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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeQ. (15)below question consists a question and two statements numbered I and II or III are given below it. You have to decide whether the data provided in the statements are sufficient to answer the question Read both the statement and Give answer.
Is the sum of the costs of A and B more than the sum of the costs of a C and a D?
I. 30% of the cost of the A and 20% of the cost of the B is more than 40% of a cost of the C and 60% of the cost of D.
II. 20% of the cost of the A and 30% of the cost of the B is less than 10% of the cost of the C and 15% of the cost of the D.Correct
Answer : 3. Either I or II
Explanation
Incorrect
Answer : 3. Either I or II
Explanation

Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeQ. (15)below question consists a question and two statements numbered I and II or III are given below it. You have to decide whether the data provided in the statements are sufficient to answer the question Read both the statement and Give answer.
Fine the average of 13 consecutive odd numbers.
Statement I: The 5th number exceeds the 1st number by 8.
Statement II: The 4th number is three times the first number.Correct
Answer : 2. Only II
Explanation
First statement is not useful.
From II: (x+6)=3x
x=3 now we can find average from itIncorrect
Answer : 2. Only II
Explanation
First statement is not useful.
From II: (x+6)=3x
x=3 now we can find average from it 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeQ. (15)below question consists a question and two statements numbered I and II or III are given below it. You have to decide whether the data provided in the statements are sufficient to answer the question Read both the statement and Give answer.
what is the age of P in a group of 6 students – P, Q, R, S, T and U who average age is 16 years?
Statement I: Total age of Q and R is 29 years
Statement II: Total age of S and T is 28 years.Correct
Answer : 4. Neither I nor II
Explanation
From both statements also we do not know the age of both P and U. So of P can’t be foundIncorrect
Answer : 4. Neither I nor II
Explanation
From both statements also we do not know the age of both P and U. So of P can’t be found 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeQ. (15)below question consists a question and two statements numbered I and II or III are given below it. You have to decide whether the data provided in the statements are sufficient to answer the question Read both the statement and Give answer.
What is the profit earned by selling a calculator for Rs. 2575?
I. The cost price of 5 such calculators is equal to selling price of 4 such calculators.
II. 25% profit is earned by selling each calculator.Correct
Answer : 3. Either I or II
Explanation
Let’s assume that the cost price of the calculator is Rs. C.
From statement (1):
The cost price of 5 such calculators is equal to selling price of 4 such calculators.
⇒ 5C = 4 × 2575
⇒ C = Rs. 2060
∴ Profit = Selling price – Cost price = 2575 – 2060 = Rs. 515
∴ Statement I alone is sufficient to answer the question.
From statement (2):
25% profit is earned by selling each calculator.
∵ Cost price of each calculator = Rs. C,
Profit earned by selling each calculator = 25% of Rs. C = 0.25C
Selling price = Cost price + profit
∴ Selling price = C + 0.25C = 1.25 C = 2575
⇒ C = 2575/1.25 = 2060
∴ Profit = 0.25 × 2060 = Rs. 515
∴ the statement II alone is sufficient to answer the question.
∴ either to statement I alone or statement II alone is sufficient to answer the questionIncorrect
Answer : 3. Either I or II
Explanation
Let’s assume that the cost price of the calculator is Rs. C.
From statement (1):
The cost price of 5 such calculators is equal to selling price of 4 such calculators.
⇒ 5C = 4 × 2575
⇒ C = Rs. 2060
∴ Profit = Selling price – Cost price = 2575 – 2060 = Rs. 515
∴ Statement I alone is sufficient to answer the question.
From statement (2):
25% profit is earned by selling each calculator.
∵ Cost price of each calculator = Rs. C,
Profit earned by selling each calculator = 25% of Rs. C = 0.25C
Selling price = Cost price + profit
∴ Selling price = C + 0.25C = 1.25 C = 2575
⇒ C = 2575/1.25 = 2060
∴ Profit = 0.25 × 2060 = Rs. 515
∴ the statement II alone is sufficient to answer the question.
