Hello Aspirants. Welcome to Online Quantitative Aptitude section in AffairsCloud.com. Here we are creating question sample inÂ **Profit and loss** , which is common for all the competitive exams. We have included Some questions that are repeatedly asked in exams!!!

**After allowing a discount of 25% on the market price of an article, there is a gain of 20%. What is the profit % if the article is sold at market price i.e. allowing no discount?**

A) 65%

B) 55%

C) 60%

D) 50%

E) 35%**C) 60%**

Explanation:

Let MP = Rs 100

SP = Rs 75, then Discount = 25

Gain = 20%

CP = (100/120) * 75 = 62.5

So Profit% when no discount = [100-62.5/62.5]*100**A chair and a table together cost Rs 1800. If by selling the table at a profit of 15% and the chair at a loss of 10% a total profit of 6% is made, then what is the cost price of the chair?**

A) Rs 890

B) Rs 844

C) Rs 648

D) Rs 728

E) None of these**D) Rs 648**

Explanation:

Be method of allegation:

15 Â Â Â Â Â Â Â Â Â -10

. Â Â Â Â Â 6

6-(-10) Â Â Â Â Â Â 15-6

16 : 9

So cost of table = 9/(16+9) * 1800**An article is marked 10% above the cost price. When the selling price of an article is increased by 20% the profit gets increased by Rs 96. If the marked price of the article is Rs 440, then find original selling price.**

A) Rs 455

B) Rs 365

C) Rs 385

D) Rs 435

E) Rs 480**E) Rs 480**

Explanation:

MP = 440, Also given MP = (110/100)*CP, so CP = Rs 400

Now SP â€“ 400 = P

And given that, when SP increased by 20%:

(120/100)*SP â€“ 400 = P + 96

Solve both equations**An article is sold at a discount of 25% and still there is a gain of 20% on it. Find the marked price of the article if it costs Rs 525.**

A) Rs 658

B) Rs 840

C) Rs 758

D) Rs 930

E) None of these**B) Rs 840**

Explanation:

Use M.P. = (100 + p%)/(100 â€“ d%) * C.P.

So MP = (100+20)/(100-25) * 525**An article is marked at Rs 1500. A customer gets a discount of 20% on it. If he wants the article at Rs 960, what additional discount he wants to have?**

A) 15%

B) 20%

C) 14%

D) 22%

E) 18%**B) 20%**

Explanation:

1500 * [(100-20)/100] * [(100-x)/100] = 960**Cost price of 25 note books is equal to the selling price of 40 note books. What is the gain or loss per cent?**

A) 37 1/2% loss

B) 23 2/3% loss

C) 23 2/3% gain

D) 37 1/2% gain

E) 45% loss**A) 37 1/2% loss**

Explanation:

CP of 25 = SP of 40

When number of articles in SP > number of articles in CP, these is loss, so

loss % = (40-25)/40 * 100**There is a loss of 25% on an article when it is sold at 3/5th the previous selling price. What is the actual profit% on it?**

A) 25%

B) 30%

C) 18%

D) 10%

E) 22%**A) 25%**

Explanation:

Shortcut:

[(5/3)*(100-25)] â€“ 100 = 125 â€“ 100**A shopkeeper bought an article at 20% discount on the marked price, and he sold it at a profit of 40% on the marked price. What is the actual profit% made by the shopkeeper?**

A) 55%

B) 45%

C) 75%

D) 72%

E) 66%**C) 75%**

Explanation:

Let MP = 100

So CP = Rs 80

And SP = 140

So actual profit% = (140-80)/80 * 100**5 kg of an article is bought at Rs 480, 1/3rd of it is sold at a profit of 20%. At what loss% should the remaining article be sold so that there is an overall profit of 3 1/3%?**

A) 8.5%

B) 7%

C) 6.5%

D) 5%

E) 8%**D) 5%**

Explanation:

Shortcut:

Let the remaining 2/3rd be sold at x% loss

1/3(20) + 2/3(-x) = 3 1/3 [x% loss, so used – sign]

1/3(20) + 2/3(-x) = 10/3

Solve, x = 5%**An article is sold at 25% profit. If the CP and the SP of the article are increased by Rs 60 and Rs 30 respectively, the profit% decreases by 15%. Find the cost price of the article.**

A) Rs 190

B) Rs 240

C) Rs 285

D) Rs 305

E) None of these**B) Rs 240**

Explanation:

CP = x, then SP = (125/100)*x = 5x/4

New CP = (x+60), new SP = (5x/4 + 30), new profit% = 25-15 = 10

So (5x/4 + 30) = (110/100) * (x+60)

Solve, x = 240

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