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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeThe average weight of all the 11 players of RCB is 49 kg. If the average of first six lightest weight players of RCB is 49 kg and that of the six heaviest players of RCB is 52 kg. The average weight of the player which lies in the sixth position in the list of players when all the 11 players of RCB are arranged in the order of increasing or decreasing weights.
Correct
Answer – 4. 67 kg
Explanation:
Average of First six players = 49 * 6 = 294
Average of Last six players = 52 * 6 = 312; Average of all players = 49 * 11 = 539
Average weight of sixth player = 294 + 312 – 539 = 67Incorrect
Answer – 4. 67 kg
Explanation:
Average of First six players = 49 * 6 = 294
Average of Last six players = 52 * 6 = 312; Average of all players = 49 * 11 = 539
Average weight of sixth player = 294 + 312 – 539 = 67 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeA container which contains a mixture of Sulfuric acid and water in ratio 13:4. 25.5 litres of mixture is taken out from the container and 2.5 litres of pure water and 5 litres of Sulfuric acid is added to the mixture. If resultant mixture contains 25% water, what was the initial quantity of mixture in the container before the replacement in litre?
Correct
Answer – 2. 68 litre
Explanation :
Quantity of Sulfuric acid = 13x
Quantity of water = 4x
Total = 17x
Resultant Mixture = 17x – 25.5 + 2.5 + 5 = 17x – 18
Resultant water = 4x – 25.5 * (4/17) + 2.5 = 4x – 3.5
Resultant mixture contains 25% water
(17x – 18)*25/100 = 4x – 3.5
x = 4
Initial quantity = 17*4 = 68Incorrect
Answer – 2. 68 litre
Explanation :
Quantity of Sulfuric acid = 13x
Quantity of water = 4x
Total = 17x
Resultant Mixture = 17x – 25.5 + 2.5 + 5 = 17x – 18
Resultant water = 4x – 25.5 * (4/17) + 2.5 = 4x – 3.5
Resultant mixture contains 25% water
(17x – 18)*25/100 = 4x – 3.5
x = 4
Initial quantity = 17*4 = 68 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeThe present age of Rohini is onefourth that of her father. After 6 years, the father’s age will be twice the age of Kajol. If Kajol celebrated fifth birthday 8 year ago, What is the Present age of Rohini?
Correct
Answer – 3. 8 years
Explanation :
Kajol’s present age = 8 + 5 = 13
Kajol’s age after 6 years = 13 + 6 = 19
Kajol’s father age = 2 * 19 = 38
Father’s present age = 32
Rohini’s present age = 32 / 4 = 8Incorrect
Answer – 3. 8 years
Explanation :
Kajol’s present age = 8 + 5 = 13
Kajol’s age after 6 years = 13 + 6 = 19
Kajol’s father age = 2 * 19 = 38
Father’s present age = 32
Rohini’s present age = 32 / 4 = 8 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeInitially, a shopkeeper had “Y” bangles. A customer bought 10% of bangles from “Y” then another customer bought 20% of the remaining bangles after that one more customer purchased 25% of the remaining bangles. Finally, shopkeeper is left with 270 bangles in his shop. How many bangles were there initially in his shop?
Correct
Answer – 5. 500
Explanation:
Y*0.9*0.8*0.75 =270
Y = 270 * 10000 / 9 * 8 * 75
Y = 500Incorrect
Answer – 5. 500
Explanation:
Y*0.9*0.8*0.75 =270
Y = 270 * 10000 / 9 * 8 * 75
Y = 500 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeRitesh sells his bike to Mukesh at a loss of 20% who subsequently sells it to Sharma at a profit of 25%. Sharma after finding some defect in the bike, returns it to Mukesh but could recover only Rs.4.50 for every Rs. 5 he had paid. Find the amount of Sharma’s loss if Ritesh had paid Rs.50,000 for the bike?
Correct
Answer – 4. Rs. 5000
Explanation :
0.50/5 * 50,000 = 5000Incorrect
Answer – 4. Rs. 5000
Explanation :
0.50/5 * 50,000 = 5000 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeSyndicate Bank lent Rs. 10,000 to Dinesh 7% SI for 10 years. Meanwhile, the government implemented a scheme due to which interest rate reduced by 2%. By this Dinesh paid Rs.16,000 in total. Then after how many years after Dinesh took the loan, the government introduced the scheme?