∴ either to statement I alone or statement II alone is sufficient to answer the question 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeQ. (15)below question consists a question and two statements numbered I and II or III are given below it. You have to decide whether the data provided in the statements are sufficient to answer the question Read both the statement and Give answer.
Find in how many days P alone can do the work?
Statement I: If P and Q do a work together for 10 days and Q left the work and P do the remaining work in 20 days.
Statement II: If P and Q can do the work in 15 daysCorrect
Answer : 5. Both I and II
Explanation
From I. 30/P + 10/Q =1
from II. 1/P + 1/Q =1/15. We can get P and Q using bothIncorrect
Answer : 5. Both I and II
Explanation
From I. 30/P + 10/Q =1
from II. 1/P + 1/Q =1/15. We can get P and Q using both 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeQ. (610) Study the following charts and answer the questions that follow.
PERCENTAGE OF WORK DONE BY 5 PEOPLE TO COMLETE THE PROJECT
J can complete the whole work in number of days equal to the average of number of days in which A and B can complete the work. J, C, D, and E all started the work and after 5 days they were replaced by A and B. A and B completed the remaining work in how many days?
Correct
Answer : 1. 3 (1/5)
Explanation
A in 20 days, B in 30days.
J in (20+30)/2 = 25 days
J, C, D, and E started work
[1/25 + 1/24 + 1/25 + 1/40]= 11/75.
Worked for 5 days
11/75 * 5 =11/15 of work
Remaining work = 4/15
[1/20 + 1/30]*x = 4/15
x = 48/15 days = 3 (1/5) daysIncorrect
Answer : 1. 3 (1/5)
Explanation
A in 20 days, B in 30days.
J in (20+30)/2 = 25 days
J, C, D, and E started work
[1/25 + 1/24 + 1/25 + 1/40]= 11/75.
Worked for 5 days
11/75 * 5 =11/15 of work
Remaining work = 4/15
[1/20 + 1/30]*x = 4/15
x = 48/15 days = 3 (1/5) days 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeQ. (610) Study the following charts and answer the questions that follow.
PERCENTAGE OF WORK DONE BY 5 PEOPLE TO COMLETE THE PROJECT
P is 20% more efficient than B and Q is 60% more efficient than C. They worked together for 5 days and left the work, after which the remaining work was completed by C and E together. If all worked together, in how many less days they could have completed the work?
Correct
Answer : 5. None of these
Explanation
P and B
P = 120:100 = 6:5. Days = 5:6
6 =30, 1 =5, 5 =25.
P can complete work in 25 days
Q and C
Q = 160: 100 = 8: 5.Days = 5: 8
8 = 24, 1 = 3, 5 = 15.
Q can complete work in 15 days
They worked for 5 days. So
[1/25 + 1/15]*5 = 8/15 work
Reaming 7/15 by C and E
So [1/24 + 1/40]*x = 7/15
x = 7 days
Total = 5+7 = 12 days
They work together
[1/25 + 1/15 + 1/24 + 1/40] = 13/75
So 75/13 days
So less days = 12 – 75/13 = 81/13 = 6 (3/13) daysIncorrect
Answer : 5. None of these
Explanation
P and B
P = 120:100 = 6:5. Days = 5:6
6 =30, 1 =5, 5 =25.
P can complete work in 25 days
Q and C
Q = 160: 100 = 8: 5.Days = 5: 8
8 = 24, 1 = 3, 5 = 15.
Q can complete work in 15 days
They worked for 5 days. So
[1/25 + 1/15]*5 = 8/15 work
Reaming 7/15 by C and E
So [1/24 + 1/40]*x = 7/15
x = 7 days
Total = 5+7 = 12 days
They work together
[1/25 + 1/15 + 1/24 + 1/40] = 13/75
So 75/13 days
So less days = 12 – 75/13 = 81/13 = 6 (3/13) days 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeQ. (610) Study the following charts and answer the questions that follow.
