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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeDirections.Q(15) Read the following bar diagram carefully and answer the questions given below it.
Number of competitions conducted by 5 Schools(A,B,C,D and E) during 2 given years:
The number of competitions conducted by School C in 2018 was 150% of the number of competitions conducted by it in 2015 and number of competitions conducted by School D in 2018 was 60% of the number of competitions conducted by it in 2015. The number of competitions conducted by School A in 2018 was 120% of the number of competitions conducted by it in 2015 and number of competitions conducted by School B in 2018 was 80% of the number of competitions conducted by it in 2015. What is the sum of the number of competitions conducted by A, B, C and D together in 2018?
Correct
Answer – 4) 1506
Explanation:
A – 120/100 * 390 = 468
B – 80/100 * 360 = 288
C – 150/100 * 360 = 540
D – 60/100 * 350 = 210
468 + 288 + 540 + 210 = 1506Incorrect
Answer – 4) 1506
Explanation:
A – 120/100 * 390 = 468
B – 80/100 * 360 = 288
C – 150/100 * 360 = 540
D – 60/100 * 350 = 210
468 + 288 + 540 + 210 = 1506 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeDirections.Q(15) Read the following bar diagram carefully and answer the questions given below it.
Number of competitions conducted by 5 Schools(A,B,C,D and E) during 2 given years:
The number of competitions conducted by School E increased by what % from 2015 to 2016?
Correct
Answer – 2) 72(2/9)
Explanation:
310 – 180 /180 * 100 = 72(2/9)Incorrect
Answer – 2) 72(2/9)
Explanation:
310 – 180 /180 * 100 = 72(2/9) 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeDirections.Q(15) Read the following bar diagram carefully and answer the questions given below it.
Number of competitions conducted by 5 Schools(A,B,C,D and E) during 2 given years:
The number of competitions conducted by Schools C and D increased by 25% and 16% respectively from 2016 to 2017. What was the difference between the number of competitions conducted by Schools C and D in 2017?
Correct
Answer – 4) 68
Explanation:
= 240 * 125/100 – 200 * 116/100
= 300 – 232 =68Incorrect
Answer – 4) 68
Explanation:
= 240 * 125/100 – 200 * 116/100
= 300 – 232 =68 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeDirections.Q(15) Read the following bar diagram carefully and answer the questions given below it.
Number of competitions conducted by 5 Schools(A,B,C,D and E) during 2 given years:
Combining the years 2015 and 2016, 58% of the total number of competitions conducted by School A was nonacademic and 35% of the total number of competitions conducted by School B was nonacademic. What is the number of academic competitions conducted by Schools A and B in 2015 and 2016 together?
Correct
Answer – 3) 611
Explanation:
650 * 42/100 + 520 * 65/100
273 + 338 = 611Incorrect
Answer – 3) 611
Explanation:
650 * 42/100 + 520 * 65/100
273 + 338 = 611 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeDirections.Q(15) Read the following bar diagram carefully and answer the questions given below it.
Number of competitions conducted by 5 Schools(A,B,C,D and E) during 2 given years:
The difference between the number of competitions conducted by School A in two years is referred as ‘y1’. Similarly the difference between the number of competitions conducted by other Schools B, C, D and E in two years are referred as “y2”, ”y3”, ”y4” and ”y5” respectively. Then what is the average of y1, y2, y3, y4 and y5?
Correct
Answer – 3) 146
Explanation:
Sum of the Differences = 130 + 200 + 120 + 150 + 130 = 730
Average = 730/5 = 146Incorrect
Answer – 3) 146
Explanation:
Sum of the Differences = 130 + 200 + 120 + 150 + 130 = 730
Average = 730/5 = 146 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative Aptitude? 10 20 38 65 102 150
Correct
Incorrect

Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudePipe M takes 3 minutes more to fill the tank than two pipes M & N opened together to fill it. Second pipe N takes 64/3 minutes more to fill tank than two pipes M & N opened together to fill it. When will the tank be full if both the pipes are opened simultaneously.
Correct
Answer – 3) 8 minutes
Explanation:
1/x = 1/(x + 3) + 3/(3x + 64)
1/x = [ 3x + 64 + 3(x + 3) ] ÷ [(x + 3)(3x + 64) ]
1/x = [ 3x + 64 + 3x + 9 ] ÷ [ 3x² + 64x + 9x + 192 ]
1/x = (6x + 73) ÷ (3x² + 73x + 192)
3x² + 73x + 192 = 6x² + 73x
3x² = 192
x² = 64
x = 8 or 8
x = 8 minutesIncorrect
Answer – 3) 8 minutes
Explanation:
1/x = 1/(x + 3) + 3/(3x + 64)
1/x = [ 3x + 64 + 3(x + 3) ] ÷ [(x + 3)(3x + 64) ]
1/x = [ 3x + 64 + 3x + 9 ] ÷ [ 3x² + 64x + 9x + 192 ]
1/x = (6x + 73) ÷ (3x² + 73x + 192)
3x² + 73x + 192 = 6x² + 73x
3x² = 192
x² = 64
x = 8 or 8
x = 8 minutes 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeTotal distance between two points is ‘a’ km. If the distance covered along the stream is three times of the total distance and the distance covered against the stream is two times of the total distance. If the time taken to cover the distance along the stream is 10% less than the time taken to cover the distance against the stream. If Mahendra cover a distance of 21 km in 1 hour 24 minutes along the stream, then find the thrice of the rate of current?
Correct
Answer – 5) 9 kmph
Explanation:
Distance covered along the stream = 3a
Distance covered against the stream = 2a
Speed of boat in still water = x kmph
Speed of current = y kmph
21/x+y = 7/5
x + y = 15
3Z/x+y = 90/100 * 2Z/xy
x – y = 9
x = 12 y = 3 * 3 = 9Incorrect
Answer – 5) 9 kmph
Explanation:
Distance covered along the stream = 3a
Distance covered against the stream = 2a
Speed of boat in still water = x kmph
Speed of current = y kmph
21/x+y = 7/5
x + y = 15
3Z/x+y = 90/100 * 2Z/xy
x – y = 9
x = 12 y = 3 * 3 = 9 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeFind out the wrong number in the series given below
92 88 84 72 52 22Correct
Answer – 4) 88
Explanation:
Incorrect
Answer – 4) 88
Explanation:

Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeA smartphone costs 15 times as compared to cost of a feature phone. On each Smartphone there is profit of 25%. While the total profit on selling a feature phone and a smartphone is 30%. If there is a profit of Rs 2100 on selling the feature phone then find the total cost price of smartphone and feature phone?
Correct
Answer – 3) Rs 32000
Explanation:
Let CP of feature phone = x
CP of Smartphone = 15x
Total SP = 16x * 1.3 = 20.8x
SP of Smartphone = 15x * 1.25 = 18.75x
SP of feature phone = 2.05x
Profit = 1.05x = 2100
x = 2000
15x = 30000; 16x = 32000Incorrect
Answer – 3) Rs 32000
Explanation:
Let CP of feature phone = x
CP of Smartphone = 15x
Total SP = 16x * 1.3 = 20.8x
SP of Smartphone = 15x * 1.25 = 18.75x
SP of feature phone = 2.05x
Profit = 1.05x = 2100
x = 2000
15x = 30000; 16x = 32000
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