Welcome to Online Quant Test in AffairsCloud.com. We are starting SBI Clerk Prelims 2016 Course and we are creating sample questions in Quant section, these type of questions will be ask in SBI Clerk 2016 !!!

You have already completed the quiz before. Hence you can not start it again.

Quiz is loading...

You must sign in or sign up to start the quiz.

You have to finish following quiz, to start this quiz:

Results

0 of 10 questions answered correctly

Your time:

Time has elapsed

You have reached 0 of 0 points, (0)

Categories

Quantitative Aptitude0%

1

2

3

4

5

6

7

8

9

10

Answered

Review

Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

A can do a piece of work in the same time in which B and C can together do it. If A and B can together do it in 10 days and C alone in 30 days, then B alone could do it in how many days?

Correct

Explanation:
(A+B+C)’s 1 day’s work: 1/A + 1/B + 1/C = 1/10 + 1/30 = 4/30
Given 1/A = 1/B +1/C
So, 1/A +1/A = 4/30 gives 1/A = 4/60 = 1/15
1/A + 1/B = 1/10, so 1/B = 1/10 – 1/15 = 1/30
So B can do in 30 days

Incorrect

Explanation:
(A+B+C)’s 1 day’s work: 1/A + 1/B + 1/C = 1/10 + 1/30 = 4/30
Given 1/A = 1/B +1/C
So, 1/A +1/A = 4/30 gives 1/A = 4/60 = 1/15
1/A + 1/B = 1/10, so 1/B = 1/10 – 1/15 = 1/30
So B can do in 30 days

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

A committee of 5 is to be formed from among 4 girls and 5 boys. What is the probability that the committee will have number of boys less than number of girls?

Correct

Explanation:
Case 1: 4 girls and 1 boys [0 boys cannot be there, because maximum girls are 4]
4C4*5C1/9C5
Case 2: 3 girls and 2 boys
4C3*5C2/9C5
Add both cases

Incorrect

Explanation:
Case 1: 4 girls and 1 boys [0 boys cannot be there, because maximum girls are 4]
4C4*5C1/9C5
Case 2: 3 girls and 2 boys
4C3*5C2/9C5
Add both cases

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

Solution A has 42 6/7% water and rest milk. If 6 litres of water is added to it, then percentage of water will become 60%. What was the initial weight of solution A?

Correct

Explanation:
42 6/7 = 300/7%
Then
(300/7*100) * x + 6 = (60/100) * (x+6)
Solve, x = 14

Incorrect

Explanation:
42 6/7 = 300/7%
Then
(300/7*100) * x + 6 = (60/100) * (x+6)
Solve, x = 14

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

The average age of Anisha and Vinisha is 11 years who are sitting in a group having 11 people. The maximum and minimum average of remaining becomes 12 years and 11 years respectively when anyone of Anisha or Vinisha leaves the group. What is the average of all people in the group?

Correct

Explanation:
Let total age of 9 people except Anisha and Vinisha = a years
Age of anisha = x years, age of vinisha = y yeas
Then (x+y)/2 = 11, gives x + y = 22
Then (a+x)/10 = 11, gives a + x = 110
Then (a+y)/10 = 12, gives a + y = 120
Now there are 3 equations, solve and find all values, a = 104, x = 16, y = 6
Then average = (104+16+6)/11

Incorrect

Explanation:
Let total age of 9 people except Anisha and Vinisha = a years
Age of anisha = x years, age of vinisha = y yeas
Then (x+y)/2 = 11, gives x + y = 22
Then (a+x)/10 = 11, gives a + x = 110
Then (a+y)/10 = 12, gives a + y = 120
Now there are 3 equations, solve and find all values, a = 104, x = 16, y = 6
Then average = (104+16+6)/11

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

In a class of 70 students, ratio of number of boys to girls is 4 : 3. Among the girls ratio of number of girls coming by bus and not coming by bus is 1 : 4. If the ratio of total students coming by bus and not coming by bus in class is 8 : 27, find the ratio of number of boys coming by bus and not coming by bus.

