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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

Q. (1-4) study the following pie-chart and table and answer the given questions. The following pie-chart shows the percentage number of students passed in matriculate examination from six different schools across the country in the year 2015. Also, the bar graph shows the percentage of female students who passed their exam in 2015(0ut of total of students passed from that particular school)

if in 2015, total number of female students from school ROS was 336, then how many male students passed the exam from school NBV?

Correct

Answer : 4.1056 Explanation
Let the total number of students who passed from school ROS be x, then 28% of x = 336 or x = 1200, now, let the total students passed from all school be y, then, 15% of y = 1200 or y =8000. Now total students passed from school NBV = 22% of 8000 =1760. Therefore, number of male students passed from school NBV = 60% of 1760 =1056.

Incorrect

Answer : 4.1056 Explanation
Let the total number of students who passed from school ROS be x, then 28% of x = 336 or x = 1200, now, let the total students passed from all school be y, then, 15% of y = 1200 or y =8000. Now total students passed from school NBV = 22% of 8000 =1760. Therefore, number of male students passed from school NBV = 60% of 1760 =1056.

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

Q. (1-4) study the following pie-chart and table and answer the given questions. The following pie-chart shows the percentage number of students passed in matriculate examination from six different schools across the country in the year 2015. Also, the bar graph shows the percentage of female students who passed their exam in 2015(0ut of total of students passed from that particular school)

if total passed students from school DPI in 2015 was 2400, then what is the ratio of the numbers of female students who passed from school CRR to that of male students who passed from school ROS?

Correct

Answer: 3.77:540 Explanation
We can say, 12% of x = 2400(x = total number of passed students in all schools or, x= 20000. Number of female passed students from school CRR = 14% of 11% of 20000 = 308
Number of male passed students from school ROS = 72% of15% of 20000 = 2160.
Required ratio = 308:2160 = 77/540

Incorrect

Answer: 3.77:540 Explanation
We can say, 12% of x = 2400(x = total number of passed students in all schools or, x= 20000. Number of female passed students from school CRR = 14% of 11% of 20000 = 308
Number of male passed students from school ROS = 72% of15% of 20000 = 2160.
Required ratio = 308:2160 = 77/540

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

Q. (1-4) study the following pie-chart and table and answer the given questions. The following pie-chart shows the percentage number of students passed in matriculate examination from six different schools across the country in the year 2015. Also, the bar graph shows the percentage of female students who passed their exam in 2015(0ut of total of students passed from that particular school)

If in the year 2016, there is an increase of 16% and 24% in the strength of passing students from school ROS and DAV respectively and the total number of passed students from school CRR in the year 2015 was 1650. What would be the total number of students who passed from school DAV and ROS in 2016?

Correct

Answer: 3.7074 Explanation
11% of x = 1650 x = total number of passed students in all school or x = 15000. Total students passed
from school ROS = 15% of 15000 = 2250, total students passed from school DAV = 24% of 15000 = 3600.
In the year 2016, total students passed from school ROS = 116% of 2250 = 2610, total students passed from school DAV = 124% of 3600 = 4464, total number of students passed in both school in 2016 = 2610+4464 = 7074

Incorrect

Answer: 3.7074 Explanation
11% of x = 1650 x = total number of passed students in all school or x = 15000. Total students passed
from school ROS = 15% of 15000 = 2250, total students passed from school DAV = 24% of 15000 = 3600.
In the year 2016, total students passed from school ROS = 116% of 2250 = 2610, total students passed from school DAV = 124% of 3600 = 4464, total number of students passed in both school in 2016 = 2610+4464 = 7074

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

Q. (1-4) study the following pie-chart and table and answer the given questions. The following pie-chart shows the percentage number of students passed in matriculate examination from six different schools across the country in the year 2015. Also, the bar graph shows the percentage of female students who passed their exam in 2015(0ut of total of students passed from that particular school)

if the male students passed from school DAV in 2015 were 306. What was the total number of passed students from all schools together?

