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 Quantitative Aptitude 0%

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Question 1 of 10
1. Question
1 pointsCategory: Quantitative Aptitude5 years hence the respective ratio of Arun’s and Bala’ age will be 7 :5 and that of Bala’s and Chitra’s age will be 10:9. 10 years ago, if the sum of Arun’s and Chitra’s age was 62 years, what is Bala’s present age?(in years)
Correct
Answer – 5) 35
Explanation:
Sum of the present ages of Arun & Chitra is (62+20)=82 years
5 years hence ,
Arun:Bala=7:5=14:10
Bala:Chitra=10:9
Arun:Bala:Chitra=14:10:9
14X+9X10=82
X=4
Bala’s present age = 10X5=(10 *45) =35 yearsIncorrect
Answer – 5) 35
Explanation:
Sum of the present ages of Arun & Chitra is (62+20)=82 years
5 years hence ,
Arun:Bala=7:5=14:10
Bala:Chitra=10:9
Arun:Bala:Chitra=14:10:9
14X+9X10=82
X=4
Bala’s present age = 10X5=(10 *45) =35 years 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeArun and Bala started a business by investing Rs X & Rs (X+3000) respectively. After 9 months from the start of the business, Bala left. If the respective ratio in Arun’s share and Bala’s share in annual profit is 8:9, what is the value of (X+3000)?
Correct
Answer – 4) 9000
Explanation:
12X/(X+3000) *9 = 8/9
X=6000
X+3000 = 9000Incorrect
Answer – 4) 9000
Explanation:
12X/(X+3000) *9 = 8/9
X=6000
X+3000 = 9000 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative Aptitude17 25 16 80 55 ?
Correct
Answer – 2) 271
Explanation:
17 + 2^3 = 25
25 – 3^2 = 16
16 + 4^3 = 80
80 – 5^2 = 55
55 + 6^3 = 271Incorrect
Answer – 2) 271
Explanation:
17 + 2^3 = 25
25 – 3^2 = 16
16 + 4^3 = 80
80 – 5^2 = 55
55 + 6^3 = 271 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeThree numbers are given. The average of first and the second number is greater than the average of the second and the third number by 28. If the respective ratio of first and third number is 9 : 2, what is the third number?
Correct
Answer – 3) 16
Explanation:
Let the numbers be a,b & c
(a+b)/2 –(b+c)/=28
ac= 56
a:c= 9:2
9X2X= 56
X=8
Third number =2X=2*8=16Incorrect
Answer – 3) 16
Explanation:
Let the numbers be a,b & c
(a+b)/2 –(b+c)/=28
ac= 56
a:c= 9:2
9X2X= 56
X=8
Third number =2X=2*8=16 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeA train can cross an electric pole in 12 seconds. Had the length of the train been 80 metre less, it could have crossed 500 m long platform in 28 seconds. What is the length of the train?
Correct
Answer – 4) 315 m
Explanation:
length of the train = X m
Speed of train = X/12
(X80)+ 500=X/12 *28
X=315 mIncorrect
Answer – 4) 315 m
Explanation:
length of the train = X m
Speed of train = X/12
(X80)+ 500=X/12 *28
X=315 m 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeThe respective ratio of speed of a boat downstream and speed of water current is 5:2. If the boat can travel 12.6 km in 84 minutes downstream, what is the speed of water current? (in kmph)
Correct
Answer – 3) 3.6 kmph
Explanation:
Rate of downstream of boat = (126 *60)/84 = 9 kmph
Speed of current =9/5 * 2 =3.6 kmphIncorrect
Answer – 3) 3.6 kmph
Explanation:
Rate of downstream of boat = (126 *60)/84 = 9 kmph
Speed of current =9/5 * 2 =3.6 kmph 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeThe population of city B was 2400 in 2013. It increased by 10% from 2013 to 2014 and by a certain percent from 2014 to 2015. If the population of city B was 3036 in 2015, what was the percent increase in population from 2014 to 2015?
Correct
Answer – 4) 15%
Explanation:
Rate of increase in population during 20142015 =%
2400 *110/100* (1+X/100)=3036
X=15%Incorrect
Answer – 4) 15%
Explanation:
Rate of increase in population during 20142015 =%
2400 *110/100* (1+X/100)=3036
X=15% 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeIf the percentage profit is equal to the labeled price and when the watch is sold for hundred rupees more than the labeled price, the percentage profit is increased by 5%. Find the labeled price of the watch?
Correct
Answer – 1) 2000
Explanation:
Labeled price be Rs X
Selling price =X + 100
X + 100= (105X)/100
X=2000Incorrect
Answer – 1) 2000
Explanation:
Labeled price be Rs X
Selling price =X + 100
X + 100= (105X)/100
X=2000 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative Aptitude6 men and 6 children together can complete a piece of work in 6 days . In how many days can 15 men alone complete the same work if 9 children alone can complete it in 10 days?
Correct
Answer – 5) 4
Explanation:
9 children→ 10 days .
6 children can complete the work in (10 *9)/6=15 days
6 children in 6 days → 6/15=2/5 part
The remaining part =3/5 will be completed by 6 men in 6 days
6 men’s work in 1 day = 3 * (5 *6)=1/10 part
6 men can complete the work in 10 days
15 men can complete the work in (6 *10)/15=4 daysIncorrect
Answer – 5) 4
Explanation:
9 children→ 10 days .
6 children can complete the work in (10 *9)/6=15 days
6 children in 6 days → 6/15=2/5 part
The remaining part =3/5 will be completed by 6 men in 6 days
6 men’s work in 1 day = 3 * (5 *6)=1/10 part
6 men can complete the work in 10 days
15 men can complete the work in (6 *10)/15=4 days 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeThe average age of A, B and C is 22 years. 3 years ago the average age of B and C is 18 years. Find the age of A, 9 years hence.
Correct
Answer – 4) 33
Explanation:
A + B + C = 66
B + C = 18 * 2 = 36(3 years ago)
Present age of B + C = 36 + 6 = 42
A = 6642 = 24
Age of A after 9 years = 33Incorrect
Answer – 4) 33
Explanation:
A + B + C = 66
B + C = 18 * 2 = 36(3 years ago)
Present age of B + C = 36 + 6 = 42
A = 6642 = 24
Age of A after 9 years = 33  Click view Questions button to view Explanation
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