Welcome to Online Quant Test in AffairsCloud.com. We are starting SSC CGL 2016 Course and we are creating sample questions in Quant section, type of which will be asked in SSC CGL 2016 !!!

You have already completed the quiz before. Hence you can not start it again.

Quiz is loading...

You must sign in or sign up to start the quiz.

You have to finish following quiz, to start this quiz:

Results

0 of 10 questions answered correctly

Your time:

Time has elapsed

You have reached 0 of 0 points, (0)

Categories

Quantitative Aptitude0%

1

2

3

4

5

6

7

8

9

10

Answered

Review

Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

The HCF and LCM of two numbers is 70 and 1050 respectively. If the first number is 210, find the second one.

Correct

Explanation:
Product of two numbers = HCF * LCM
So 2nd number = 70*1050/210

Incorrect

Explanation:
Product of two numbers = HCF * LCM
So 2nd number = 70*1050/210

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

If sinɸ + cosecɸ = -2, then the value of sin^{3}ɸ + cosec^{3}ɸ

Correct

Explanation:
sinɸ + 1/sinɸ = -2
(sin^{2}ɸ + 1)/sinɸ = -2
sin^{2}ɸ + 2 sinɸ + 1 = 0
(sinɸ + 1) ^{2} = 0
So sinɸ + 1 = 0
So sinɸ = -1 and then also 1/sinɸ = cosecɸ = -1
So sin^{3}ɸ + cosec^{3}ɸ = -1 + (-1) = -2

Incorrect

Explanation:
sinɸ + 1/sinɸ = -2
(sin^{2}ɸ + 1)/sinɸ = -2
sin^{2}ɸ + 2 sinɸ + 1 = 0
(sinɸ + 1) ^{2} = 0
So sinɸ + 1 = 0
So sinɸ = -1 and then also 1/sinɸ = cosecɸ = -1
So sin^{3}ɸ + cosec^{3}ɸ = -1 + (-1) = -2

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

A person can row a distance of 20 km upstream in 6 minutes and downstream in 2 minutes. What is the speed of the boat in still water?

Correct

Explanation:
Upstream speed = 20/(6/60) = 200 km/hr
Downstream speed = 20/(2/60) = 600 km/hr
So speed of the boat = (1/2)*(600+200)

Incorrect

Explanation:
Upstream speed = 20/(6/60) = 200 km/hr
Downstream speed = 20/(2/60) = 600 km/hr
So speed of the boat = (1/2)*(600+200)

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

The sides of a rectangle are in the ratio 3 : 4 : 5 whose area is 216 sq. cm. What will be the perimeter of this triangle?

Correct

Explanation:
Sides 3x, 4x, 5x
So semi-perimeter, s = (3x+4x+5x)/2 = 6x
Area = √s(s-a)(s-b)(s-c)
= √6x*3x*2x*x = 6x^{2} cm^{2}
So 6x^{2} = 216, this gives x = 6
Perimeter = 12x = 12*6

Incorrect

Explanation:
Sides 3x, 4x, 5x
So semi-perimeter, s = (3x+4x+5x)/2 = 6x
Area = √s(s-a)(s-b)(s-c)
= √6x*3x*2x*x = 6x^{2} cm^{2}
So 6x^{2} = 216, this gives x = 6
Perimeter = 12x = 12*6

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

Rs 6000 becomes Rs 7200 in 3 years at a certain rate of compound interest. What will be the amount received after 9 years?

Correct

Explanation:
6000[1 + r/100]^{3} = 7200
So [1 + r/100]^{3} = 6/5
So 6000[1 + r/100]^{9} = 6000*(6/5)*(6/5)*(6/5)

Incorrect

Explanation:
6000[1 + r/100]^{3} = 7200
So [1 + r/100]^{3} = 6/5
So 6000[1 + r/100]^{9} = 6000*(6/5)*(6/5)*(6/5)

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

If x + (1/x) = 3, then [x^{2} + 4x + 1] / [x^{2} + 18x + 1] =

Correct

Explanation:
[x^{2} + 4x + 1] / [x^{2} + 18x + 1]
Take common x from both num and den and cancel
So = [x + 4 + 1/x] / [x + 18 + 1/x]
= [3+4]/[3+18] = 7/21

Incorrect

Explanation:
[x^{2} + 4x + 1] / [x^{2} + 18x + 1]
Take common x from both num and den and cancel
So = [x + 4 + 1/x] / [x + 18 + 1/x]
= [3+4]/[3+18] = 7/21

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

Find the minimum value of (sinɸ cosɸ)^{3}.

Correct

Explanation:
Minimum value = (1/2)^{n}

Incorrect

Explanation:
Minimum value = (1/2)^{n}

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

If the altitude of an equilateral triangle is 8√3 cm, then its area would be

Correct

Explanation:
Altitude= (√3/2)*a^2
8√3 = (√3/2)*a^2
Solve, a = 4
So area = (√3/4)*a^2

Incorrect

Explanation:
Altitude= (√3/2)*a^2
8√3 = (√3/2)*a^2
Solve, a = 4
So area = (√3/4)*a^2

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

A’s 4 days work is equal to B’s 3 days work. If A can complete the work in 12 days then to complete the work B will take how many days?

Correct

Explanation:
A completes 1 work in 12 days, so in 4 days, 4/12 work = 1/3 work
So B in 3 days complete 1/3 work, so 1 work in 3*3 = 9 days

Incorrect

Explanation:
A completes 1 work in 12 days, so in 4 days, 4/12 work = 1/3 work
So B in 3 days complete 1/3 work, so 1 work in 3*3 = 9 days

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

If the perimeter of a semicircle is equal to its area, what is the measure of its diameter?