiency we can find the number of days required by man to complete the work and then the required answer. From II and III: we have number of days in which 9 women can complete the work. So days required by child can be find out, and then by men. From I and III: We get 3 equations in 3 variables – man, woman and child. So it can be found too.

Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeA and B enter in to a partnership and A invests Rs.10,000 in the partnership. At the end of 4 months he withdraws Rs.2000. At the end of another 5 months, he withdraws another Rs.3000. If B invests a certain sum in the partnership at the beginning of the year and leaves it intact and receives Rs.9600 as his share of the total profit of Rs.19,100 for the year, how much did B invest in the company?
Correct
Solution: The total profit for the year is 19100. Of this B gets Rs.9600. Therefore, A would get (19100 – 9600) = Rs.9500. Therefore, the ratio of the investments of A : B = 9500 : 9600 = 95 : 96. So, the amount of money that A had invested in the company on a moneymonth basis will be = 4 * 10000 + 5 * 8000 + 3 * 5000 = 40000 + 40000 + 15000 = 95000. If A had 95000 money months invested in the company, B would have had 96,000 money months invested in the company (as the ratio of their investments is 95 : 96). If B had 96,000 moneymonths invested in the company, he has essentially invested 96000/12 = Rs.8000
Incorrect
Solution: The total profit for the year is 19100. Of this B gets Rs.9600. Therefore, A would get (19100 – 9600) = Rs.9500. Therefore, the ratio of the investments of A : B = 9500 : 9600 = 95 : 96. So, the amount of money that A had invested in the company on a moneymonth basis will be = 4 * 10000 + 5 * 8000 + 3 * 5000 = 40000 + 40000 + 15000 = 95000. If A had 95000 money months invested in the company, B would have had 96,000 money months invested in the company (as the ratio of their investments is 95 : 96). If B had 96,000 moneymonths invested in the company, he has essentially invested 96000/12 = Rs.8000

Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeSides of a triangle are in the ratio 1/3:1/4:1/5and its perimeter is 94cm. Find the length of the largest side of the triangle?
Correct
Solution: 1/3: 1/4: 1/5= 1/3*60: 1/4*60:1/5*60 = 20:15:12. So sides of the triangle is 20a, 15a, 12 a respectively. Therefore 20a+ 15a + 12a = 94 i.e. a=94/47 =2
Therefore the length of the largest side of the triangle is 20a= 20*2= 40cm.Incorrect
Solution: 1/3: 1/4: 1/5= 1/3*60: 1/4*60:1/5*60 = 20:15:12. So sides of the triangle is 20a, 15a, 12 a respectively. Therefore 20a+ 15a + 12a = 94 i.e. a=94/47 =2
Therefore the length of the largest side of the triangle is 20a= 20*2= 40cm.
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