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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeThe HCF and LCM of two numbers is 70 and 1050 respectively. If the first number is 210, find the second one.
Correct
Explanation:
Product of two numbers = HCF * LCM
So 2nd number = 70*1050/210Incorrect
Explanation:
Product of two numbers = HCF * LCM
So 2nd number = 70*1050/210 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeIf sinɸ + cosecɸ = 2, then the value of sin^{3}ɸ + cosec^{3}ɸ
Correct
Explanation:
sinɸ + 1/sinɸ = 2
(sin^{2}ɸ + 1)/sinɸ = 2
sin^{2}ɸ + 2 sinɸ + 1 = 0
(sinɸ + 1) ^{2} = 0
So sinɸ + 1 = 0
So sinɸ = 1 and then also 1/sinɸ = cosecɸ = 1
So sin^{3}ɸ + cosec^{3}ɸ = 1 + (1) = 2Incorrect
Explanation:
sinɸ + 1/sinɸ = 2
(sin^{2}ɸ + 1)/sinɸ = 2
sin^{2}ɸ + 2 sinɸ + 1 = 0
(sinɸ + 1) ^{2} = 0
So sinɸ + 1 = 0
So sinɸ = 1 and then also 1/sinɸ = cosecɸ = 1
So sin^{3}ɸ + cosec^{3}ɸ = 1 + (1) = 2 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeA person can row a distance of 20 km upstream in 6 minutes and downstream in 2 minutes. What is the speed of the boat in still water?
Correct
Explanation:
Upstream speed = 20/(6/60) = 200 km/hr
Downstream speed = 20/(2/60) = 600 km/hr
So speed of the boat = (1/2)*(600+200)Incorrect
Explanation:
Upstream speed = 20/(6/60) = 200 km/hr
Downstream speed = 20/(2/60) = 600 km/hr
So speed of the boat = (1/2)*(600+200) 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeThe sides of a rectangle are in the ratio 3 : 4 : 5 whose area is 216 sq. cm. What will be the perimeter of this triangle?
Correct
Explanation:
Sides 3x, 4x, 5x
So semiperimeter, s = (3x+4x+5x)/2 = 6x
Area = √s(sa)(sb)(sc)
= √6x*3x*2x*x = 6x^{2} cm^{2}
So 6x^{2} = 216, this gives x = 6
Perimeter = 12x = 12*6Incorrect
Explanation:
Sides 3x, 4x, 5x
So semiperimeter, s = (3x+4x+5x)/2 = 6x
Area = √s(sa)(sb)(sc)
= √6x*3x*2x*x = 6x^{2} cm^{2}
So 6x^{2} = 216, this gives x = 6
Perimeter = 12x = 12*6 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeRs 6000 becomes Rs 7200 in 3 years at a certain rate of compound interest. What will be the amount received after 9 years?
Correct
Explanation:
6000[1 + r/100]^{3} = 7200
So [1 + r/100]^{3} = 6/5
So 6000[1 + r/100]^{9} = 6000*(6/5)*(6/5)*(6/5)Incorrect
Explanation:
6000[1 + r/100]^{3} = 7200
So [1 + r/100]^{3} = 6/5
So 6000[1 + r/100]^{9} = 6000*(6/5)*(6/5)*(6/5) 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeIf x + (1/x) = 3, then [x^{2} + 4x + 1] / [x^{2} + 18x + 1] =
Correct
Explanation:
[x^{2} + 4x + 1] / [x^{2} + 18x + 1]
Take common x from both num and den and cancel
So = [x + 4 + 1/x] / [x + 18 + 1/x]
= [3+4]/[3+18] = 7/21Incorrect
Explanation:
[x^{2} + 4x + 1] / [x^{2} + 18x + 1]
Take common x from both num and den and cancel
So = [x + 4 + 1/x] / [x + 18 + 1/x]
= [3+4]/[3+18] = 7/21 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeFind the minimum value of (sinɸ cosɸ)^{3}.
Correct
Explanation:
Minimum value = (1/2)^{n}Incorrect
Explanation:
Minimum value = (1/2)^{n} 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeIf the altitude of an equilateral triangle is 8√3 cm, then its area would be
Correct
Explanation:
Altitude= (√3/2)*a^2
8√3 = (√3/2)*a^2
Solve, a = 4
So area = (√3/4)*a^2Incorrect
Explanation:
Altitude= (√3/2)*a^2
8√3 = (√3/2)*a^2
Solve, a = 4
So area = (√3/4)*a^2 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeA’s 4 days work is equal to B’s 3 days work. If A can complete the work in 12 days then to complete the work B will take how many days?
Correct
Explanation:
A completes 1 work in 12 days, so in 4 days, 4/12 work = 1/3 work
So B in 3 days complete 1/3 work, so 1 work in 3*3 = 9 daysIncorrect
Explanation:
A completes 1 work in 12 days, so in 4 days, 4/12 work = 1/3 work
So B in 3 days complete 1/3 work, so 1 work in 3*3 = 9 days 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeIf the perimeter of a semicircle is equal to its area, what is the measure of its diameter?
Correct
Explanation:
ᴨr + 2r =[ ᴨ (r)^{2}]/2
this gives, ᴨ + 2 = ᴨ * r/2
or 2ᴨ + 4 = ᴨr
solve this, r = 2 + 4/ᴨ = 2 + 4*(7/22) = 2 + 14/11 = 36/11
so diameter = 72/11Incorrect
Explanation:
ᴨr + 2r =[ ᴨ (r)^{2}]/2
this gives, ᴨ + 2 = ᴨ * r/2
or 2ᴨ + 4 = ᴨr
solve this, r = 2 + 4/ᴨ = 2 + 4*(7/22) = 2 + 14/11 = 36/11
so diameter = 72/11
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