Hello Aspirants. Welcome to Online Quant Section in AffairsCloud.com. We are starting **IBPS Clerk course 2015 **and we are creating sample questions in **Quantitative Aptitude** section, type of which will be asked in IBPS Clerk Prelims Exam.

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**A bag contains 3 blue balls, 5 yellow balls and 4 green balls. 3 balls are drawn at random. What is the probability that exactly 1 ball is yellow in color?**

A) 23/44

B) 21/44

C) 18/33

D) 19/22

E) None of these

**B) 21/44**

**Explanation:**

From 5 yellow balls, ways for 1 ball is^{5}C_{1}= 5

Other 2 balls are either blue or green, so from 7 blue+green balls, ways for 2 balls is^{7}C_{2}= 7*6/2*1 = 21

There are a total of 12 balls. Ways for drawing 3 balls is^{12}C_{3}= 12*11*10/3*2*1 = 220

So required prob. = (5*21)/220 = 21/44

**The average of first eight results is 64 and that of last eight is 84. Find the ninth result, if the average of all 17 results is 66.**

A) 72

B) 66

C) 62

D) 58

E) 56

**C) 62**

**Explanation:**

Total of 17 results = 17*66 = 1122

Total of first eight results = 8*64 = 512

Total of last eight results = 8*84 = 672

So 9th result will be (512+672) – (1122) = 62

**A sum of Rs 3600 is invested in two parts. One part at 8% for 5 years and the remaining part at 4% for 6 years and it was found that the interest on both the parts for respective times and respective rates was same. Find the difference between the two parts.**

A) Rs 900

B) Rs 870

C) Rs 960

D) Rs 875

E) None of these

**A) Rs 900**

**Explanation:**

Interests are equal. So,

1st part *8*5/100 = 2nd part * 4*6/100

This gives, 1st part : 2nd part = 3 : 5

So 1st part = 3/(3+5) * 3600 = 1350

2nd part = 3600-1350 = 2250

So diff = 2250 – 1350

**5 chairs costs Rs 450 each, 10 tables Rs 850 each, and 15 sofa sets costs Rs 1650 each. Find the average value of each of the furniture.**

A) Rs 1200

B) Rs 1180

C) Rs 1260

D) Rs 1625

E) Rs 1090

**B) Rs 1180**

**Explanation:**

Average = 5*450 + 10*850 + 15*1650 / 5+10+15 ≈ 1180

**A 54 litres mixture contains liquids A and B in the ratio 4 : 5. How much amount of liquid B is to be added so that amount of liquid B is 70% of the new mixture?**

A) 26 l

B) 20 l

C) 16 l

D) 32 l

E) None of these

**A) 26 l**

Explanation:

A present in mixture = 4/9 * 54 = 24 l

B present in mixture = 5/9 * 54 = 30 l

Let x litres of B to be added

B is to be 70% of new mixture, so A is to be 30% of new mixture. So

30/100 of new mixture = A

30/100 * (54+x) = 24

Solve, x = 26 litres

**Find the volume of a cube whose surface area is 121 1/2 sq. m.**

A) 91.125 cu. m

B) 94 cu. m

C) 87.25 cu. m

D) 80.275 cu. m

E) 95.25 cu. m

**A) 91.125 cu. m**

**Explanation:**

121 1/2 = 243/2

6a^{2}= 243/2

So a^{2}= 81/4, a = 9/2

So volume = 9/2 * 9/2 * 9/2**A, B and C starts a business by investing Rs 5000, Rs 6000 and Rs 6500. After 4 months all of them withdraw Rs 500. Find the ratio in which the total profit will be shared among them at the end of a year.**

A) 18 : 34 : 37

B) 28 : 34 : 37

C) 34 : 28 : 37

D) 16 : 25 : 34

E) 26 : 37 : 19

**B) 28 : 34 : 37**

Explanation:

Ratio =

5000*4 + 4500*8 : 6000*4 + 5500*8 : 6500*4 + 6000*8

50 + 45*2 : 60 + 55*2 : 65 + 60*2

140 : 170 : 185

**The cost price of an article is Rs 480. Some part of it is sold at 20% loss and the remaining part at some profit%. In this transaction, there is a profit of 5% on the whole. Ratio of the amount of parts sold at 20% loss and some profit% is 1 : 5. Find the profit% on the second part.**

A) 15

B) 25

C) 10

D) 30

E) None of these

**C) 10**

**Explanation:**

Let the profit% be x%.

By the method of allegation:

Loss profit

-20 x

. 5

x-5 5-(-20)=25

Ratio at 20% loss to x% profit = 1 : 5

So x-5/25 = 1/5

Solve, x = 10

**A, B and C can complete a piece of work in 10, 12, and 15 days respectively. A and B stated the work and worked for 4 days, after which B left and C joined. Find the number of days in which A and C complete the remaining work.**

A) 2 4/5 days

B) 2 days

C) 5 3/5 days

D) 1 3/5 days

E) None of these

**D) 1 3/5 days**

Explanation:

A and B start the work. Their 1 day’s work = 1/10 + 1/12 = 11/60.

They work for 4 days, so work done by A and B in 4 days = 4 * (11/60) = 11/15

B left, Remaining work = 1 –(11/15) = 4/15

(A+C)’s 1 day’s work = 1/10 + 1/15 = 1/6

A+C completes 1 work in 6 days, so 4/15 work in 6 * (4/15) = 8/5

**The present ages of A and B is in the ratio 14 : 17. 5 years hence, the ratio of their ages will be 11 : 13 respectively. Find the sum of their present ages.**

A) 48

B) 62

C) 60

D) 52

E) None of these

**B) 62**

Explanation:

Let the ages be 14x and 17x respectively, then

(14x+5)/(17x+5) = 11/13

Solve, x = 2

So sum of present ages = 14x + 17x = 31x = 31*2 = 62

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