Hello Aspirants. Welcome to Online Quant Section in AffairsCloud.com. We are starting **IBPS Clerk course 2015 **and we are creating sample questions in **Quantitative Aptitude** section, type of which will be asked in IBPS Clerk Prelims Exam.

**Stratus – IBPS Clerk Course 2015 **

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**1-5: ** **Study the given table carefully and answer the questions that follow:**

The table given below shows the data of the number of players participated and selected in qualifying rounds for 2015 Youth Tournament from five different regions in five different sports.

**From West region, which game experienced the highest percentage selection?**

A) Swimming

B) Powerlifting

C) Athletics

D) Kabaddi

E) Cycling

**E) Cycling**

Explanation:

Swimming = 22/480 * 100

Powerlifting = 31/490 * 100

Athletics = 13/420 * 100

Kabaddi = 19/480 * 100

Cycling = 28/380 * 100

Find the highest one

**What was the average number of players who participated from all the given regions in Athletics?**

A) 415

B) 605

C) 490

D) 560

E) 536

**E) 536**

Explanation:

800+760+290+420+410 / 5**What is the approximate percentage selection of players from the North region in all the given games together?**

A) 4.35%

B) 5.36%

C) 3.66%

D) 12.48%

E) 16.85%

**A) 4.35%**

Explanation:

Total participated from north region in all games = 2780

Total selected from north region in all games = 121

121/2780 * 100**The ratio of players selected for all the given games together in North-east to that of Central region is**

A) 3 : 5

B) 6 : 5

C) 5 : 6

D) 5 : 3

E) None of these

**D) 5 : 3**

Explanation:

Selected in north east = 41+19+45+23+22

Selected in central = 19+11+11+32+17

150 : 90

**Total number of players got selected from all the given regions together for Cycling is approximately what percent of the total number of players selected from all the given regions together for Swimming?**

A) 74.3%

B) 85.5%

C) 63.6%

D) 92.5%

E) 106.5%

**B) 85.5%**

Explanation:

Selected from cycling = 31+14+17+28+22 = 112

Selected from swimming = 18+31+19+22+41 = 131

112/131 * 100

**18 men complete a piece of work in 10 days. 24 women complete the same piece of work in 12 days. 15 men start the work and complete half of the work, after which they are replaced by 36 women who complete the remaining work. Find the total number of days required to complete the work in this way.**

A) 12 days

B) 15 days

C) 8 days

D) 10 days

E) None of these

**D) 10 days**

Explanation:

18 m – 10 days, so 15 m in 18*10 /15 = 12 days. They complete half of the work, so days required is 1/2 * 12 = 6

Now 24 w in 12 days, so 36 w in 24*12/36 = 8 days. They complete remaining half work. So days = 1/2 * 8 = 4

Total = 10 days

**A bag contains 3 white balls, 5 black balls and 4 yellow balls. 3 balls are drawn at random. What is the probability that exactly one ball is black in color?**

A) 16/33

B) 21/44

C) 11/24

D) 21/220

E) None of these

**B) 21/44**

Explanation:

From 5 black balls, ways for 1 balls is^{5}C_{1}= 5

From w+y balls (7 balls), ways for remaining 2 balls is^{7}C_{2}= 7*6/2*1 = 21

There are a total of 12 balls. Ways for drawing 3 balls is^{12}C_{3}= 12*11*10/3*2*1 = 220

So required prob. = 5*21/220 = 21/44**An article is sold at a profit of Rs 1600 when 1/3rd of it is sold at 3% loss and remaining at 9% profit. Find the cost price of the article.**

A) Rs 40,000

B) Rs 50,000

C) Rs 60,000

D) Rs 32,000

E) None of these

**D) Rs 32,000**

Explanation:

It can be calculated as:

CP = 1600 *100 / [2/3 *9 + 1/3 * (-3)] = 32,000

* 1/3rd sold at 3% loss so negative sign, 2/3rd sold at 9% profit.**The speed of the stream in which the boat is going is 1.5 km/hr. The ratio of the times taken by the boat to go downstream and back upstream is 1 : 4. Find the downstream speed.**

A) 10 km/hr

B) 6 km/hr

C) 4 km/hr

D) 8 km/hr

E) 12 km/hr

**C) 4 km/hr**

Explanation:

Upstream time = 4x, downstream time = x

R = 1.5

So using the formula,

B = [t_{u}+ t_{d}] / [t_{u}– t_{d}] * R

Speed of boat in still water, B = 4x+x/(4x-x) * 1.5 = 2.5 km/hr

So downstream speed = 2.5 + 1.5 = 4 km/hr

**Ratio of A’s age four years ago and B’s age four years ago was 5 : 8. A’s age 6 years after will be 6 less than B’s present age. Find the ratio of the present ages of A and B.**

A) 2 : 3

B) 3 : 4

C) 4 : 5

D) 5: 6

E) None of these

**A) 2 : 3**

Explanation:

4 yrs ago, A-4/B-4 = 5/8

8A – 5B = 12

After 6 yrs, A + 6 = B – 6

Solve the equations, A = 24, B = 36

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