Welcome to Online Quant Section in AffairsCloud.com. We are starting IBPS Clerk course 2015 and we are creating sample questions in Quantitative Aptitude section, type of which will be asked in IBPS Clerk Main Exam.

A cube of side 8 feet is to be painted from outside. The cost of paint is Rs 36.50 per kg. If 16 square feet are covered by 1 kg, then what is the cost of painting the cube?
A) Rs 832
B) Rs 876
C) Rs 782
D) Rs 924
E) Rs 856

Answer & Explanation

B) Rs 876
Explanation:
Surface area of cube = 6a^{2} = 6*8^{2} = 384 sq. feet
So quantity of paint required = (384/16) = 24 kg
So cost of painting = 36.50*24

The students of section A and section B have average weights of 30 kg and 45 kg respectively. Find the average weight of both the sections together such that the number of students in the sections A and B is in the ratio 9 : 1.
A) 34.5 kg
B) 36 kg
C) 33 kg
D) 31.5 kg
E) 32 kg

Answer & Explanation

D) 31.5 kg
Explanation:
Students in A section = 9x, students in B section = x
So total weight of students of A section = 30*9x = 270x
And total weight of students of B section = 45*x = 45x
So average weight of both sections = [(270x+45x)/(9x+x)]

There are 3 machines A, B and C which produce paper sheets. The ratio of the rates of A, B, and C is 3 : 4 : 5. They all produced 400 sheets in which A worked for 6 days, B for 8 days and C worked for 10 days. How many sheets would have been produced if A’s rate get doubled and B’s rate get tripled?
A) 750
B) 728
C) 590
D) 630
E) 910

Answer & Explanation

B) 728
Explanation:
Let their rates be 3x, 4x, 5x resp.
Then 3x*6 + 4x*8 + 5x*10 = 400
Solve, x = 4
Then if A’s rate get doubled and B’s rate get tripled:
A’s becomes 3x*2 = 6x, B’s become = 4x*3 = 12x
So they will produce now – 6x*6 + 12x*8 + 5x*10 = 182x = 182*4

The average of the ages of a man and his only son exceeds the average of the ages of his wife and his son by 25%. The age of his son is 30 years less than the age of his wife whose age is 10 years less than his age. Find the age of his son.
A) 5
B) 10
C) 15
D) 20
E) 25

Answer & Explanation

A) 5
Explanation:
Man, son and wife
[(M+S)/2] = (125/100)* [(W+S)/2]
Also S = W – 30 and W = M – 10
Solve the three equations to find S

P varies directly with the square of Q when R is a constant and inversely with R when Q is constant. When Q = 12 and R = 8, then P = 36. Find P when Q = 24 and R = 16.
A) 96
B) 68
C) 48
D) 72
E) 86

Answer & Explanation

D) 72
Explanation:
Let k be constant of proportionality,
If P directly varies with Q^{2}, then P = k Q^{2}
And if P inversely varies with R, then P = k/R
So in all P = k*Q^{2}/R
When Q = 12 and R = 8, then P = 36
So 36 = k*12^{2}/8
Solve, k = 2
Now when Q = 24 and R = 16,
P = 2*24^{2}/16

x^{2} – 5x + 6 = 0, 2y^{2} – 25y + 63 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relationship cannot be determined

Answer & Explanation

B) x < y
Explanation:
x^{2} – 5x + 6 = 0
Gives x = 2, 3
2y^{2} – 25y + 63 = 0
2y^{2} – 18y – 7y + 63 = 0
Gives y = 7/2, 9
Put on number line
2 3 7/2 9

2x^{2} + 3x – 14 = 0, 3y^{2} – 10y – 25 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relationship cannot be determined

Answer & Explanation

E) x = y or relationship cannot be determined
Explanation:
2x^{2} + 3x – 14 = 0
2x^{2} + 4x – 7x – 14 = 0
Gives x = -7/2, 2
3y^{2} – 10y – 25 = 0
3y^{2} – 15y + 5y – 25 = 0
Gives y = -5/3, 5
Put on number line
-7/2 -5/3 2 5

2x^{2} – x – 3 = 0, 3y^{2} + 8y + 5 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relationship cannot be determined

Answer & Explanation

C) x ≥ y
Explanation:
2x^{2} – x – 3 = 0
2x^{2} + 2x – 3x – 3 = 0
Gives, x = -1, 3/2
3y^{2} + 8y + 5 = 0
3y^{2} + 3y + 5y + 5 = 0
Gives y = -1, -5/3
Put on number line
-5/3 -1 3/2

3x^{2} + 10x – 8 = 0, 6y^{2} – 13y + 6 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relationship cannot be determined

Answer & Explanation

D) x ≤ y
Explanation:
3x^{2} + 10x – 8 = 0
3x^{2} + 12x – 2x – 8 = 0
Gives, x = -4, 2/3
6y^{2} – 13y + 6 = 0
6y^{2} – 9y – 4y + 6 = 0
Gives, y = 2/3, 3/2
Put on number line
-4 2/3 3/2

4x^{2} + 17x – 15 = 0, 3y^{2} + 17y + 10 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relationship cannot be determined

Answer & Explanation

E) x = y or relationship cannot be determined
Explanation:
4x^{2} + 17x – 15 = 0
4x^{2} + 20x – 3x – 15 = 0
Gives, x = -5, 3/4
3y^{2} + 17y + 10 = 0
3y^{2} + 15y + 2y + 10 = 0
Gives, y = -5, -2/3
Put on number line
-5 -2/3 3/4