Hello Aspirants. Welcome to Online Quantitative Aptitude Section with explanation in AffairsCloud.com. Here we are creating question sample in **Number System**, which is common for all the competitive exams. We have included Some questions that are repeatedly asked in bank exams !!

**A number is multiplied by 561, and the result obtained is 32,582. But it was found that both 2 in the number are wrong, what should be the correct answer?**

A) 33,583

B) 37,587

C) 39,589

D) 36,586

E) None of these**B) 37,587**

Explanation:

561 = 3*11*17

So the number must be divided by 3, 11 and 17

Only B option is divided by all.**If the number 10*47* is divisible by both 5 and 11, then the missing digits are respectively**

A) 1 and 5

B) 6 and 0

C) 5 and 0

D) 2 and 5

E) None of these**A) 1 and 5**

Explanation:

Check the options in the number 10x47y

all numbers will be divisible by 5 because in end it is 5 and 0

for number to be divisible by 11, (y+4+0) – (7+x+1) should be divisible by 11

from option A, y = 5, x = 1 gives (y+4+0) – (7+x+1) as 0 which is divisible by 11**The sum of digits of a two digit number is 6. The ratio of the original number to the number formed by interchanging its digits is 4 : 7. Find the number.**

A) 60

B) 15

C) 42

D) 33

E) 24**E) 24**

Explanation:

Let the number is 10x+y

So x+y = 6

And (10x+y)/(10y+x) = 4/7

Solve, 2x = y and from above we have x+y = 6

Solve both equations, x = 2, y = 4**When a number is multiplied by 13 and 13 is added to the product, the resultant is divisible by 5. Find the smallest number possible?**

A) 85

B) 130

C) 65

D) 90

E) 105**C) 65**

Explanation:

13x + 13 which is divisible by 15, or 13(x+1) should be divisible by 5. The smallest value of x = 4 to be put here to make it divisible by 5. So the number is 13(4+1)**Find the least number which must be subtracted from 103876 to make the obtained number divisible by 16.**

A) 5

B) 4

C) 3

D) 7

E) 9**B) 4**

Explanation:

103876/16 gives remainder 4, so 4 should be subtracted**The difference between two numbers is 2577. The quotient and remainder are respectively 26 and 2 when the larger number is divided by the smaller one. What is the largest number?**

A) 2594

B) 2680

C) 2851

D) 2654

E) 2632**B) 2680**

Explanation:

Smaller no = x, then larger = x+2577

Now x+2577 = 26x + 2

Solve, x = 103

So larger no is = 103+2577**The difference between the digits of a two digit number is 5. Also the original number is 18 more than two times the number obtained by reversing its digits. Find the original number.**

A) 94

B) 61

C) 72

D) 49

E) 27**C) 72**

Explanation:

Let number is 10x+y

Then x-y = 5 or y-x = 5

Now given that, 10x+y = 2(10y+x) + 18

Solve, 8x – 19y = 18

Now solve: 8x – 19y = 18 and x-y = 5. In this y = 2, x = 7

And also solve; 8x – 19y = 18 and y-x = 5. In this y come to be negative which is not possible so discard this

So number is 10*7 + 2**A number when divided by 462 gives the remainder as 25. When same number is divided by 14, the remainder will be?**

A) 9

B) 5

C) 12

D) 11

E) 15**D) 11**

Explanation:

Let x be the quotient, then that number becomes 462*x + 25

Which = (22x * 14) + (14*1)+11

Which = 14 (22x + 1) + 11**Kavya attends 40 questions and get 96 marks. If 3 marks are given for each correct answer and 1 mark is deducted for each wrong answer, find the number of question she attended correct?**

A) 15

B) 34

C) 32

D) 36

E) 33**B) 34**

Explanation:

Let she attend x correct answers out of 40, then incorrect = 40-x

So x*3 – (40-x)*1 = 96

Solve, x = 34**When 1 is added to the numerator of a fraction it becomes 1/4 and 1 is subtracted from the denominator of that fraction it becomes 1/5. Find the fraction.**

A) 4/19

B) 3/16

C) 5/17

D) 2/15

E) None of these**B) 3/16**

Explanation:

Let fraction = x/y

Then (x+1)/y = 1/4

And x/(y-1) = 1/5

Solve both equations, x = 3, y = 16

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