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Question 1 of 10
1. Question
1 pointsx² – 21x + 98 = 0
y² – 23y + 120 = 0Correct
Answer – 5. X = Y or relation cannot be established
Explanation:
x² – 21x + 98 = 0
x = 14, 7
y² – 23y + 120 = 0
y = 15, 8Incorrect
Answer – 5. X = Y or relation cannot be established
Explanation:
x² – 21x + 98 = 0
x = 14, 7
y² – 23y + 120 = 0
y = 15, 8 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative Aptitude2, 4, 7, ?, 87, 344
Correct
Answer – 2.24
Explanation :
2 + 1² + 1 = 4
4 + 2² – 1 = 7
7 + 4² + 1 = 24
24 + 8² – 1 = 87
87 + 16² + 1 = 344Incorrect
Answer – 2.24
Explanation :
2 + 1² + 1 = 4
4 + 2² – 1 = 7
7 + 4² + 1 = 24
24 + 8² – 1 = 87
87 + 16² + 1 = 344 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeThe ratio of efficiency of Suresh is to Praveen is 5:3. The ratio of number of days taken by Rohit is to Praveen is 2:3. Suresh takes 6 days less than Praveen, when Suresh and Praveen complete the work individually. Rohit and Praveen started the work and left after 2 days. The number of days taken by Suresh to finish the remaining work is?
Correct
Answer – 3. 6 days
Explanation :
Ratio of number of days = 9:10:15
Work done By Rohit and Praveen in first two days = 2*1/6 = 1/3
Rest of the work = 2/3
Number of days = (2/3)/(1/9) = 6 daysIncorrect
Answer – 3. 6 days
Explanation :
Ratio of number of days = 9:10:15
Work done By Rohit and Praveen in first two days = 2*1/6 = 1/3
Rest of the work = 2/3
Number of days = (2/3)/(1/9) = 6 days 
Question 4 of 10
4. Question
1 pointsCategory: General AwarenessA boat running upstream takes 8 hours 45 minutes to cover a certain distance, while it takes 5 hours to cover the same distance running downstream. What is the ratio between the speed of the boat and speed of the water current respectively?
Correct
Answer – 2. 11 : 3
Explanation :
x*35/4 = 5y
y = 7x/4
Required Ratio = (Y + X / 2) : (Y – X / 2)
11x/8 : 3x/8 = 11:3Incorrect
Answer – 2. 11 : 3
Explanation :
x*35/4 = 5y
y = 7x/4
Required Ratio = (Y + X / 2) : (Y – X / 2)
11x/8 : 3x/8 = 11:3 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeA circular Cricket ground is surrounded by a concrete wall 4 feet wide. If the area of the concrete wall surrounding the ground is 11/25 that of the ground, then the radius of the ground is?
Correct
Answer – 2. 20ft
Explanation :
Radius of the Pool = x
Radius of the Pool including the wall = x+4
Area of the concrete wall = Π[(x+4)^2 – x^2] =8Π(x+2)
8Π(x+2) = 11/25Πx^2
X = 20 feetIncorrect
Answer – 2. 20ft
Explanation :
Radius of the Pool = x
Radius of the Pool including the wall = x+4
Area of the concrete wall = Π[(x+4)^2 – x^2] =8Π(x+2)
8Π(x+2) = 11/25Πx^2
X = 20 feet 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeA basket contains 5 red 4 blue 3 green stones. If three stones picked up random, What is the probability that at least one is blue?
Correct
Answer – 1. 41/55
Explanation :
Total stones = 12
other than blue 8c3 / 12c3 = 14/55
probability = 114/55 = 41/55Incorrect
Answer – 1. 41/55
Explanation :
Total stones = 12
other than blue 8c3 / 12c3 = 14/55
probability = 114/55 = 41/55 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeArun normally takes 4 hours more than the time taken by Shyam to walk X km. If Arun doubles her speed, she can make it in 2 hours less than that of Shyam. How much time does Shyam require for walking X km?
Correct
Answer – 3. 8 hours
Explanation :
Let Shyam takes x hours to walk X km.
Then, Arun takes (x + 4) hours to walk X km.
With double of the speed, Arun will take (x + 4)/2 hours.
x – (x + 4)/2 = 2
=> 2x – (x + 4) = 4
=> 2x – x – 4 = 4
x = 4 + 4 = 8 hoursIncorrect
Answer – 3. 8 hours
Explanation :
Let Shyam takes x hours to walk X km.
Then, Arun takes (x + 4) hours to walk X km.
With double of the speed, Arun will take (x + 4)/2 hours.
x – (x + 4)/2 = 2
=> 2x – (x + 4) = 4
=> 2x – x – 4 = 4
x = 4 + 4 = 8 hours 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeA Reservoir can be filled by an inlet pipe at the rate of 5 litres per minute. A leak in the bottom of a Reservoir can empty the full tank in 8 hours. When the Reservoir is full, the inlet is opened and due to the leak, the Reservoir is empty in 40 hours. How many litres does the Reservoir hold?
Correct
Answer – 5. 3000 litre
Explanation :
Part emptied by the leak in 1 hour = 1/8
part filled by (leak & inlet open) in 1 hour = 1/40
Part filled by the inlet pipe in 1 hour = 1/8 – 1/40 = 1/10
Inlet pipe fills the tank in = 10 hours
Inlet pipe fills water at the rate of 5 litres a minute.
Capacity of Reservoir = 10 * 60 * 5 = 3000 litreIncorrect
Answer – 5. 3000 litre
Explanation :
Part emptied by the leak in 1 hour = 1/8
part filled by (leak & inlet open) in 1 hour = 1/40
Part filled by the inlet pipe in 1 hour = 1/8 – 1/40 = 1/10
Inlet pipe fills the tank in = 10 hours
Inlet pipe fills water at the rate of 5 litres a minute.
Capacity of Reservoir = 10 * 60 * 5 = 3000 litre 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeRohit, Ravi and Ram invested Rs 1000 for 8 months, Rs 1200 for 6 months and Rs 1500 for some months. Out of a total profit of Rs 5,675 as profit, Rohit received Rs 2000. For how much months did Ram invested?
Correct
Answer – 3. 5
Explanation:
1000*8 : 1200*6 : 1500*x
80 : 72 : 15x
So 80/(80+72+15x) * 5675 = 2000
Solve, x = 5.Incorrect
Answer – 3. 5
Explanation:
1000*8 : 1200*6 : 1500*x
80 : 72 : 15x
So 80/(80+72+15x) * 5675 = 2000
Solve, x = 5. 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeTwo trains are running in opposite directions in the same speed. The length of each train is 150 meter. If they cross each other in 15 seconds, the speed of each train (in km/hr) is
Correct
Answer – 2.36
Explanation:
Distance covered = 150+150 = 300 m
Time = 15 s
Let the speed of each train = x. Then relative speed = x + x = 2x
2x = distance/time = 300/15 = 20 m/s
Speed of each train = x = 20/2 = 10 m/s
= 10 × 18/5 km/hr = 36 km/hrIncorrect
Answer – 2.36
Explanation:
Distance covered = 150+150 = 300 m
Time = 15 s
Let the speed of each train = x. Then relative speed = x + x = 2x
2x = distance/time = 300/15 = 20 m/s
Speed of each train = x = 20/2 = 10 m/s
= 10 × 18/5 km/hr = 36 km/hr
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