Hello Aspirants. Welcome to Online Quantitative Aptitude Section in AffairsCloud.com. Here we are creating sample questions in Quadratic Equations which is common for all the competitive exams. We have included Some questions that are repeatedly asked in bank exams !!!
Follow the link To solve Quadratic Equations with the help of Number Line
- 5x + 2y = 31
3x + 7y = 36
A. X > Y
B. X < Y
C. X ≥ Y
D. X ≤ Y
E. X = Y or relation cannot be establishedA. X > Y
Explanation:
5x + 2y = 31 —-(1)
3x + 7y = 36 —-(2)
By solving eqn(1) and (2)
x = 5 ; y = 3 - x2 – x – √3x + √3= 0
y2 – 3y + 2 = 0
A. X > Y
B. X < Y
C. X ≥ Y
D. X ≤ Y
E. X = Y or relation cannot be establishedE. X = Y or relation cannot be established
Explanation:
x2 – x – √3x + √3= 0
x (x-1) – √3(x -1) = 0
(x-1) (x-√3) = 0
x = 1, 1.732
y2 – 3y + 2 = 0
y2 – y – 2y + 2 = 0
y = 1, 2
Put on number line
1, 1, 1.732, 2 - [48 / x4/7] – [12 / x4/7] = x10/7
y³ + 783 = 999
A. X > Y
B. X < Y
C. X ≥ Y
D. X ≤ Y
E. X = Y or relation cannot be establishedD. X ≤ Y
Explanation:
(48 – 12) / x4/7 = x10/7
36 = x(10/7 + 4/7)
36 = x2
x = ± 6
y3 + 783 = 999
y3 = 999 – 783
y3 = 216
y = 6
Put on number line
-6, 6, 6 - 172 + 144 ÷ 18 = x
262 – 18 * 21 = y
A. X > Y
B. X < Y
C. X ≥ Y
D. X ≤ Y
E. X = Y or relation cannot be establishedB. X < Y
Explanation:
172 + 144 ÷ 18 = x
x = 297
262 – 18 * 21 = y
y = 676 – 378 = 29 - 5/7 – 5/21 = √x/42
√y/4 + √y/16 = 250/√y
A. X > Y
B. X < Y
C. X ≥ Y
D. X ≤ Y
E. X = Y or relation cannot be establishedB. X < Y
Explanation:
5/7 – 5/21 = √x/42
10/21 = √x/42
√x = 20
x = 400
√y/4 + √y/16 = 250/√y
5√y/16 = 250/√y
y = 800 - 9/√x + 19/√x = √x
y5 – [(28)11/2 /√y] = 0
A. X > Y
B. X < Y
C. X ≥ Y
D. X ≤ Y
E. X = Y or relation cannot be establishedE. X = Y or relation cannot be established
Explanation:
9/√x + 19/√x = √x
x = 28
y5 – [(28)11/2 /√y] = 0
y11/2 = (28)11/2
y = 28 - 12/√x – 23/√x = 5√x
√y/12 – 5√y/12 = 1/√y
A. X > Y
B. X < Y
C. X ≥ Y
D. X ≤ Y
E. X = Y or relation cannot be establishedA. X > Y
Explanation:
12/√x – 23/√x = 5√x
-11 = 5x
x = -2.2
√y/12 – 5√y/12 = 1/√y
√y[1/12 – 5/12]= 1/√y
y = -3 - 7x + 6y + 4z = 122
4x + 5y + 3z = 88
9x + 2y + z = 78
A. X < Y = Z
B. X ≤ Y < Z
C. X < Y > Z
D. X = Y > Z
E. X = Y = Z or relation cannot be establishedA. X < Y = Z
Explanation:
7x + 6y + 4z = 122 —(1)
4x + 5y + 3z = 88 —(2)
9x + 2y + z = 78 —(3)
From (1) and (2) => 5x – 2y =4 —(a)
From (2) and (3) => 23x + y = 146 —(b)
From (a) and (b) => x = 6, y = 8. Put values in eqn (3) => z = 8 - (x+y)³ = 1331
x – y + z = 0
xy = 28
A. X < Y = Z
B. X ≤ Y < Z
C. X < Y > Z
D. X = Y > Z
E. X = Y = Z or relation cannot be establishedE. X = Y or relation cannot be established
Explanation:
(x + y)³ = 1331
x + y = 11 —(a)
(x + y)2 = 121
(a + b)2 – (a – b)2 = 4ab
(x – y)2 + 4xy = 121
x – y = 3 —(b)
From eqn (a) and (b)
x = 7; y = 4 Put values in eqn (2) => z = -3 - 7x + 6y = 110
4x + 3y = 59
x + z = 15
A. X < Y = Z
B. X ≤ Y < Z
C. X < Y > Z
D. X = Y > Z
E. X = Y = Z or relation cannot be establishedC. X < Y > Z
Explanation:
7x + 6y = 110 —(1)
4x + 3y = 59 —(2)
x + z = 15 —(3)
From eqn(1) and (2)
x = 8; y = 9 Put values in eqn (3) => z = 7
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