# IBPS Clerk Main: Quants Day 12

Hello Aspirants,

Welcome to Online Quant Section in AffairsCloud.com. We are starting IBPS Clerk course 2015 and we are creating sample questions in Quantitative Aptitude section, type of which will be asked in IBPS Clerk Main Exam.

Stratus – IBPS Clerk Course 2015 [flipclock]

1. The simple interest obtained on a sum of money after 5 years is Rs 3000. If the principal gets trebled for the next 5 years, what will be the total interest at the end of the 10th year?
A) Rs 10,000
B) Rs 6,000
C) Rs 12,000
D) Rs 10,500
E) Rs 12,500
C) Rs 12,000
Explanation:

Formula –
(n+1) * principal i.e. (3+1) *3000

2. An article is marked 20% above the cost price. The profit gets doubled, when the selling price of an article is increased by 30%. Marked price of an article is given to be Rs 480. What is approximately the original selling price?
A) Rs 470
B) Rs 530
C) Rs 600
D) Rs 570
E) Rs 590
D) Rs 570
Explanation:

MP = 480, and also, MP = (120/100)*CP, so CP = 400
Profit = SP – 400
When SP increase by 30%, profit doubled, so
2*profit = (130/100)*SP – 400
Solve both equations, SP ≈ 570

3. From a cone of height 60 cm, a small cone is cut off at the top of by a plane parallel to its base. The cone cut has a volume equal to 1/64 of the original cone. At what height above the base is the section made?
A) 22 cm
B) 15 cm
C) 18 cm
D) 20 cm
E) 25 cm
B) 15 cm
Explanation:

(1/3*ᴨr12h1)/ (1/3*ᴨr2h) = 1/64
(r1/r)2 * h1/h = 1/64
(h1/h) ^3 = (1/4)^3 ( r1/r = h1/h)
h1 = 1/4 * 60=15

4. Two varieties of wheat worth Rs. 110 per kg and Rs. 95 per kg respectively are mixed with a third variety of wheat in the ratio 1 : 1 : 2. If the obtained mixture is worth Rs. 115 per kg, find the price of the third variety of wheat?
A) Rs 107.5
B) Rs 127.5
C) Rs 125
D) Rs 117.5
E) Rs 130.5
B) Rs 127.5
Explanation:

Mixing 1st two varieties gives average of (110+95)/2 = Rs 102.5 per kg
Now this mixed with 3rd variety in ratio (1+1) : 2 = 1 : 1
102.5 x
. 115
x-115 12.5
(x-115)/12.5 = 1/1
Solve, x = 127.5

5. A bag contains 3 blue balls, 5 yellow balls and 4 green balls. 3 balls are drawn at random. What is the probability that exactly 2 balls are yellow in color?
A) 23/33
B) 7/22
C) 8/22
D) 19/22
E) None of these
B) 7/22
Explanation:
From 5 yellow balls, ways for 2 balls is 5C2 = 10
Other 1 ball is either blue or green, so from 7 blue+green balls, ways for 1 ball is 7C1 = 7
There are a total of 12 balls. Ways for drawing 3 balls is 12C3 = 12*11*10/3*2*1 = 220
So required prob. = (10*7)/220 = 7/22

6. P, Q and R alone can do a certain work in 10, 12, and 15 days respectively. P and Q started the work. After working for 4 days, Q left and R joined. What is the number of days in which P and R can complete the remaining work?
A) 2 1/5 days
B) 2 days
C) 5 days
D) 1 3/5 days
E) 3 days
D) 1 3/5 days
Explanation:

P and Q start the work. Their 1 day’s work = 1/10 + 1/12 = 11/60.
They work for 4 days, so work done by P and Q in 4 days = 4 * (11/60) = 11/15
Q left, Remaining work = 1 – (11/15) = 4/15
(P+R)’s 1 day’s work = 1/10 + 1/15 = 1/6
P+R completes 1 work in 6 days, so 4/15 work in 6 * (4/15) = 8/5

7. A and B have earning is in the ratio 4 : 5. After a year, income of A is increased by 25% and that of B is decreased by 20%, and now the ratio of their earnings becomes 5 : 4. Find the earnings of A.
A) Rs 75,000
B) Rs 55,000
C) Rs 50,000
E) None of these
Explanation:

Let A’s income = 4x, B’s income = 5x
After change – A’s income = 125/100 * 4x = 5x and B’s income = 80/100 * 5x = 4x
So new ratio = 5x : 4x = 5 : 4 which is also given, but it does not give value for x, so data inadequate

8. A right circular cylinder has curved surface area equal to 2640 cm2. If the circumference of its base is 66 cm, then what is the volume of this cylinder?
A) 13720 cm3
B) 23460 cm3
C) 13860 cm3
D) 16544 cm3
E) None of these
C) 13860 cm3
Explanation:

2ᴨr = 66
2ᴨrh = 2640
Divide the equations, find r and h.
Volume = ᴨr2h

9. A train starts from point P at 8:00 AM with speed 25 km/hr. Another train starts from point Q at 9:00 AM at 30 km/hr in the opposite direction of the first one. If the distance PQ is 300 km, at what time will they meet?
A) 1: 00 AM
B) 2:00 PM
C) 11:30 AM
D) 12:30 PM
E) 1:30 PM
B) 2:00 PM
Explanation:

Distance is 300 km
Speed of first = 25 km/hr, so after 1 hr, i.e. at 9:00 AM, the first has covered 25 km.
The distance left = (300 – 25) km = 275 km. relative speed = 25 + 30 = 55
So time they will meet at = 9:00 AM + 275 / 55
= 9:00 AM + 5 hrs = 2:00 PM

10. Ratio of P’s age four years ago and Q’s age that time was 5 : 8. P’s age 6 years after will be 6 less than Q’s present age. Find the ratio of the present ages of P and Q.
A) 2 : 3
B) 3 : 2
C) 5 : 3
D) 3 : 8
E) 3 : 4
A) 2 : 3
Explanation:

4 yrs ago, (P-4)/(Q-4) = 5/8
Solve, 8P – 5Q = 12
After 6 yrs, P + 6 = Q – 6
Solve the equations, P = 24, Q = 36

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