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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

A sum of money is lent for 2 years at 20% p.a. compound interest. It yields Rs 602.5 more when compounded semi-annually than compounded annually. What is the sum lent?

50 people start a work working 9 hours each day. After 10 days it was found that only 3/5th of the work was done. How many additional people need to be employed in order to complete the remaining work in 5 days working 8 hours each day?

Correct

Explanation:
Let x people need to be employed to complete remaining work (1 – 3/5) = 2/5
M1*D1*H1*W2 = M2*D2*H2*W1
50*10*9*(2/5) = (50+x)*5*8*(3/5)
Solve x = 25

Incorrect

Explanation:
Let x people need to be employed to complete remaining work (1 – 3/5) = 2/5
M1*D1*H1*W2 = M2*D2*H2*W1
50*10*9*(2/5) = (50+x)*5*8*(3/5)
Solve x = 25

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

A man can row 8 km/hr in still water. When the river is running at 6 km/hr, it takes him 4 hrs to row to a place and come back. How far is the place?

Correct

Explanation:
B is speed of boat in still water, R is speed of stream
Time is total time taken for upstream and downstream
Distance = time * [B^2 – R^2] / 2*B
= 4 * [8^2 – 6^2] / 2*8

Incorrect

Explanation:
B is speed of boat in still water, R is speed of stream
Time is total time taken for upstream and downstream
Distance = time * [B^2 – R^2] / 2*B
= 4 * [8^2 – 6^2] / 2*8

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

There are two examination halls A and B. If 5 students are sent from A to B, the number of students in both the halls is same. If 10 students are sent from B to A, then the ratio of no of students in A to B becomes 8 : 5. The number of students in sections A and B resp. is

Correct

Explanation:
x-5 = y+5
x-y = -10…………….(1)
(x+10)/(y-10) = 8/5
5x-8y=-130…………….(2)
solve (1) & (2)
we get x = 70, y = 60

Incorrect

Explanation:
x-5 = y+5
x-y = -10…………….(1)
(x+10)/(y-10) = 8/5
5x-8y=-130…………….(2)
solve (1) & (2)
we get x = 70, y = 60

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

The cost of material is divides in its raw materials, labour cost and transportation in the ratio 4 : 9 : 5. If the labour cost on the making of material was Rs 8100, what is the cost of material?

Correct

Explanation:
4 : 9 : 5
So 9/(4+9+5) * x = 8100
So, x = 16200

Incorrect

Explanation:
4 : 9 : 5
So 9/(4+9+5) * x = 8100
So, x = 16200

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

The percentage increase in the surface area of a cube when each side if doubled is

Correct

Explanation:
Surface area = 6a^{2}
So when side becomes 2a, Surface area = 6(2a)^{2} = 24a^{2}
So % increase = (24a^{2} – 6a^{2})/6a^{2} * 100

Incorrect

Explanation:
Surface area = 6a^{2}
So when side becomes 2a, Surface area = 6(2a)^{2} = 24a^{2}
So % increase = (24a^{2} – 6a^{2})/6a^{2} * 100

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

A and B invested Rs 16000 and Rs 12000 respectively in a business. After 3 months A withdrew Rs 5000 while B invested Rs 5000 more. After 3 more months C joined them with Rs 21000. After 1 year, out of a total profit of Rs 26,400, the share of B exceeded that of C by

Correct

Explanation:
A : B : C
16000*3 + 11000*9 : 12000*3 + 17000*9 : 21000*6
7 : 9 : 6
So, difference in shares of B and C = (9-6)/(7+9+6) * 26400 = 3600

Incorrect

Explanation:
A : B : C
16000*3 + 11000*9 : 12000*3 + 17000*9 : 21000*6
7 : 9 : 6
So, difference in shares of B and C = (9-6)/(7+9+6) * 26400 = 3600

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

The sides of a triangle are in the ratio 1/2 : 1/3 : 1/4. If the perimeter of the triangle is 65 cm, then the largest side is

Correct

Explanation:
1/2 : 1/3 : 1/4 = 6 : 4 : 3,
So 6x+4x+3x = 65
13x = 65, so x = 5
So largest side is = 6x = 6*5

Incorrect

Explanation:
1/2 : 1/3 : 1/4 = 6 : 4 : 3,
So 6x+4x+3x = 65
13x = 65, so x = 5
So largest side is = 6x = 6*5

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

If x + (1/x) = 3, then [x^{2} + 4x + 1] / [x^{2} + 18x + 1] =

Correct

Explanation:
[x^{2} + 4x + 1] / [x^{2} + 18x + 1]
Take common x from both num and den and cancel
So = [x + 4 + 1/x] / [x + 18 + 1/x]
= [3+4]/[3+18] = 7/21

Incorrect

Explanation:
[x^{2} + 4x + 1] / [x^{2} + 18x + 1]
Take common x from both num and den and cancel
So = [x + 4 + 1/x] / [x + 18 + 1/x]
= [3+4]/[3+18] = 7/21

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

A price of an article is first decreased by 10% and then increased by 25%. If the final price of the article becomes Rs 360, what was the original price?

Correct

Explanation:
x * (90/100) * (125/100) = 360
solve, x = 320

Incorrect

Explanation:
x * (90/100) * (125/100) = 360
solve, x = 320