Hello Aspirants. Welcome to Online Quant Section in AffairsCloud.com. We are starting **IBPS Clerk course 2015 **and we are creating sample questions in **Quantitative Aptitude** section, type of which will be asked in IBPS Clerk Prelims Exam.

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**The speed of a boat in still water is 36 km/h. If the boat goes 56 km upstream in 1 hour 45 minutes, what is the time taken by the boat to cover the same distance down the stream?**

A) 2 hours 25 minutes

B) 3 hours

C) 1 hour 24 minutes

D) 2 hours 21 minutes

E) 2 hours**C) 1 hour 24 minutes**

Explanation:

Speed of boat in still water (B) = 36 km/hr

1hr 45 min = 1 + 45/60 = 7/4 hrs

Upstream speed (U)= 56/(7/4) = 32 km/hr

B = (D+U)/2, so 36 = (D+32)/2, D = 40 km/hr

Time for downstream = 56/40 = 7/5 hrs = 1 2/5 hrs = 1 hr 2/5 * 60 mins = 1 hr 24 mins**The speeds of A and B are in the ratio of 3 : 4 when they cover same distance. In this journey, A takes 30 minutes more than B to reach their destination. Find the time taken by A to reach the destination.**

A) 3 minutes

B) 1/2 hour

C) 1 1/2 hours

D) 2 hours

E) 3 1/2 hours**D) 2 hours**

Explanation:

Speed of A = 3x, speed of B = 4x

Difference in time to reach destination is 30 min or 1/2 hour

Total distance = ((3x*4x)/(4x – 3x)) * 1/2 = 6x

Time taken by A to travel 6x = 6x/3x = 2 hrs**An alloy contains 2 metals. The first alloy weighs 5 kg in which 1st metal is 1/3rd and the rest is 2nd metal. The second alloy weighs 2 kg in which 1st metal is 1/4th and the rest is 2nd metal. If both alloys are mixed, find the ratio of the weights of 1st metal to 2nd metal in the final mixture?**

A) 13 : 19

B) 13 : 29

C) 20 : 41

D) 19 : 29

E) None of these**B) 13 : 29**

Explanation:

2nd metal in first alloy = 1 – 1/3 = 2/3

2nd metal in second alloy = 1 – 1/4 = 3/4

New ratio = (1/3 * 5 + 1/4 * 2) : (2/3 * 5 + 3/4 * 2)**A completes a piece of work in the same time in which B and C can together do the work. If A and B together complete the work in 10 days and C alone does the work in 50 days, then B alone could do the same work in:**

A) 20 days

B) 22 days

C) 25 days

D) 28 days

E) None of these**C) 25 days**

Explanation:

(A+B+C)’s 1 day’s work: 1/A + 1/B + 1/C = 1/10 + 1/50 = 3/25

Given 1/A = 1/B +1/C

So, 1/A +1/A = 3/25 gives 1/A = 3/50

1/A + 1/B = 1/10, so 1/B = 1/10 – 3/50 = 1/25

So B can do in 25 days**The circumference of the base of a right circular cylinder is 66 cm and curved surface area of the cylinder is 2640 cm**^{2}. Find the volume of this cylinder.

A) 8205 cm^{3}

B) 13960 cm^{3}

C) 9680 cm^{3}

D) 14480 cm^{3}

E) None of these**C) 13860 cm**^{3}

Explanation:

2ᴨr = 66

2ᴨrh = 2640

Find r and h.

Volume = ᴨr^{2}h**A dealer marked an article at 60% above the cost price. At the time of selling he offered a discount of 20% so as to have a profit of 40% on the article. What is his actual profit percent?**

A) 25%

B) 16 2/3%

C) 28%

D) 13 1/3%

E) 18%**C) 28%**

Explanation:

The actual profit% will be 60 – 20 + (60)(-20)/100**12 children can complete a piece of work in 16 days and 8 adults complete the same work in 12 days. 16 adults start the work and after 3 days, 10 of the adults left and in place of them 4 children joined. In how many days the remaining work will be completed?**

A) 10 days

B) 3 days

C) 4 days

D) 8 days

E) 6 days**E) 6 days**

Explanation:

12 c in 16 days, so 1 child in 12*16 days. So 4 children in 12*16/4 = 48 days

8 a in 12 days, so 1 adult in 8*12 days. 16 adults in 8*12/16 = 6 days

16 adults worked for 3 days, so in 3 days they do 1/6 * 3 = 1/2 work

10 adults left, 6 left, 6 adults do in 8*12/6 = 16 days

So 6 adults and 4 children’s 1 day work = 1/16 + 1/48 = 1/12. Let they complete remaining work (1 – 1/2 = 1/2) in x days

So 1/12 * x = 1/2

x = 6**Some men are employed to complete a piece of work in 60 days. But if 8 more men are employed then the same work could be completed in 10 days less. Find the number of men initially employed.**

A) 40 men

B) 42 men

C) 48 men

D) 38 men

E) 32 men**A) 40 men**

Explanation:

Let number of men = x.

8 more men means x + 8, 10 days less means (60 – 10) = 50 days. Then,

M1 * D1 = M2 * D2

x*60 = (x + 8)*50

x = 40 men**8x**^{2}+ 6x = 5, 12y^{2}– 22y + 8 = 0

A) x > y

B) x < y

C) x ≥ y

D) x ≤ y

E) x = y or relationship cannot be determined**(D) x ≤ y**

Explanation:

8x^{2}+ 6x – 5 = 0

8x^{2}+ 10x – 4x – 5 = 0

2x(4x+5) – (4x+5) = 0

x = 1/2 , -5/4

12y^{2}– 22y + 8 = 0

12y^{2}– 16y – 6y +8 = 0

4y(3y-4) – 2(3y-4) = 0

y = 1/2, 4/3

put on number line

-5/4 1/2 4/3**7x + 16y = 75, 6x – 8y = -9**

A) x > y

B) x < y

C) x ≥ y

D) x ≤ y

E) x = y or relationship cannot be determined**(B) x < y**

Explanation:

To solve the equations, multiply 2nd equation by 2, and add both equations:

7x + 16y = 75

12x – 16y = -18

On addition – 19x + 0y = 75-18

Or 19x = 57

x = 3

now put x=3 in any of the equations to find y, y= 27/8

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