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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeQ (15) Study the following graph carefully to answer these questions.Percentage rise in population of two states from previous year
If total population of two states in 2008 was 85 thousands, what was the total population of two states in 2009? (in thousand)
Correct
Incorrect

Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeQ (15) Study the following graph carefully to answer these questions.Percentage rise in population of two states from previous year
If the ratio between the population of Punjab and Chennai in year 2011 was 2 : 3 respectively, what was the respective ratio in 2010 ?
Correct
Explanation:
(X*130/100)/(y*140/100)=2/3
x/y=28/39Incorrect
Explanation:
(X*130/100)/(y*140/100)=2/3
x/y=28/39 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeQ (15) Study the following graph carefully to answer these questions.Percentage rise in population of two states from previous year
If population of Punjab in 2008 was 20 thousand, what was the average population of state in 2008, 2009 and 2010 together ?
Correct
Explanation:
2008=20
2009=20*1.25=25
2010=25*1.35=33.75
Average=20+25+33.75/3=26.25Incorrect
Explanation:
2008=20
2009=20*1.25=25
2010=25*1.35=33.75
Average=20+25+33.75/3=26.25 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeQ (15) Study the following graph carefully to answer these questions.Percentage rise in population of two states from previous year
What was the effective percentage increase in population of Punjab from 2011 to 2013 ?
Correct
Explanation:
2011=100
2012=140
2013=140*1.45=203
Increase=103Incorrect
Explanation:
2011=100
2012=140
2013=140*1.45=203
Increase=103 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeQ (15) Study the following graph carefully to answer these questions.Percentage rise in population of two states from previous year
If population of Chennai in 2010 was 80 thousand, what was its approximate population in 2008 ? (in thousand) ?
Correct
Explanation:
X*1.2*1.3=80
X=51.30Incorrect
Explanation:
X*1.2*1.3=80
X=51.30 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeI.x^{2} – 29x + 208 = 0
II.y^{3} = 2197Correct
Incorrect
Explanation:
I.x^{2} – 29x + 208 = 0
x^{2} – 16x – 13x + 208 = 0
x(x16)13(x16)= 0
(x13)(x16)=0
x=13, 16
II.y^{3} = 2197
y=13
x≥y 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeI.3x^{2} – 13x + 14 = 0
II.2y^{2} – 29y + 50 = 0Correct
Explanation:
I.3x^{2} – 13x + 14 = 0
3x^{2 }– 6x – 7x + 14 = 0
3x(x2)7(x2)= 0
(3x7)(x2)=0
x=7/3, 2
II.2y^{2} – 29y + 50 = 0
2y^{2} – 4y – 25y + 50 = 0
2y(y2) – 25(y2) = 0
(2y25)(y2)=0
y=2, 25/2Incorrect
Explanation:
I.3x^{2} – 13x + 14 = 0
3x^{2 }– 6x – 7x + 14 = 0
3x(x2)7(x2)= 0
(3x7)(x2)=0
x=7/3, 2
II.2y^{2} – 29y + 50 = 0
2y^{2} – 4y – 25y + 50 = 0
2y(y2) – 25(y2) = 0
(2y25)(y2)=0
y=2, 25/2 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeI.x^{2} + 4x – 1517 = 0
II.y^{2} – 45y + 374 = 0Correct
Explanation:
I.x^{2} + 4x – 1517 = 0
x^{2} + 41x – 37x – 1517 = 0
x(x+41)37(x+41)= 0
(x37)(x+41)=0
x= 41, 37
II.y^{2} – 45y + 374 = 0
y^{2} – 11y – 34y + 444 = 0
y(y11) 34(y11)=0
(y11)(y34)=0
y=11, 34
No relation can be established.Incorrect
Explanation:
I.x^{2} + 4x – 1517 = 0
x^{2} + 41x – 37x – 1517 = 0
x(x+41)37(x+41)= 0
(x37)(x+41)=0
x= 41, 37
II.y^{2} – 45y + 374 = 0
y^{2} – 11y – 34y + 444 = 0
y(y11) 34(y11)=0
(y11)(y34)=0
y=11, 34
No relation can be established. 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeI.x^{2} – 32x + 255 = 0
II.y^{2} – 25y +156= 0Correct
Explanation:
I.x^{2} – 32x + 255 = 0
x^{2} – 15x – 17x + 255 = 0
x(x15)17(x15)=0
(x15)(x17)=0
x=15,17
II.y^{2} – 25y + 156 = 0
y^{2} – 12y – 13y + 156= 0
y(y12)13(y12)=0
(y12)(y13)=0
y=13, 12
x>yIncorrect
Explanation:
I.x^{2} – 32x + 255 = 0
x^{2} – 15x – 17x + 255 = 0
x(x15)17(x15)=0
(x15)(x17)=0
x=15,17
II.y^{2} – 25y + 156 = 0
y^{2} – 12y – 13y + 156= 0
y(y12)13(y12)=0
(y12)(y13)=0
y=13, 12
x>y 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeI.2x^{2} – 39x + 145 = 0
II.y^{2} 32y + 247= 0Correct
Explanation:
I.2x^{2 }– 39x + 145 = 0
2x^{2} – 29x – 10x + 145 = 0
x(2x29)5(2x29)= 0
(x5)(2x29)=0
x=5, 29/2
II.y^{2} 32y + 247 = 0
y^{2} 13y – 19y + 247 = 0
y (y13) – 19(y – 13) = 0
(y19)(y13)=0
y=19,13Incorrect
Explanation:
I.2x^{2 }– 39x + 145 = 0
2x^{2} – 29x – 10x + 145 = 0
x(2x29)5(2x29)= 0
(x5)(2x29)=0
x=5, 29/2
II.y^{2} 32y + 247 = 0
y^{2} 13y – 19y + 247 = 0
y (y13) – 19(y – 13) = 0
(y19)(y13)=0
y=19,13
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