Correct

Answer: 1.1875 Explanation
It is given that, 68% of x = 306 (x = total number of DAV passed students) or x = 450, now, 24% of y =
450(y= total number of passed students in all schools or, y = 1875)

Incorrect

Answer: 1.1875 Explanation
It is given that, 68% of x = 306 (x = total number of DAV passed students) or x = 450, now, 24% of y =
450(y= total number of passed students in all schools or, y = 1875)

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

Correct

Answer: 1.2.4 Explanation
75 × x = 64 + 116 = 180
X = 180/75 =2.4

Incorrect

Answer: 1.2.4 Explanation
75 × x = 64 + 116 = 180
X = 180/75 =2.4

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

36.06% of 449.95 + √3140 – 17.96 × 12.92=x

Correct

Answer : 4.-16 Explanation
162 + 56 – 234 =-16

Incorrect

Answer : 4.-16 Explanation
162 + 56 – 234 =-16

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

Rahul and Rafick start a business with investments of Rs. 2500 and Rs. 2250 respectively. After 2 months, Rahul takes out Rs.1250 from his capital. After 1 more month, Rafick takes out Rs.750 of his capital while Ramesh joins them with a capital of Rs. 3500. At the end of 6 months, they earn a profit of Rs. 2540. Which of the following is the share of each member in the profit?

Correct

Answer : 3.Rahul – Rs. 800, Rafick – Rs. 900, Ramesh – Rs. 840 Explanation
Initial investment of Rahul = Rs.2500.
After 2 months, he withdraws Rs.1250 from his capital.
Therefore, we have, Rahul invested Rs.2500 for 2 months and Rs. (2500-1250=) 1250 for 4 months.
Rafick invested Rs. 2250 for 3 months and Rs. (2250-750=) 1500 for 3 months.
And, Ramesh invested Rs.3500 for 3 months;

Total profit for 6 months = Rs.2540
Therefore, Rahul’s share = Rs. (2540 x 40/ (40+45+42)) = Rs. (2540 x 40/127) = Rs.800
Rafick’s share = Rs. (2540 x 45/127) = Rs.900
Ramesh’s share = Rs. (2540 x 42/127) = Rs.840

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

S & T can do a piece of work in 9 days and 18 days respectively. As they were ill they could do 90% and 72% of their efficiency respectively. How many days will they take to complete the work together?

Correct

Answer: 1.50/7 Explanation
Let the amount of work be 1800 units. Rate of doing work by S is = 1800/9 = 200 units/day; similarly, for T rate will be = 1800/18 = 100 units/day
But the efficiency as given for S is 90% so its rate will be = 90% of 200 = 180 units/day
Similarly, the efficiency of T as given is 72% so its rate becomes = 72% of 100 = 72 units/day
With this reduced efficiency of doing work bot S & T together will take = 1800/ (180+72) = 1800/252 =50/7days

Incorrect

Answer: 1.50/7 Explanation
Let the amount of work be 1800 units. Rate of doing work by S is = 1800/9 = 200 units/day; similarly, for T rate will be = 1800/18 = 100 units/day
But the efficiency as given for S is 90% so its rate will be = 90% of 200 = 180 units/day
Similarly, the efficiency of T as given is 72% so its rate becomes = 72% of 100 = 72 units/day
With this reduced efficiency of doing work bot S & T together will take = 1800/ (180+72) = 1800/252 =50/7days

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

A circular wire of radius 42 cm is cut and bent in the form of a rectangle whose sides are in the ratio of 6:5 find the smaller side of the rectangle

Correct

Answer : 1.60 Explanation

Incorrect

Answer : 1.60 Explanation

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

a motor boat in still water travels at a speed of 36 km/h. it goes 56 km upstream in 1 hour 45 minutes. The time taken by it to cover the same distance down the stream will be:

Correct

Answer : 2.1 hr 24 mins Explanation

Incorrect

Answer : 2.1 hr 24 mins Explanation

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