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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

Amit’s age eight years ago was equal to twice of Beaula’s age two years ago. Chand is six years older than Beaula. If the ratio of the present ages of Amit to that of Chand is 8:5, then what is Beaula’s present age?

Correct

Answer – 5)14
Explanation:
Let the present age of Amit, Beaula, Chand be X,Y,Z years respectively
Amit = X, Beaula = Y , Chand =Z=(Y+6)
(X-8)=2(Y-2)
X= 2Y + 4
(X)/(Y+6) = 8/5
(2y+4)/(Y+6)= 8/5
Y= 24-10= 14 years

Incorrect

Answer – 5)14
Explanation:
Let the present age of Amit, Beaula, Chand be X,Y,Z years respectively
Amit = X, Beaula = Y , Chand =Z=(Y+6)
(X-8)=2(Y-2)
X= 2Y + 4
(X)/(Y+6) = 8/5
(2y+4)/(Y+6)= 8/5
Y= 24-10= 14 years

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

Rosy & Sharmi spent 60% and 75% of their respective monthly salaries. Sharmi kept 60% of the remaining in savings and gave the remaining Rs 2100 to her sister. What was Rosy’s monthly expenditure if her monthly salary was 25% less than that of Sharmi?

Correct

Answer – 1) 9450
Explanation:
Let Sharmi’s salary – Rs 100
Remaining after expenditure = 25
Sharmi’s savings = 60 % of 25 = 15
She gave 10% to her sister
10 ⟹2100
100= 21000
Rosy’s salary = 75% of 21000 = Rs 15750
Rosy’s expenditure = 60% of 15750 = Rs 9450

Incorrect

Answer – 1) 9450
Explanation:
Let Sharmi’s salary – Rs 100
Remaining after expenditure = 25
Sharmi’s savings = 60 % of 25 = 15
She gave 10% to her sister
10 ⟹2100
100= 21000
Rosy’s salary = 75% of 21000 = Rs 15750
Rosy’s expenditure = 60% of 15750 = Rs 9450

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

Ajay and Banu started a business. Banu’s investment was Rs 4000 more than that of Ajay. At the end of 8 months from the start of the business, Banu left & Chitra joined with an investment which was Rs 6000 more than that of Ajay. If the ratio of the total annual profit to Banu’s share in profit was 11:5, then what was the investment made by Ajay?

Population of city A is 20% more than population of city B. Population of city C is 40% more than A. If the difference between population of cities B & C is 1122 , what is the population of city A?

Correct

Answer – 3) 1980
Explanation:
Let the population of city B= X
Population of city A = X * (120/100)
Population of city C = 120/100 * 140/100
120/X * 140/X – X = 1122
X = 1650
Hence Population of city A = 1650 * ( 120/100) = 1980

Incorrect

Answer – 3) 1980
Explanation:
Let the population of city B= X
Population of city A = X * (120/100)
Population of city C = 120/100 * 140/100
120/X * 140/X – X = 1122
X = 1650
Hence Population of city A = 1650 * ( 120/100) = 1980

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

A truck takes 5 hours to travel from point P to Q. It would have taken 6 hours. If the same truck had travelled the same distance at a speed which was 15 kmph less than its original speed. What is the distance between points P & Q?

Correct

Answer – 3) 450 km
Explanation:
Let the distance between P & Q = X km
X/5-X/6= 15
X = 450 km

Incorrect

Answer – 3) 450 km
Explanation:
Let the distance between P & Q = X km
X/5-X/6= 15
X = 450 km

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

A vendor bought a mobile after getting a discount of 30% on the marked price(MP). He sold the mobile to customer for Rs 4536 and earned a profit of 20% on his cost price(CP). What was the initial price of the mobile?

Correct

Answer – 4) 5400
Explanation:
Let the initial marked price of the mobile = Rs X
4536= X * 70/100 * 120/100
X= 5400

Incorrect

Answer – 4) 5400
Explanation:
Let the initial marked price of the mobile = Rs X
4536= X * 70/100 * 120/100
X= 5400

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

3/4th of one number is equal to 3/5th of the second number. If the difference between both the numbers is 105, then what is 20% of the second number.

Correct

Answer – 5) 105
Explanation:
Let the first number = X
Second number = Y
3/4 X= 3/5 Y
Y= 5/4 X
Y-X= 105
5/4 X- X=105
X = 420; Y = 525
20% of Y = 525 * (20/100) = 105

Incorrect

Answer – 5) 105
Explanation:
Let the first number = X
Second number = Y
3/4 X= 3/5 Y
Y= 5/4 X
Y-X= 105
5/4 X- X=105
X = 420; Y = 525
20% of Y = 525 * (20/100) = 105

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

If the SI on Rs 3200 for 2 years at the rate of X% per annum is Rs 832. What would be the simple interest on Rs 4400 for 3 years at the rate of (X+4)% per annum

A cistern has a capacity of 120 litre and has two inlets P and Q. When both the inlets were opened simultaneously for 3 hours, they were able to fill 35 litre water in the cistern. If inlet P alone can fill the empty cistern completely in 24 years. How many hours will inlet Q take to fill the empty cistern completely?

Correct

Answer – 4) 18 hours
Explanation:
Cistern filled by P in 1 hour = 120/24 = 5 litre
Cistern filled by (P+Q) in 1 hour = 35/3 litre
Cistern filled by Q in 1 hour = 35/3-5 = 20/3 litre
Time taken by Q to fill the cistern completely = 120 /(20/3) = 18 hours

Incorrect

Answer – 4) 18 hours
Explanation:
Cistern filled by P in 1 hour = 120/24 = 5 litre
Cistern filled by (P+Q) in 1 hour = 35/3 litre
Cistern filled by Q in 1 hour = 35/3-5 = 20/3 litre
Time taken by Q to fill the cistern completely = 120 /(20/3) = 18 hours

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

There are total 240 players(boys + girls) in a school who opted for either Hockey or Tennis. 100 players(boys + girls) opted for Hockey. Number of boys who opted for Tennis was 106 more than those of girls. If the respective ratio between total number of boys and that of girls was 2 : 1, how many girls opted for Hockey?

Correct

Answer – 4) 63
Explanation:
Out of 240 players, Number of boys = 2/3 * 240 = 160
Number of girls = 80
Players who opted for Tennis = 240-100 = 140
Girls who opted for Tennis = (140-106)/2 = 17
Boys who opted for Hockey = 160-123 = 37
Girls who opted for Hockey = 100-37 = 63

Incorrect

Answer – 4) 63
Explanation:
Out of 240 players, Number of boys = 2/3 * 240 = 160
Number of girls = 80
Players who opted for Tennis = 240-100 = 140
Girls who opted for Tennis = (140-106)/2 = 17
Boys who opted for Hockey = 160-123 = 37
Girls who opted for Hockey = 100-37 = 63

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