Correct
Answer – 3. 5 years
Explanation :
6000 = 10000(7*x+5*(10x))/100
x = 5Incorrect
Answer – 3. 5 years
Explanation :
6000 = 10000(7*x+5*(10x))/100
x = 5 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeA Minivan travelled to a place B from A, the first 50 km at 10 kmph faster than the usual speed, but it returned the same distance at 10 kmph slower than usual speed. If the total time taken by the Minivan is 12 hours, then how many hours will travel at the faster speed?
Correct
Answer – 3. 2 hours
Explanation :
Total time taken,
[50/(x10)] + 50/(x +10)] = 12 hours.
By solving the equation, we get
x = 15
Time is taken by the Minivan at faster speed = 50/(15+10) = 2 hours.Incorrect
Answer – 3. 2 hours
Explanation :
Total time taken,
[50/(x10)] + 50/(x +10)] = 12 hours.
By solving the equation, we get
x = 15
Time is taken by the Minivan at faster speed = 50/(15+10) = 2 hours. 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeIn a firecrackers company, there are equal number of women and children. Women work for 8 hours a day and children for 6 hours a day. During festival time, the work load goes up by 50%. The government rule does not allow children to work for more than 8 hours a day. If they are equally efficient and the extra work is done by women, then extra hours of work put in by women every day are?
Correct
Answer – 1. 5
Explanation :
Let extra hours a day are x.
According to the formula,
(M1D1T1) / W1 = (M2D2T2) / W2
⇒ [1 x 1 x (8 + 6)] / 1 = [1 x 1 x (8 + 8 + x)] / 3/2
⇒ (3/2) x 14 = 16 + x
⇒ 21= 16 + x
∴ x = 21 – 16 = 5Incorrect
Answer – 1. 5
Explanation :
Let extra hours a day are x.
According to the formula,
(M1D1T1) / W1 = (M2D2T2) / W2
⇒ [1 x 1 x (8 + 6)] / 1 = [1 x 1 x (8 + 8 + x)] / 3/2
⇒ (3/2) x 14 = 16 + x
⇒ 21= 16 + x
∴ x = 21 – 16 = 5 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeThe ratio of the age between Arun and Bala is 6:5, and the age of Chitra and Daniel is 9/10 times that of Bala. Age of Faruq is less than Arun but greater than Bala. The ratio of age of Bala & Preeti is 2:3, also age of A is 3 years less than Preeti .What is the ratio of age of Arun and Faruq, if all the ages are in integers ?
Correct
Answer – 4. 12 : 11
Explanation :
B = 5/6A
C = D = 9/10B
B = 3/2E
E – A =3
A/E = ⅘ => E = 5/4A
EA = 5A/4 – A = 3
A = 12, E = 15, B =10, C = D = 9 and F = 11
A : F = 12 : 11Incorrect
Answer – 4. 12 : 11
Explanation :
B = 5/6A
C = D = 9/10B
B = 3/2E
E – A =3
A/E = ⅘ => E = 5/4A
EA = 5A/4 – A = 3
A = 12, E = 15, B =10, C = D = 9 and F = 11
A : F = 12 : 11 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeJames and Dinesh have to clear their respective loans by paying 3 equal annual installments of Rs. 30000 each. James pays @ 10% per annum of simple interest while Dinesh pays 10% per annum compound interest. What is the difference in their payments?
Correct
Answer – 1. Rs. 300
Explanation :
James = SI
1st year=100
2nd = 100+10% of 100=110
3rd = 110+10% of 100=120
Total = 330
Dinesh = CI
1st yr = 100
2nd yr =100+10% of 100=110
3rd year=110+10% of 110=121
Total = 331
Diff = 331330=1%
30000*1%=300Incorrect
Answer – 1. Rs. 300
Explanation :
James = SI
1st year=100
2nd = 100+10% of 100=110
3rd = 110+10% of 100=120
Total = 330
Dinesh = CI
1st yr = 100
2nd yr =100+10% of 100=110
3rd year=110+10% of 110=121
Total = 331
Diff = 331330=1%
30000*1%=300
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