Hello Aspirants
Welcome to Online Quants Test in AffairsCloud.com. We are starting Cumulus Course for IBPS Clerk 2018 Main Exam and we are creating sample questions in Quants section, this type of Question will be asked in IBPS Clerk 2018!!!
Click Here to View Cumulus Course: IBPS Clerk 2018 Mains
IBPS Clerk 2018 Mains: GA Test – 7.00 PM Every Day
IBPS Clerk 2018 Mains: Reasoning Test – 8.00 PM Every Day
IBPS Clerk 2018 Mains: Quants Test – 9.00 PM Every Day
IBPS Clerk 2018 Mains: English Test – 10.00 PM Every Day
Help: Share Our Cumulus Course for IBPS Clerk 2018 Exam Course page to your Friends & FB Groups
________________________
Quizsummary
0 of 10 questions completed
Questions:
 1
 2
 3
 4
 5
 6
 7
 8
 9
 10
Information
All the Best
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 10 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
Categories
 Quantitative Aptitude 0%
 1
 2
 3
 4
 5
 6
 7
 8
 9
 10
 Answered
 Review

Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeA watercraft goes downstream from one point to another in 19 hours. It covers the same distance upstream in 23 hours. If the speed of the stream is 2 kmph, then find the distance between the two points?
Correct
Answer – 2) 437 km
Explanation:
19(S+R) = 23(SR)
S = 21 R =2
D = 19*23 = 437Incorrect
Answer – 2) 437 km
Explanation:
19(S+R) = 23(SR)
S = 21 R =2
D = 19*23 = 437 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeA van starts with the speed of 60 kmph with its speed increasing every three hours by 10 kmph. In how many hours will it cover 470 km?
Correct
Answer – 5) 7 hours
Explanation:
470 = 60*3+70*3+80*t
t =1 hour
Total time = 7 hoursIncorrect
Answer – 5) 7 hours
Explanation:
470 = 60*3+70*3+80*t
t =1 hour
Total time = 7 hours 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeRavi sells 3 different files, first at profit 20%, second at 25% loss and third at 10% loss. During the whole transaction he bears the loss of Rs.120, find the cost price of first file if their SP is same?
Correct
Answer – 3) Rs. 360
Explanation:
x = A*120/100 = 1.2A
x = B*75/100 = 0.75B
x = C*90/100 = 0.9C
Loss = (A+B+C) – (1.2A+0.75B+0.9C) = 120
0.4A+ 0.4A/3 0.2A =120
A = 360Incorrect
Answer – 3) Rs. 360
Explanation:
x = A*120/100 = 1.2A
x = B*75/100 = 0.75B
x = C*90/100 = 0.9C
Loss = (A+B+C) – (1.2A+0.75B+0.9C) = 120
0.4A+ 0.4A/3 0.2A =120
A = 360 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeThe CI on a certain sum for 2 years is Rs. 1512 and SI is Rs.1440. If the sum is invested such that the SI is Rs. 2592 and the number of years is equal to the rate of interest per annum, then find the rate?
Correct
Answer – 4) 6%
Explanation:
SI for first year = Rs.720
CISI = 72
Interest on Rs.720 for 1 year =Rs.72
then R =10%
1440 = (P*2*10)/100
P =7200
7200*R*R/100 =2592
R =6Incorrect
Answer – 4) 6%
Explanation:
SI for first year = Rs.720
CISI = 72
Interest on Rs.720 for 1 year =Rs.72
then R =10%
1440 = (P*2*10)/100
P =7200
7200*R*R/100 =2592
R =6 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative Aptitude40 staffs can complete a job in 46 days. After 40 days, some more staffs joined and the job was completed 2 days earlier. How many new staffs joined?
