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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

Vivek, Daniel, Samuel are three partners. They all together invested Rs 140000 in a business for a year. At the end of year Vivek, Daniel and Samuel got Rs 3375, Rs 1125 and Rs 6750 Profit respectively.
Quantity I: The sum of the investments of Vivek & Daniel
Quantity II: The difference between the investments of Vivek & Samuel

Correct

Answer – 1) Quantity I > Quantity II
Explanation:
3375:1125:6750
Ratio : 3:1:6
Vivek’s Investment = 42000
Daniel’s Investment = 16000
Samuel’s Investment = 84000
From I
Investment of Vivek & Daniel =42000 + 16000 = 58000
From II
Difference of Investment of Vivek & Samuel =84000-42000=42000
Hence Quantity I > Quantity II

Incorrect

Answer – 1) Quantity I > Quantity II
Explanation:
3375:1125:6750
Ratio : 3:1:6
Vivek’s Investment = 42000
Daniel’s Investment = 16000
Samuel’s Investment = 84000
From I
Investment of Vivek & Daniel =42000 + 16000 = 58000
From II
Difference of Investment of Vivek & Samuel =84000-42000=42000
Hence Quantity I > Quantity II

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

There are 5 Pink bowls, 4 Purple bowls and 3 Brown bowls in a basket. Four bowls are chosen at random.
Quantity I: The probability of being 2 Pink and 2 Purple bowl
Quantity II: The probability of being 2 Pink, 1 Purple & 1 Brown.

Correct

Answer – 2) Quantity I < Quantity II
Explanation:
I) (5c2 * 4c2)/12c4 = 60/495=4/33
II) (5c2 * 4c1 *3c1)/12c4 =120/95=8/33
Hence Quantity I < Quantity II

Incorrect

Answer – 2) Quantity I < Quantity II
Explanation:
I) (5c2 * 4c2)/12c4 = 60/495=4/33
II) (5c2 * 4c1 *3c1)/12c4 =120/95=8/33
Hence Quantity I < Quantity II

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

Five years ago, Mano’s age was three times that of Bharat. Ten years ago, Mano’s age was half that of Richard. Richard’s present age is 36 years.
Quantity I: Bharat’s current age
Quantity II: Difference between Richard’s age and Mano’s age

Correct

Answer – 2) Quantity I < Quantity II
Explanation:
Mano’s present age = (36-10)/2 + 10 = 23
Bharat’s present age = (23-5)/3 + 5 = 11
Difference between Richard’s age & Mano’s age =36-23=13
Hence Quantity I < Quantity II

Incorrect

Answer – 2) Quantity I < Quantity II
Explanation:
Mano’s present age = (36-10)/2 + 10 = 23
Bharat’s present age = (23-5)/3 + 5 = 11
Difference between Richard’s age & Mano’s age =36-23=13
Hence Quantity I < Quantity II

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

Find the sum of the last three positive consecutive odd numbers
I) The average of four consecutive odd numbers is 30
II) The difference between the highest positive odd number and the lowest positive odd number is 6

Correct

Answer – 1) The data in statement I alone are sufficient to answer the question, while the data in statement II alone are not sufficient to answer the question.
Explanation:
From I
Let the first odd number X
Then (X+X+2+X+4+X+6)/4=30
X=27
Four consecutive number =27,29,31,33
The sum of the last three consecutive numbers = 29+31+33 = 93

Incorrect

Answer – 1) The data in statement I alone are sufficient to answer the question, while the data in statement II alone are not sufficient to answer the question.
Explanation:
From I
Let the first odd number X
Then (X+X+2+X+4+X+6)/4=30
X=27
Four consecutive number =27,29,31,33
The sum of the last three consecutive numbers = 29+31+33 = 93

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

Mumbai Mail leaves Chennai at 5 pm for Pune. At what time will it reach Pune?
I) It maintains the average speed of 120 kmph
II) It has three stoppage of 10 minutes each between Chennai & Pune
III) It covers 350 Km before each stoppage.

Correct

Answer – 4) All I,II and III are required
Explanation:
From II & III
Total distance =350 km; 3x= 1050 km
From I
Average speed =120 kmph
So From I,II, III
Time = Distance/speed =1050/120= 8 hours 45 minutes
So the train will reach Pune at 5 pm + 8 hours 45 minutes

Incorrect

Answer – 4) All I,II and III are required
Explanation:
From II & III
Total distance =350 km; 3x= 1050 km
From I
Average speed =120 kmph
So From I,II, III
Time = Distance/speed =1050/120= 8 hours 45 minutes
So the train will reach Pune at 5 pm + 8 hours 45 minutes

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

What was the percentage discount offered by the seller for selling a T-Shirt?
I) Profit earned by selling the T-Shirt for Rs 432 after giving discount was Rs 32.
II) Had there been no discount, the profit earned would have been Rs 80.
III) Had there been no discount, the profit earned would have been 20%.

Correct

Answer – 4) I & Either II or III only
Explanation:
From I CP=400
From I & II, MP = 480 Discount = 48
So % discount = (48*100)/480=10%
From I & III
% Profit without discount = 20%
20% of 400= 80

Incorrect

Answer – 4) I & Either II or III only
Explanation:
From I CP=400
From I & II, MP = 480 Discount = 48
So % discount = (48*100)/480=10%
From I & III
% Profit without discount = 20%
20% of 400= 80

Mr. Mahesh invested Rs X in SI at a rate of interest of 15% for 5 years then he invested X+600 at CI at 10% rate for 2 years. The total interest obtained in 2 years is Rs 5310. Find the amount (in Rs) invested by Mahesh in CI.

At 10% less than usual speed in still water, Mr. Suresh covers 110 km downstream in 5 hrs. If Suresh’s usual speed in still water is 400% more than the stream’s speed, in what time will he cover 144 km upstream at his usual speed?

Correct

Answer – 5) 9 hours
Explanation:
Let the speed of stream be X
Usual speed = X + 400% of X =5X
10% less speed than the usual speed = 5x-5x * (10/100)=4.5X
Downstream speed = 4.5X + X = 22
X=4
Upstream speed = 5X-x= 4X=4 * 4= 16 kmph
Time =144/16= 9

Incorrect

Answer – 5) 9 hours
Explanation:
Let the speed of stream be X
Usual speed = X + 400% of X =5X
10% less speed than the usual speed = 5x-5x * (10/100)=4.5X
Downstream speed = 4.5X + X = 22
X=4
Upstream speed = 5X-x= 4X=4 * 4= 16 kmph
Time =144/16= 9

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