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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeWhen a number is divided by another number, the quotient and remainder obtained are 26 and 2 respectively. If the difference between these numbers is 2577, what is the larger number?
Correct
Explanation:
Smaller no = x, then larger = x+2577
Now x+2577 = 26x + 2
Solve, x = 103
So larger no is = 103+2577Incorrect
Explanation:
Smaller no = x, then larger = x+2577
Now x+2577 = 26x + 2
Solve, x = 103
So larger no is = 103+2577 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeRs 6630 is to be invested in two schemes such that interest after 7 years and 4 years is same on respective parts. If scheme A offers 10% rate of interest and scheme B offers 8% rate of interest, what is the amount invested in scheme B?
Correct
Explanation:
Shortcut when interests are equal:
1/(7*10) : 1/((4*8)
16 : 35
So amount invested in scheme A = (35/51) * 6630Incorrect
Explanation:
Shortcut when interests are equal:
1/(7*10) : 1/((4*8)
16 : 35
So amount invested in scheme A = (35/51) * 6630 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeThere are 6 boys and 3 girls from which 4 people are to be selected. What is the number of ways in which they can be selected so that a particular girl is always selected?
Correct
Explanation:
A particular girl is already selected from the 3 girls
This means now 2 girls left and 6 boys. From these 8 people, 3 are to be selected.
So ^{8}C_{3}Incorrect
Explanation:
A particular girl is already selected from the 3 girls
This means now 2 girls left and 6 boys. From these 8 people, 3 are to be selected.
So ^{8}C_{3} 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeA can complete 4/5th of a piece of work in 12 days and B can complete 1/3rd of the same work in 9 days. If both A and B work together, they can do 7/15th of that work in how many days?
Correct
Explanation:
A can do 4/5th of the work in 12 days, so whole work in 5/4 * 12 = 15 days.
B can do 1/3th of the work in 9 days, so whole work in 3/1 * 9 = 27 days.
A and B together can complete whole work in 15*27/(15+27) = 15*9/14 days.
So 7/15th work in 7/15 * (15*9/14)Incorrect
Explanation:
A can do 4/5th of the work in 12 days, so whole work in 5/4 * 12 = 15 days.
B can do 1/3th of the work in 9 days, so whole work in 3/1 * 9 = 27 days.
A and B together can complete whole work in 15*27/(15+27) = 15*9/14 days.
So 7/15th work in 7/15 * (15*9/14) 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeRs 310 are to be divided among A, B and C in the ratio 1/2 : 1/3 : 1/5, but by mistake it was divided in the ratio of 2 : 3 : 5 among them respectively. How much did A lost in this transaction?
Correct
Explanation:
Ratio in which divided = 2 : 3 : 5
Actual ratio = 1/2 : 1/3 : 1/5 or 15 : 10 : 6
Both ratios show that A and B have lost and C has gained the most.
A got = 2/(2+3+5) * 310 = 62
Actually A would have got = 15/(15+10+6) * 310 = 150
So A lost 150 – 62Incorrect
Explanation:
Ratio in which divided = 2 : 3 : 5
Actual ratio = 1/2 : 1/3 : 1/5 or 15 : 10 : 6
Both ratios show that A and B have lost and C has gained the most.
A got = 2/(2+3+5) * 310 = 62
Actually A would have got = 15/(15+10+6) * 310 = 150
So A lost 150 – 62 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeDirections (610): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –
3x^{2} – 20x + 12 = 0, 2y^{2} – 15y + 18 = 0
Correct
Explanation:
3x^{2} – 20x + 12 = 0
3x^{2} – 20x + 12 = 0
Gives x = 6, 2/3
2y^{2} – 15y + 18 = 0
2y^{2} – 12y – 3y + 18 = 0
Gives y = 6, 3/2
Put on number line
2/3…… 3/2 ….. 6
When y = 3/2, y < x(2/3) and y > x(6), so cant be determined.Incorrect
Explanation:
3x^{2} – 20x + 12 = 0
3x^{2} – 20x + 12 = 0
Gives x = 6, 2/3
2y^{2} – 15y + 18 = 0
2y^{2} – 12y – 3y + 18 = 0
Gives y = 6, 3/2
Put on number line
2/3…… 3/2 ….. 6
When y = 3/2, y < x(2/3) and y > x(6), so cant be determined. 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeDirections (610): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –
12x^{2} + x – 1 = 0, 3y^{2} + 13y + 4 = 0
Correct
Explanation:
12x^{2} + x – 1 = 0
12x^{2} + 4x – 3x – 1 = 0
Gives x = 1/3, 1/4
3y^{2} + 13y + 4 = 0
3y^{2} + 12y + y + 4 = 0
Gives y = 1/3, 4
Put on number line
4……. 1/3….. 1/4Incorrect
Explanation:
12x^{2} + x – 1 = 0
12x^{2} + 4x – 3x – 1 = 0
Gives x = 1/3, 1/4
3y^{2} + 13y + 4 = 0
3y^{2} + 12y + y + 4 = 0
Gives y = 1/3, 4
Put on number line
4……. 1/3….. 1/4 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeDirections (610): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –
3x^{2} + 8x + 5 = 0, 4y^{2} – 13y + 10 = 0
Correct
Explanation:
3x^{2} + 8x + 5 = 0
3x^{2} + 3x + 5x + 5 = 0
Gives x = 5/3, 1
4y^{2} – 13y + 10 = 0
4y^{2} – 8y – 5y + 10 = 0
Gives y = 5/4, 2
Put on number line
5/3… 1……. 5/4….. 2Incorrect
Explanation:
3x^{2} + 8x + 5 = 0
3x^{2} + 3x + 5x + 5 = 0
Gives x = 5/3, 1
4y^{2} – 13y + 10 = 0
4y^{2} – 8y – 5y + 10 = 0
Gives y = 5/4, 2
Put on number line
5/3… 1……. 5/4….. 2 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeDirections (610): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –
x^{2} + 4x + 3 = 0, 2y^{2} – 11y + 12 = 0
Correct
Explanation:
x^{2} + 4x + 3 = 0
x^{2} + 3x + x + 3 = 0
Gives x = 1, 3
2y^{2} – 11y + 12 = 0
2y^{2} – 8y – 3y + 12 = 0
Gives y = 3/2, 4
Put on number line
3…………. 1………. 3/2……… 4Incorrect
Explanation:
x^{2} + 4x + 3 = 0
x^{2} + 3x + x + 3 = 0
Gives x = 1, 3
2y^{2} – 11y + 12 = 0
2y^{2} – 8y – 3y + 12 = 0
Gives y = 3/2, 4
Put on number line
3…………. 1………. 3/2……… 4 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeDirections (610): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –
2x^{2} + 13x + 6 = 0, 2y^{2} + y – 10 = 0
Correct
Explanation:
2x^{2} + 13x + 6 = 0
2x^{2} + 12x + x + 6 = 0
Gives x = 6, 1/2
2y^{2} + y – 10 = 0
2y^{2} 4y + 5y – 10 = 0
Gives y= 5/2 , 2
Put on number line
6……….. 5/2……. 1/2…….2Incorrect
Explanation:
2x^{2} + 13x + 6 = 0
2x^{2} + 12x + x + 6 = 0
Gives x = 6, 1/2
2y^{2} + y – 10 = 0
2y^{2} 4y + 5y – 10 = 0
Gives y= 5/2 , 2
Put on number line
6……….. 5/2……. 1/2…….2
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