PERCENTAGE OF WORK DONE BY 5 PEOPLE TO COMLETE THE PROJECT
All people decided to complete work in less number of days. So they divided the work equally among themselves. In how many days will the work be completed this way? (They all worked individually)
Correct
Answer : 4. 27.8
Explanation
5 people equally divided the work so each did 1/5 work now
A 1/5 work in 4 days as earlier
B =1/10 work in 3 days, so 1/5 work in 6 days
C =1/4 work in 6 days, so 1/5 work in 24/5 days
D = 3/10 work in 7.5 days, so 1/5 work in 5 days
E = 3/20 work in 6 days, so 1/5 work in 8 days
Complete work in = 4 + 6 + 24/5 + 5 + 8 = 27.8 daysIncorrect
Answer : 4. 27.8
Explanation
5 people equally divided the work so each did 1/5 work now
A 1/5 work in 4 days as earlier
B =1/10 work in 3 days, so 1/5 work in 6 days
C =1/4 work in 6 days, so 1/5 work in 24/5 days
D = 3/10 work in 7.5 days, so 1/5 work in 5 days
E = 3/20 work in 6 days, so 1/5 work in 8 days
Complete work in = 4 + 6 + 24/5 + 5 + 8 = 27.8 days 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeQ. (610) Study the following charts and answer the questions that follow.
PERCENTAGE OF WORK DONE BY 5 PEOPLE TO COMLETE THE PROJECT
G who can complete whole work in 30 days replaced A and did A’s part of work. He left and then B also worked for same number of days as G. If remaining work was completed by M who can do complete work in onefourth the numbers of days in which E can complete the work, then in how many days was the whole work completed?
Correct
Answer : 1. 18
Explanation
A’s part of work = 20% = 1/5
So G did 1/5 of work,
Whole work in 30 days, 1/5 work in 1/5 * 30 = 6 days
B also worked for 6 days.
B can complete whole work in 30 days, in 6 days, completed 6/30 = 1/5 of work
Now remaining work = 1 – (1/5 + 1/5) = 3/5
Now E can complete whole work in 40 days [100*6/15]
So M can complete work in 10 days. So completed 3/5 work in 3/5 * 10 = 6days
So total number of days = 6+6+6 = 18 daysIncorrect
Answer : 1. 18
Explanation
A’s part of work = 20% = 1/5
So G did 1/5 of work,
Whole work in 30 days, 1/5 work in 1/5 * 30 = 6 days
B also worked for 6 days.
B can complete whole work in 30 days, in 6 days, completed 6/30 = 1/5 of work
Now remaining work = 1 – (1/5 + 1/5) = 3/5
Now E can complete whole work in 40 days [100*6/15]
So M can complete work in 10 days. So completed 3/5 work in 3/5 * 10 = 6days
So total number of days = 6+6+6 = 18 days 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeQ. (610) Study the following charts and answer the questions that follow.
PERCENTAGE OF WORK DONE BY 5 PEOPLE TO COMLETE THE PROJECT
A and B started doing the work. After 2 days they both left, and C joined the work. He completed his part of work. Now the remaining work was completed by F in 7 days. In how many days can F complete whole work?
Correct
Answer : 2. 12
Explanation
A does 20% works in 4 days.
100% work in 100*4/20 = 20 days
B can complete 100% work in 100*3/10 = 30 days
They worked for 2 days,
[1/20 + 1/30]*2 = 1/6 work
Now C completed 25% = 1/4 work
So now remaining work = 1 – (1/6 + 1/4) = 7/12
F complete 7/12 work in 7 days, so complete work in 12 daysIncorrect
Answer : 2. 12
Explanation
A does 20% works in 4 days.
100% work in 100*4/20 = 20 days
B can complete 100% work in 100*3/10 = 30 days
They worked for 2 days,
[1/20 + 1/30]*2 = 1/6 work
Now C completed 25% = 1/4 work
So now remaining work = 1 – (1/6 + 1/4) = 7/12
F complete 7/12 work in 7 days, so complete work in 12 days
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