Correct

Explanation:
Boys in class = (4/7)*70 = 40, so girls = 70-40=30
Among girls, spots persons = (1/5)*30 = 6, so non-sports persons = 30-6 = 24
Total sports person in class = 8/(8+27) * 70 = 16, so non-sports
persons = 70-16 = 54
So among boys sports person = 16-6=10, non-sports = 54-24 = 30
So ratio = 10: 30 = 1: 3

Incorrect

Explanation:
Boys in class = (4/7)*70 = 40, so girls = 70-40=30
Among girls, spots persons = (1/5)*30 = 6, so non-sports persons = 30-6 = 24
Total sports person in class = 8/(8+27) * 70 = 16, so non-sports
persons = 70-16 = 54
So among boys sports person = 16-6=10, non-sports = 54-24 = 30
So ratio = 10: 30 = 1: 3

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

Directions (6-10): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give
answer –

9x^{2} – 9x + 2 = 0, 3y^{2} + 11y – 4 = 0

Correct

Explanation:
9x^{2} – 9x + 2 = 0
9x^{2} – 3x – 6x + 2 = 0
Gives x = 1/3, 2/3
3y^{2} + 11y – 4 = 0
3y^{2} + 12y – y – 4 = 0
Gives y = -4, 1/3
Put on number line
-4…… 1/3 ….. 2/3

Incorrect

Explanation:
9x^{2} – 9x + 2 = 0
9x^{2} – 3x – 6x + 2 = 0
Gives x = 1/3, 2/3
3y^{2} + 11y – 4 = 0
3y^{2} + 12y – y – 4 = 0
Gives y = -4, 1/3
Put on number line
-4…… 1/3 ….. 2/3

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

Directions (6-10): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give
answer –

x^{2} – 10x + 25 = 0, y^{2} – 9y + 20 = 0

Correct

Explanation:
x^{2} – 10x + 25 = 0
x^{2} – 5x – 5x + 25 = 0
Gives x = 5
y^{2} – 9y + 20 = 0
y^{2} – 5y – 4y + 20 = 0
Gives y = 4,5
Put on number line
4……. 5

Incorrect

Explanation:
x^{2} – 10x + 25 = 0
x^{2} – 5x – 5x + 25 = 0
Gives x = 5
y^{2} – 9y + 20 = 0
y^{2} – 5y – 4y + 20 = 0
Gives y = 4,5
Put on number line
4……. 5

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

Directions (6-10): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give
answer –

6x^{2} + 11x + 3 = 0, 20y^{2} + 9y + 1 = 0

Correct

Explanation:
6x^{2} + 11x + 3 = 0
6x^{2} + 2x + 9x + 3 = 0
Gives x = -1/3, -3/2
20y^{2} + 9y + 1 = 0
20y^{2} + 4y + 5y + 1 = 0
Gives y = -1/4, -1/5
Put on number line
-3/2… -1/3……. -1/4…… -1/5

Incorrect

Explanation:
6x^{2} + 11x + 3 = 0
6x^{2} + 2x + 9x + 3 = 0
Gives x = -1/3, -3/2
20y^{2} + 9y + 1 = 0
20y^{2} + 4y + 5y + 1 = 0
Gives y = -1/4, -1/5
Put on number line
-3/2… -1/3……. -1/4…… -1/5

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

Directions (6-10): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give
answer –

30x^{2} + 17x ¬+ 2 = 0, 3y^{2} + 8y + 4 = 0

Correct

Explanation:
30x^{2} + 17x ¬+ 2 = 0
30x^{2} + 5x ¬+ 12x + 2 = 0
Gives x = -1/6, -2/5
3y^{2} + 8y + 4 = 0
3y^{2} + 6y + 2y + 4 = 0
Gives y = -2, -2/3
Put on number line
-2…………. -2/3………. -2/5……… -1/6

Incorrect

Explanation:
30x^{2} + 17x ¬+ 2 = 0
30x^{2} + 5x ¬+ 12x + 2 = 0
Gives x = -1/6, -2/5
3y^{2} + 8y + 4 = 0
3y^{2} + 6y + 2y + 4 = 0
Gives y = -2, -2/3
Put on number line
-2…………. -2/3………. -2/5……… -1/6

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

Directions (6-10): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give
answer –

4x^{2} – 13x + 10 = 0, 2y^{2} – 15y + 22 = 0

Correct

Explanation:
4x^{2} – 13x + 10 = 0
4x^{2} – 8x – 5x + 10 = 0
Gives x = 2, 5/4
2y^{2} – 15y + 22 = 0
2y^{2} – 4y – 11y + 22 = 0
Gives y= 11/2 , 2
Put on number line
5/4……….. 2………. 11/2

Incorrect

Explanation:
4x^{2} – 13x + 10 = 0
4x^{2} – 8x – 5x + 10 = 0
Gives x = 2, 5/4
2y^{2} – 15y + 22 = 0
2y^{2} – 4y – 11y + 22 = 0
Gives y= 11/2 , 2
Put on number line
5/4……….. 2………. 11/2