**Hello Aspirants**. Welcome to Online Quantitative Aptitude Section in AffairsCloud.com. Here we are creating sample questions in **Quadratic Equations** which is common for all the competitive exams. We have included Some questions that are repeatedly asked in bank exams !!!

Follow the link **To solve Quadratic Equations with the help of Number Line**

**(x – 2)(x + 1) = 0**

**2y² – y + 1/8 = 0**

A. X > Y

B. X < Y

C. X ≥ Y

D. X ≤ Y

E. X = Y or relation cannot be established**E. X = Y or relation cannot be established**

Explanation:

(x – 2) (x + 1) = 0

x = -1, 2

2y² – y + 1/8 = 0

1/8(16y² – 8y + 1) = 0

16y² – 8y + 1 = 0

y = 0.25, 0.25**x**^{2}– 27x + 182 = 0

**y**^{2}+ (y + 1)^{2}= 365

A. X > Y

B. X < Y

C. X ≥ Y

D. X ≤ Y

E. X = Y or relation cannot be established**C. X ≥ Y**

Explanation:

x^{2}– 27x + 182 = 0

x = 13, 14

y^{2}+ (y + 1)^{2}= 365

y^{2}+ y² + 1 + 2y = 365

y^{2}+ y – 182 = 0

y = -14, 13**x**^{2}+ (x – 7)² = 13²

**y(2y + 3) = 90**

A. X > Y

B. X < Y

C. X ≥ Y

D. X ≤ Y

E. X = Y or relation cannot be established**E. X = Y or relation cannot be established**

Explanation:

x^{2}+ (x – 7)² = 13²

x^{2}– 7x – 60 = 0

x = 12, -5

y(2y + 3) = 90

2y² + 3y – 90 = 0

y = – 7.5, 6**1/(x – 3) + 1/(x + 5) = 1/3**

**(y + 2)(27 – y) = 210**

A. X > Y

B. X < Y

C. X ≥ Y

D. X ≤ Y

E. X = Y or relation cannot be established**B. X < Y**

Explanation:

1/(x – 3) + 1/(x + 5) = 1/3

x^{2}– 4x -21 = 0

x = 7, -3

(y + 2)(27 – y) = 210

y² – 25x + 156 = 0 => y = 12, 13**√(x² + (x + 30)²)= x + 60**

**(y + 5) (360/y – 1)= 0**

A. X > Y

B. X < Y

C. X ≥ Y

D. X ≤ Y

E. X = Y or relation cannot be established**E. X = Y or relation cannot be established**

Explanation:

√(x² + (x + 30)²)= x + 60

x² – 60x – 2700 = 0

x = 90, – 30

y^{2}– 355y – 1800 = 0

y = 360, -5**(3x – 2)/y = (3x + 6)/(y + 16)**

**(x + 2)/(y + 4) = (x + 5)/(y + 10)**

A. X > Y

B. X < Y

C. X ≥ Y

D. X ≤ Y

E. X = Y or relation cannot be established**B. X < Y**

Explanation:

(3x – 2)/y = (3x + 6)/(y + 16)

y + 16(3x – 2) = y (3x + 16)

48x – 8y = 32 —(a)

(x + 2)/(y + 4) = (x + 5)/(y + 10)

(x + 2)(y + 10) = (x + 5)(y + 4)

2x = y —(b)

From (a) and (b) x = 1, y = 2**1/x + 1/(x-10) = 8/75**

**132/y – 132/(y + 11) = 1**

A. X > Y

B. X < Y

C. X ≥ Y

D. X ≤ Y

E. X = Y or relation cannot be established**E. X = Y or relation cannot be established**

Explanation:

1/x + 1/x-10 = 8/75

8x² – 230x + 750 = 0

x = 25, 3.75

132/y – 132/(y + 11) = 1

y² + 11y – 1452 = 0

y = -44, 33**x² – 4x – 21 = 0**

**y² – 35y + 306 = 0**

A. X > Y

B. X < Y

C. X ≥ Y

D. X ≤ Y

E. X = Y or relation cannot be established**B. X < Y**

Explanation:

x² – 4x – 21 = 0

x = 7, -3

y² – 35y + 306 = 0

y = 18, 17**(x – 2)(x + 1) = (x – 1)(x + 3)**

**(y + 3)(y – 2) = (y + 1)(y + 2)**

A. X > Y

B. X < Y

C. X ≥ Y

D. X ≤ Y

E. X = Y or relation cannot be established**A. X > Y**

Explanation:

(x – 2)(x + 1) = (x – 1)(x + 3)

x = 1/3

(y + 3)(y – 2) = (y +1)(y + 2)

y = – 4**(x – 4)(x – 3) = (x – 6)(x – 5)**

**(y – 9)(y – 3) = (y – 4)(y – 3)**

A. X > Y

B. X < Y

C. X ≥ Y

D. X ≤ Y

E. X = Y or relation cannot be established**A. X > Y**

Explanation:

(x – 4)(x – 3) = (x – 6)(x – 5)

4x = 18

x = 4.5

(y – 9)(y – 3) = (y – 4)(y – 3)

y = 3

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