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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeThe total surface area of a cube, sphere and cylinder is the same. The height of the cylinder is twice its radius.
Quantity I: Volume of the cube.
Quantity II: Volume of the sphere.
Quantity III: Volume of the cylinder.Correct
Answer : 2. Quantity II > Quantity III > Quantity I
Explanation
Let the cubeâ€™s edge length is a, the surface area of cube = 6a^2 and its volume = a^3.
Let the radius of the sphere is r, then its volume = (4/3) Ï€r^3 and its surface area will be 4Ï€r^2.
Let the height of the cylinder be 2h therefore, its radius will be h.
Surface area of the cylinder = 2Ï€h (2h) +2Ï€h^2 = 6Ï€h^2.
Now since the surface area are same, 6a^2 = 4Ï€r^2 = 6Ï€h^2, therefore, r= (âˆš3/âˆš (2Ï€)) a.
Volume of sphere = (âˆš6/âˆšÏ€)a^3, this will be always greater than a^3.
Hence Quantity II > Quantity I, Also 6a^2 = 4Ï€r^2 = 6Ï€h^2, a = (âˆšÏ€)/h.
Volume of the cylinder = Ï€h^2(2h) = 2Ï€h^3 = 2Ï€(a/âˆšÏ€)^3 = 2a^3/(âˆšÏ€) > a^3.
Hence Quantity III > Quantity I. Volume of sphere = (âˆš6/âˆšÏ€) a^3 is > volume of the cylinder = 2a^3/ (âˆšÏ€).
Hence, Quantity II > Quantity III > Quantity IIncorrect
Answer : 2. Quantity II > Quantity III > Quantity I
Explanation
Let the cubeâ€™s edge length is a, the surface area of cube = 6a^2 and its volume = a^3.
Let the radius of the sphere is r, then its volume = (4/3) Ï€r^3 and its surface area will be 4Ï€r^2.
Let the height of the cylinder be 2h therefore, its radius will be h.
Surface area of the cylinder = 2Ï€h (2h) +2Ï€h^2 = 6Ï€h^2.
Now since the surface area are same, 6a^2 = 4Ï€r^2 = 6Ï€h^2, therefore, r= (âˆš3/âˆš (2Ï€)) a.
Volume of sphere = (âˆš6/âˆšÏ€)a^3, this will be always greater than a^3.
Hence Quantity II > Quantity I, Also 6a^2 = 4Ï€r^2 = 6Ï€h^2, a = (âˆšÏ€)/h.
Volume of the cylinder = Ï€h^2(2h) = 2Ï€h^3 = 2Ï€(a/âˆšÏ€)^3 = 2a^3/(âˆšÏ€) > a^3.
Hence Quantity III > Quantity I. Volume of sphere = (âˆš6/âˆšÏ€) a^3 is > volume of the cylinder = 2a^3/ (âˆšÏ€).
Hence, Quantity II > Quantity III > Quantity I 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeThere are 5 red balls, 6 green balls, 9 blue balls and remaining yellow balls in a lot of 50 balls.
Quantity I: Probability of picking 2 balls such that one is green and the other is blue.
Quantity II: Probability of picking up three balls such that at least one of them is red.
Quantity III: Probability of picking 3 balls such that at least one is blue.Correct
Answer : 4. Quantity III > Quantity II > Quantity I
Explanation
Quantity I: 6*9/(50C2) = 54/1225.
Quantity II = 1 45C3/(50C3)= 1 â€“ 14190/19600 = 541/1960 > Quantity I .
Quantity III = 1 â€“ 41C3/(50C3)= 1 â€“ 10660/19600 = 894/1960 > Quantity II > Quantity I.
Hence, Quantity III > Quantity II > Quantity IIncorrect
Answer : 4. Quantity III > Quantity II > Quantity I
Explanation
Quantity I: 6*9/(50C2) = 54/1225.
Quantity II = 1 45C3/(50C3)= 1 â€“ 14190/19600 = 541/1960 > Quantity I .
Quantity III = 1 â€“ 41C3/(50C3)= 1 â€“ 10660/19600 = 894/1960 > Quantity II > Quantity I.
Hence, Quantity III > Quantity II > Quantity I 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative Aptitudewhat will be the increase percent in volume?
Statement I: An ice cube is dip into 10 litre water
Statement II: If radius of a cylinder increases by 20% and height increases by 10%
Statement III: If the height of ice cube is 10 cm.Correct
Answer : 2. II alone and I and III together
Explanation
Volume = Ï€*r*r*h
so by successive formula, the increase in volume can be found
First: r*r
So 20 + 20 + (20) (20)/100 = 44%
Next: 44 + 10 + (44)*(10)/100 â€“ final increase in volume
From I and III:
volume of given shape (cylinder, cube, cone etc.) = 10 l (initial volume). And ice cube of height 10 cm is dip into it.
So after finding new volume or increase in volume after the ice cube is dipped, % increase in volume can be found.Incorrect
Answer : 2. II alone and I and III together
Explanation
Volume = Ï€*r*r*h
so by successive formula, the increase in volume can be found
First: r*r
So 20 + 20 + (20) (20)/100 = 44%
Next: 44 + 10 + (44)*(10)/100 â€“ final increase in volume
From I and III:
volume of given shape (cylinder, cube, cone etc.) = 10 l (initial volume). And ice cube of height 10 cm is dip into it.
So after finding new volume or increase in volume after the ice cube is dipped, % increase in volume can be found. 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeHow many students failed in class 6?
