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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeWhat will be the cost of fencing of a circular ground?
I. The area of the circular ground is 1386 sq m
II. The cost of fencing is Rs 28 per metreCorrect
Answer – 5) If the data in both statement I & II together are necessary to answer the question.
Explanation:
From I & II Area of the circular ground = p.r.r=1386
r=21
Perimeter of circular ground = 2 p r= 924 m
Cost of fencing the circular ground = 924 * 28 = 25872Incorrect
Answer – 5) If the data in both statement I & II together are necessary to answer the question.
Explanation:
From I & II Area of the circular ground = p.r.r=1386
r=21
Perimeter of circular ground = 2 p r= 924 m
Cost of fencing the circular ground = 924 * 28 = 25872 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative Aptitude6, 8, 12, 42, 160, ?
Correct
Answer – 5) 810
Explanation :
6 * 1 + 2 = 8
8 * 2 – 4 = 12
12 * 3 + 6 = 42
42 * 4 – 8 = 160
160 * 5 + 10 = 810Incorrect
Answer – 5) 810
Explanation :
6 * 1 + 2 = 8
8 * 2 – 4 = 12
12 * 3 + 6 = 42
42 * 4 – 8 = 160
160 * 5 + 10 = 810 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeFive years ago, Ajay’s age was three times that of Banu. Ten years ago, Ajay’s age was half that of Ritesh. Ritesh’s present age is 36 years.
Quantity I : Banu’s present age
Quantity II : Ajay’s present ageCorrect
Answer – 2) Quantity I < Quantity II
Explanation:
Ajay’s present age = (3610)/2 + 10 =23
Banu’s present age = (235)/3 + 5 = 11Incorrect
Answer – 2) Quantity I < Quantity II
Explanation:
Ajay’s present age = (3610)/2 + 10 =23
Banu’s present age = (235)/3 + 5 = 11 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative Aptitude5/9 of 503.8 + 3/8 of 639.9 = ?
Correct
Answer – 3) 520
Explanation :
5/9 of 504 = 280 ; 3/8 of 640 = 240 => 280 + 240 = 520Incorrect
Answer – 3) 520
Explanation :
5/9 of 504 = 280 ; 3/8 of 640 = 240 => 280 + 240 = 520 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeSharmi starts from Pune and Ritesh starts from Mumbai to meet each other. The Speed of Sharmi is 37 kmph, while the speed of Ritesh is 41 kmph. If the distance between Pune and Mumbai be 234 km and both Sharmi and Ritesh start their journey at the same time, when they will meet?
Correct
Answer – 5) 3 hours later
Explanation:
234 = (37+41)*t
t =3Incorrect
Answer – 5) 3 hours later
Explanation:
234 = (37+41)*t
t =3 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeFind the wrong number in the series given below
3 17 72 220 452 462Correct
Answer – 2) 220
Explanation :
3 * 5 + 2 = 17
17 * 4 + 4 = 72
72 * 3 + 6 = 222
222 * 2 + 8 = 452
452 * 1 + 10 = 462Incorrect
Answer – 2) 220
Explanation :
3 * 5 + 2 = 17
17 * 4 + 4 = 72
72 * 3 + 6 = 222
222 * 2 + 8 = 452
452 * 1 + 10 = 462 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeA cistern has one inlet, L and one inlet, M. L takes 5 hours to fill the empty tank, when M is not open and M takes 8 hours to empty the full tank, if the tank is two fifth full, how much time will it take to fill the tank completely when both L and M are opened simultaneously? (in hours)
Correct
Answer – 4) 8 hours
Explanation:
If the tank is 2/5th full, then remaining empty tank will be = 12/5=3/5th
L and M can fill the empty tank in = (5*8)/(85)=40/3 hours
Then 3/5 th tank fill in =40/3 * 3/5= 8 hoursIncorrect
Answer – 4) 8 hours
Explanation:
If the tank is 2/5th full, then remaining empty tank will be = 12/5=3/5th
L and M can fill the empty tank in = (5*8)/(85)=40/3 hours
Then 3/5 th tank fill in =40/3 * 3/5= 8 hours 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeThe average age of Hari, his wife and their two children is 23 years. His wife is just 4 years younger than Hari and his wife was 20 years old when their daughter was born. He was 28 years old when their son was born. What is the sum of the age of Hari and his daughter is?
Correct
Answer – 4) 50 years
Explanation:
H+W+S+D/4 = 23
H= W+4
D =W20 = H24
S = H28
H+H4+H24+H28/4 = 23
H =37 D =13
H + D = 50Incorrect
Answer – 4) 50 years
Explanation:
H+W+S+D/4 = 23
H= W+4
D =W20 = H24
S = H28
H+H4+H24+H28/4 = 23
H =37 D =13
H + D = 50 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeRithika had Rs 8000. She invested some of it in savings scheme P and the rest of the money in savings scheme Q. She invested for 3 years in savings scheme P and for 2 years in savings scheme Q. savings scheme P offers SI at a rate of 20% pa while savings scheme Q compounded annually at the rate of 30% pa. The interest received from savings scheme P is 930 more than the interest received from savings scheme Q. If Rs 1500 is debited from the invested amount of savings scheme P then find the difference between the amount invested by Rithika in savings scheme P & savings scheme Q.
Correct
Answer – 4) Rs 500
Explanation:
Amount invested in savings scheme P= Rs X
Amount invested in savings scheme Q= Rs (8000X)
Compounding 30 % for 2 years , rate
30+30+ (30*30)/100= 69 %
60 % of X 69 % of (8000X)=930
X= 5000
In savings savings scheme Q = 80005000=3000
5000 – 1500 = 3500
Difference =35003000=Rs 500Incorrect
Answer – 4) Rs 500
Explanation:
Amount invested in savings scheme P= Rs X
Amount invested in savings scheme Q= Rs (8000X)
Compounding 30 % for 2 years , rate
30+30+ (30*30)/100= 69 %
60 % of X 69 % of (8000X)=930
X= 5000
In savings savings scheme Q = 80005000=3000
5000 – 1500 = 3500
Difference =35003000=Rs 500 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeThe Simple Interest(SI) for 16 years on an amount at particular rate is Rs 10000. If the principal is doubled at an interval of every 4 years and the rate is tripled at every such interval, find the new Simple Interest(SI)
Correct
Answer – 4) 647500
Explanation:
Let New SI be X
10000/16 = X/4(1*1+2*3+4*9+8*27)
10000/16=X/4(1+6+36+216)
X=647500Incorrect
Answer – 4) 647500
Explanation:
Let New SI be X
10000/16 = X/4(1*1+2*3+4*9+8*27)
10000/16=X/4(1+6+36+216)
X=647500
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