**Hello Aspirants,**

Welcome to Online Quant Section in AffairsCloud.com. We are starting **IBPS Clerk course 2015 **and we are creating sample questions in **Quantitative Aptitude** section, type of which will be asked in IBPS Clerk Main Exam.

**Stratus – IBPS Clerk Course 2015 **

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**The simple interest obtained on a sum of money after 5 years is Rs 3000. If the principal gets trebled for the next 5 years, what will be the total interest at the end of the 10th year?**

A) Rs 10,000

B) Rs 6,000

C) Rs 12,000

D) Rs 10,500

E) Rs 12,500**C) Rs 12,000**

Explanation:

Formula –

(n+1) * principal i.e. (3+1) *3000**An article is marked 20% above the cost price. The profit gets doubled, when the selling price of an article is increased by 30%. Marked price of an article is given to be Rs 480. What is approximately the original selling price?**

A) Rs 470

B) Rs 530

C) Rs 600

D) Rs 570

E) Rs 590**D) Rs 570**

Explanation:

MP = 480, and also, MP = (120/100)*CP, so CP = 400

Profit = SP – 400

When SP increase by 30%, profit doubled, so

2*profit = (130/100)*SP – 400

Solve both equations, SP ≈ 570**From a cone of height 60 cm, a small cone is cut off at the top of by a plane parallel to its base. The cone cut has a volume equal to 1/64 of the original cone. At what height above the base is the section made?**

A) 22 cm

B) 15 cm

C) 18 cm

D) 20 cm

E) 25 cm**B) 15 cm**

Explanation:

(1/3*ᴨr1^{2}h1)/ (1/3*ᴨr^{2}h) = 1/64

(r1/r)^{2}* h1/h = 1/64

(h1/h) ^3 = (1/4)^3 ( r1/r = h1/h)

h1 = 1/4 * 60=15**Two varieties of wheat worth Rs. 110 per kg and Rs. 95 per kg respectively are mixed with a third variety of wheat in the ratio 1 : 1 : 2. If the obtained mixture is worth Rs. 115 per kg, find the price of the third variety of wheat?**

A) Rs 107.5

B) Rs 127.5

C) Rs 125

D) Rs 117.5

E) Rs 130.5**B) Rs 127.5**

Explanation:

Mixing 1st two varieties gives average of (110+95)/2 = Rs 102.5 per kg

Now this mixed with 3rd variety in ratio (1+1) : 2 = 1 : 1

102.5 x

. 115

x-115 12.5

(x-115)/12.5 = 1/1

Solve, x = 127.5**A bag contains 3 blue balls, 5 yellow balls and 4 green balls. 3 balls are drawn at random. What is the probability that exactly 2 balls are yellow in color?**

A) 23/33

B) 7/22

C) 8/22

D) 19/22

E) None of these**B) 7/22**

Explanation:

From 5 yellow balls, ways for 2 balls is^{5}C_{2}= 10

Other 1 ball is either blue or green, so from 7 blue+green balls, ways for 1 ball is^{7}C_{1}= 7

There are a total of 12 balls. Ways for drawing 3 balls is^{12}C_{3}= 12*11*10/3*2*1 = 220

So required prob. = (10*7)/220 = 7/22**P, Q and R alone can do a certain work in 10, 12, and 15 days respectively. P and Q started the work. After working for 4 days, Q left and R joined. What is the number of days in which P and R can complete the remaining work?**

A) 2 1/5 days

B) 2 days

C) 5 days

D) 1 3/5 days

E) 3 days**D) 1 3/5 days**

Explanation:

P and Q start the work. Their 1 day’s work = 1/10 + 1/12 = 11/60.

They work for 4 days, so work done by P and Q in 4 days = 4 * (11/60) = 11/15

Q left, Remaining work = 1 – (11/15) = 4/15

(P+R)’s 1 day’s work = 1/10 + 1/15 = 1/6

P+R completes 1 work in 6 days, so 4/15 work in 6 * (4/15) = 8/5**A and B have earning is in the ratio 4 : 5. After a year, income of A is increased by 25% and that of B is decreased by 20%, and now the ratio of their earnings becomes 5 : 4. Find the earnings of A.**

A) Rs 75,000

B) Rs 55,000

C) Rs 50,000

D) Data inadequate

E) None of these**D) Data inadequate**

Explanation:

Let A’s income = 4x, B’s income = 5x

After change – A’s income = 125/100 * 4x = 5x and B’s income = 80/100 * 5x = 4x

So new ratio = 5x : 4x = 5 : 4 which is also given, but it does not give value for x, so data inadequate**A right circular cylinder has curved surface area equal to 2640 cm**^{2}. If the circumference of its base is 66 cm, then what is the volume of this cylinder?

A) 13720 cm^{3}

B) 23460 cm^{3}

C) 13860 cm^{3}

D) 16544 cm^{3}

E) None of these**C) 13860 cm**^{3}

Explanation:

2ᴨr = 66

2ᴨrh = 2640

Divide the equations, find r and h.

Volume = ᴨr^{2}h**A train starts from point P at 8:00 AM with speed 25 km/hr. Another train starts from point Q at 9:00 AM at 30 km/hr in the opposite direction of the first one. If the distance PQ is 300 km, at what time will they meet?**

A) 1: 00 AM

B) 2:00 PM

C) 11:30 AM

D) 12:30 PM

E) 1:30 PM**B) 2:00 PM**

Explanation:

Distance is 300 km

Speed of first = 25 km/hr, so after 1 hr, i.e. at 9:00 AM, the first has covered 25 km.

The distance left = (300 – 25) km = 275 km. relative speed = 25 + 30 = 55

So time they will meet at = 9:00 AM + 275 / 55

= 9:00 AM + 5 hrs = 2:00 PM**Ratio of P’s age four years ago and Q’s age that time was 5 : 8. P’s age 6 years after will be 6 less than Q’s present age. Find the ratio of the present ages of P and Q.**

A) 2 : 3

B) 3 : 2

C) 5 : 3

D) 3 : 8

E) 3 : 4**A) 2 : 3**

Explanation:

4 yrs ago, (P-4)/(Q-4) = 5/8

Solve, 8P – 5Q = 12

After 6 yrs, P + 6 = Q – 6

Solve the equations, P = 24, Q = 36

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