**Hello Aspirants,**

Welcome to Online Quant Section in AffairsCloud.com. We are starting **IBPS Clerk course 2015 **and we are creating sample questions in **Quantitative Aptitude** section, type of which will be asked in IBPS Clerk Main Exam.

**Stratus – IBPS Clerk Course 2015 **

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**A cube of side 8 feet is to be painted from outside. The cost of paint is Rs 36.50 per kg. If 16 square feet are covered by 1 kg, then what is the cost of painting the cube?**

A) Rs 832

B) Rs 876

C) Rs 782

D) Rs 924

E) Rs 856

**B) Rs 876**

Explanation:

Surface area of cube = 6a^{2}= 6*8^{2}= 384 sq. feet

So quantity of paint required = (384/16) = 24 kg

So cost of painting = 36.50*24**The students of section A and section B have average weights of 30 kg and 45 kg respectively. Find the average weight of both the sections together such that the number of students in the sections A and B is in the ratio 9 : 1.**

A) 34.5 kg

B) 36 kg

C) 33 kg

D) 31.5 kg

E) 32 kg

**D) 31.5 kg**

Explanation:

Students in A section = 9x, students in B section = x

So total weight of students of A section = 30*9x = 270x

And total weight of students of B section = 45*x = 45x

So average weight of both sections = [(270x+45x)/(9x+x)]**There are 3 machines A, B and C which produce paper sheets. The ratio of the rates of A, B, and C is 3 : 4 : 5. They all produced 400 sheets in which A worked for 6 days, B for 8 days and C worked for 10 days. How many sheets would have been produced if A’s rate get doubled and B’s rate get tripled?**

A) 750

B) 728

C) 590

D) 630

E) 910

**B) 728**

Explanation:

Let their rates be 3x, 4x, 5x resp.

Then 3x*6 + 4x*8 + 5x*10 = 400

Solve, x = 4

Then if A’s rate get doubled and B’s rate get tripled:

A’s becomes 3x*2 = 6x, B’s become = 4x*3 = 12x

So they will produce now – 6x*6 + 12x*8 + 5x*10 = 182x = 182*4

**The average of the ages of a man and his only son exceeds the average of the ages of his wife and his son by 25%. The age of his son is 30 years less than the age of his wife whose age is 10 years less than his age. Find the age of his son.**

A) 5

B) 10

C) 15

D) 20

E) 25

**A) 5**

Explanation:

Man, son and wife

[(M+S)/2] = (125/100)* [(W+S)/2]

Also S = W – 30 and W = M – 10

Solve the three equations to find S**P varies directly with the square of Q when R is a constant and inversely with R when Q is constant. When Q = 12 and R = 8, then P = 36. Find P when Q = 24 and R = 16.**

A) 96

B) 68

C) 48

D) 72

E) 86

**D) 72**

Explanation:

Let k be constant of proportionality,

If P directly varies with Q^{2}, then P = k Q^{2}

And if P inversely varies with R, then P = k/R

So in all P = k*Q^{2}/R

When Q = 12 and R = 8, then P = 36

So 36 = k*12^{2}/8

Solve, k = 2

Now when Q = 24 and R = 16,

P = 2*24^{2}/16**x**^{2}– 5x + 6 = 0, 2y^{2}– 25y + 63 = 0

A) x > y

B) x < y

C) x ≥ y

D) x ≤ y

E) x = y or relationship cannot be determined

**B) x < y**

Explanation:

x^{2}– 5x + 6 = 0

Gives x = 2, 3

2y^{2}– 25y + 63 = 0

2y^{2}– 18y – 7y + 63 = 0

Gives y = 7/2, 9

Put on number line

2 3 7/2 9**2x**^{2}+ 3x – 14 = 0, 3y^{2}– 10y – 25 = 0

A) x > y

B) x < y

C) x ≥ y

D) x ≤ y

E) x = y or relationship cannot be determined

**E) x = y or relationship cannot be determined**

Explanation:

2x^{2}+ 3x – 14 = 0

2x^{2}+ 4x – 7x – 14 = 0

Gives x = -7/2, 2

3y^{2}– 10y – 25 = 0

3y^{2}– 15y + 5y – 25 = 0

Gives y = -5/3, 5

Put on number line

-7/2 -5/3 2 5**2x**^{2}– x – 3 = 0, 3y^{2}+ 8y + 5 = 0

A) x > y

B) x < y

C) x ≥ y

D) x ≤ y

E) x = y or relationship cannot be determined

**C) x ≥ y**

Explanation:

2x^{2}– x – 3 = 0

2x^{2}+ 2x – 3x – 3 = 0

Gives, x = -1, 3/2

3y^{2}+ 8y + 5 = 0

3y^{2}+ 3y + 5y + 5 = 0

Gives y = -1, -5/3

Put on number line

-5/3 -1 3/2**3x**^{2}+ 10x – 8 = 0, 6y^{2}– 13y + 6 = 0

A) x > y

B) x < y

C) x ≥ y

D) x ≤ y

E) x = y or relationship cannot be determined

**D) x ≤ y**

Explanation:

3x^{2}+ 10x – 8 = 0

3x^{2}+ 12x – 2x – 8 = 0

Gives, x = -4, 2/3

6y^{2}– 13y + 6 = 0

6y^{2}– 9y – 4y + 6 = 0

Gives, y = 2/3, 3/2

Put on number line

-4 2/3 3/2**4x**^{2}+ 17x – 15 = 0, 3y^{2}+ 17y + 10 = 0

A) x > y

B) x < y

C) x ≥ y

D) x ≤ y

E) x = y or relationship cannot be determined

**E) x = y or relationship cannot be determined**

Explanation:

4x^{2}+ 17x – 15 = 0

4x^{2}+ 20x – 3x – 15 = 0

Gives, x = -5, 3/4

3y^{2}+ 17y + 10 = 0

3y^{2}+ 15y + 2y + 10 = 0

Gives, y = -5, -2/3

Put on number line

-5 -2/3 3/4

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