Correct
Answer – 5) 20
Explanation :
40 * (4640) = (40+X) * (62)
X = 20Incorrect
Answer – 5) 20
Explanation :
40 * (4640) = (40+X) * (62)
X = 20 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeDirections.(Q.610) Study the information carefully to answer the questions that follow :
Data regarding the number of people (both graduate and nongraduate) who participated in a Marathon
The total number of people(graduates + nongraduates) who participated the Marathon in July was what percent more than those who participated in November?
Correct
Answer – 3) 10%
Explanation:
Total number of people who participated the Marathon in July = 420 x (420/6) =770
Total number of people who participated the Marathon in November = 420 + 2X (420/3)=700
Required % more = [(770700)*100]/700= 10%Incorrect
Answer – 3) 10%
Explanation:
Total number of people who participated the Marathon in July = 420 x (420/6) =770
Total number of people who participated the Marathon in November = 420 + 2X (420/3)=700
Required % more = [(770700)*100]/700= 10% 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeDirections.(Q.610) Study the information carefully to answer the questions that follow :
Data regarding the number of people (both graduate and nongraduate) who participated in a Marathon
In November, if 192 nongraduate males participated the Marathon, what was the number of graduate females who participated the Marathon in that Month?
Correct
Answer – 1) 292
Explanation:
Number of graduate males in November = 320192= 128
graduate females in November =420128= 292Incorrect
Answer – 1) 292
Explanation:
Number of graduate males in November = 320192= 128
graduate females in November =420128= 292 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeDirections.(Q.610) Study the information carefully to answer the questions that follow :
Data regarding the number of people (both graduate and nongraduate) who participated in a Marathon
In December, if the number of nongraduates (males + females) increased by 40% and that of graduates (males + females) reduced by 20%, as compared to August, what was the difference between the number of graduates and nongraduates who participated the Marathon in December?
Correct
Answer – 4) 14
Explanation:
Number of nongraduate (males + female) in August = 350 * (3/5) =210
Required difference =(21 * 140/100) – (350 * 80/100)=14Incorrect
Answer – 4) 14
Explanation:
Number of nongraduate (males + female) in August = 350 * (3/5) =210
Required difference =(21 * 140/100) – (350 * 80/100)=14 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeDirections.(Q.610) Study the information carefully to answer the questions that follow :
Data regarding the number of people (both graduate and nongraduate) who participated in a Marathon
What is the average number of nongraduates (males + females) who participated the Marathon in July, September and October?
Correct
Answer – 1) 370
Explanation:
Required average = [(420 * 5/6 + 320 *5/4 + 300 * 6/5)]/3=370Incorrect
Answer – 1) 370
Explanation:
Required average = [(420 * 5/6 + 320 *5/4 + 300 * 6/5)]/3=370 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeDirections.(Q.610) Study the information carefully to answer the questions that follow :
Data regarding the number of people (both graduate and nongraduate) who participated in a Marathon
What is the ratio of the total number of males (graduates + nongraduates) who participated the Marathon in August and September together to that of females (graduates and nongraduates) who participated the Marathon in the same Months together?
Correct
Answer – 2) 7 : 9
Explanation:
Number of nongraduates (males + females) in August = 350 * 3/5 = 210
Number of nongraduates (males + females) in November = 320 * (5/4)=400
Number of females (graduates + nongraduates) in August = (350 +210240)=320
Similarly in November = (320+400320) = 400
Required ratio = (240+320) : (320+400)= 7 : 9Incorrect
Answer – 2) 7 : 9
Explanation:
Number of nongraduates (males + females) in August = 350 * 3/5 = 210
Number of nongraduates (males + females) in November = 320 * (5/4)=400
Number of females (graduates + nongraduates) in August = (350 +210240)=320
Similarly in November = (320+400320) = 400
Required ratio = (240+320) : (320+400)= 7 : 9
________________________
 Click view Questions button to view Explanation
 Note: We are providing unique questions for you to practice well, have a try !!
 Ask your doubt in comment section, AC Mod’s ll clear your doubts in caring way.
 If you find any mistake, please tell us in the comment section.s