Statement I: 400 students passed in class.
Statement II: Number of students failed in class 6 is 10% of those of failed in class 7?
Statement III: 75% of the students who appeared in examination have passed either in class 8.Correct
answer : 4. None of these
Explanation
Data is not sufficient to find the number of failed students in class 6.Incorrect
answer : 4. None of these
Explanation
Data is not sufficient to find the number of failed students in class 6. 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeA bag contains 3 red, 4 green and 2 blue balls. Two balls are drawn at random.
Quantity I: Probability that none of the ball drawn is blue.
Quantity II: Fraction of work completed by A in 7 days if he is 20% more efficient than B who can complete the work in 12 days.Correct
Answer : 3. Quantity II > Quantity I
Explanation
Solution: I: 7C2/9C2=7/12
II: A> 10 days => fraction of work in 7 days = 7/10
Hence II > IIncorrect
Answer : 3. Quantity II > Quantity I
Explanation
Solution: I: 7C2/9C2=7/12
II: A> 10 days => fraction of work in 7 days = 7/10
Hence II > I 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeQ. (610) in college A, B, C, D, and E students watch differentdifferent serials, there are three serials GOT, SUITS and FRIENDS. Number of students who watch particular serial and from particular college are shown above, Answer the following questions
From college D, out of the students watching FRIENDS, 40% got selected for State levelâ€™ quiz competition. Out of which 25% further got selected for National levelâ€™s quiz competition. From college E, out of the students watching FRIENDS, 33 1/3% got selected for State levelâ€™s quiz competition, out of which twofifth further got selected for National levelâ€™s quiz competition. What is the total number of students watching FRIENDS from these two colleges who got selected for National levelâ€™s quiz competition?Correct
Answer : 3. 50
ExplanationTotal student in D who watch FRIENDS are 300, student selected for state level quiz is 40% of 300=120
For national level is 25% of 120=30
Total student who watch FRIENDS are 150, for state level quiz 33(1/3)% of 150= 50, for national level are two fifth of 50 is 20
Total student from both colleges selected for national level quiz are 50Incorrect
Answer : 3. 50
ExplanationTotal student in D who watch FRIENDS are 300, student selected for state level quiz is 40% of 300=120
For national level is 25% of 120=30
Total student who watch FRIENDS are 150, for state level quiz 33(1/3)% of 150= 50, for national level are two fifth of 50 is 20
Total student from both colleges selected for national level quiz are 50 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeQ. (610) in college A, B, C, D, and E students watch differentdifferent serials, there are three serials GOT, SUITS and FRIENDS. Number of students who watch particular serial and from particular college are shown above, Answer the following questions
Total number of students watch suits from all colleges together is approximately what percent of the total number of students watch GOT from all colleges together?Correct
Answer : 3. 95.23
Explanation
Total no of student who watch SUITS= 200+300+250+150+100=1000
Total no of students who watch GOT=250+100+150+200+350=1050
1000/1050=95.23Incorrect
Answer : 3. 95.23
Explanation
Total no of student who watch SUITS= 200+300+250+150+100=1000
Total no of students who watch GOT=250+100+150+200+350=1050
1000/1050=95.23 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeQ. (610) in college A, B, C, D, and E students watch differentdifferent serials, there are three serials GOT, SUITS and FRIENDS. Number of students who watch particular serial and from particular college are shown above, Answer the following questions
If out of the students watching SUITS from colleges B, D and E 16.66 %, 6.66%, and 20% respectively got selected for state levelâ€™s quiz competition, what was the total number of students watching SUITS got selected for State levelâ€™s quiz competition from these colleges together?Correct
Answer : 1. 80
Explanation
Students selected for state level from college B = 16(2/3)% of 300=50
Students selected for state level from college D = 6(2/3)% of 150=10
Students selected for state level from college E = 20% of 100= 20
Total = 50+10+20= 80Incorrect
Answer : 1. 80
Explanation
Students selected for state level from college B = 16(2/3)% of 300=50
Students selected for state level from college D = 6(2/3)% of 150=10
Students selected for state level from college E = 20% of 100= 20
Total = 50+10+20= 80 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeQ. (610) in college A, B, C, D, and E students watch differentdifferent serials, there are three serials GOT, SUITS and FRIENDS. Number of students who watch particular serial and from particular college are shown above, Answer the following questions
If the number of students watching each serial in college C is increased by 15% and the number of students watching each serial in college E is decreased by 5%, then what will be the difference between number of students in college C and E?Correct
Answer : 2. 120
Explanation
Total no of student after increment in C is =600(115/100)=690
Total no of student after decrement in E is=600(95/100)=570
Difference = 690570= 120Incorrect
Answer : 2. 120
Explanation
Total no of student after increment in C is =600(115/100)=690
Total no of student after decrement in E is=600(95/100)=570
Difference = 690570= 120 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeQ. (610) in college A, B, C, D, and E students watch differentdifferent serials, there are three serials GOT, SUITS and FRIENDS. Number of students who watch particular serial and from particular college are shown above, Answer the following questions
Total number of students watching GOT and SUITS together from college A is what percent of the total number of students watching these two serials together from college D?Correct
Answer : 1. 128(4/7)
Explanation
Student from A who watch these two serials =450
Student from D who watch these two serials =350
Required answer=(450/350)Ã—100=128(4/7)Incorrect
Answer : 1. 128(4/7)
Explanation
Student from A who watch these two serials =450
Student from D who watch these two serials =350
Required answer=(450/350)Ã—100=128(4/7)
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