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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

A group of men were assigned a work. After half of the work completed, double the number of men joined the original group. Now the work gets completed 6 days earlier than the scheduled number of days. What is the total number of days the initial group of men would have taken to complete the work?

Correct

Explanation:
Let initially x man are there to complete work in 2y days
Now after half of work completed, i.e. after ‘y’ days, double men before joined the group – this means now there are 3x men working.
So after y days
M1*D1 = M2*D2
x*y = 3x*(y-6)
y = 9
so total days x men would have taken = 2y = 18 days

Incorrect

Explanation:
Let initially x man are there to complete work in 2y days
Now after half of work completed, i.e. after ‘y’ days, double men before joined the group – this means now there are 3x men working.
So after y days
M1*D1 = M2*D2
x*y = 3x*(y-6)
y = 9
so total days x men would have taken = 2y = 18 days

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

The ratio of the heights of two right circular cones is 2 : 3 and ratio of perimeters of their bases is 1 : 2. Find the ratio of their respective volumes.

Radhika got two successive discounts of 20% each on article marked at Rs 30,000. She spent Rs 2,800 on its repairs and then sold the same for Rs 26,000. What is her profit percent in the whole transaction?

Correct

Explanation:
Successive discounts of 20% and 20% makes overall discount of (-20) + (-20) + (-20)(-20)/100 = -40 + 4 = -36%
So she buys the article for [(100-36)/100] * 30000 = 19,200
Spends 2800 on repairs, so total CP = 2800 + 19200 = 22,000
SP = 26,000
So profit% = (4000/22000) * 100

Incorrect

Explanation:
Successive discounts of 20% and 20% makes overall discount of (-20) + (-20) + (-20)(-20)/100 = -40 + 4 = -36%
So she buys the article for [(100-36)/100] * 30000 = 19,200
Spends 2800 on repairs, so total CP = 2800 + 19200 = 22,000
SP = 26,000
So profit% = (4000/22000) * 100

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

A, B and C invested Rs 2000, Rs 2500 and Rs 2500 respectively in a business. After 8 months, all withdrew Rs 500 from their investments for only 2 months and then reinvested. Out of a total profit of Rs 48,600 after a year, what is the share of C in the profit?

Correct

Explanation:
A invested 2000 for total 10 months (first 8 months and last 2 months) and 1500 for 2 months (9th and 10th month). Similarly with others. So A : B : C is
2000*10+1,500*2 : 2500*10 +2,000*2 : 2500*10 +2,000*2
23 : 29 : 29
So B gets = [29/(23+29+29)] * 48,600 = 17400

Incorrect

Explanation:
A invested 2000 for total 10 months (first 8 months and last 2 months) and 1500 for 2 months (9th and 10th month). Similarly with others. So A : B : C is
2000*10+1,500*2 : 2500*10 +2,000*2 : 2500*10 +2,000*2
23 : 29 : 29
So B gets = [29/(23+29+29)] * 48,600 = 17400

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

The sum of the present ages of A and B is 66. The ratio of ages of A after 4 years and B 6 years ago is 5 : 3. What is B’s present age?

Correct

Explanation:
A + B = 66
(A+4)/(B-6) = 5/3
Solve both equations, B = 30

Incorrect

Explanation:
A + B = 66
(A+4)/(B-6) = 5/3
Solve both equations, B = 30

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

A person travels from A to B at 30 km/hr and back from B to A at 34 km/hr. If the total time taken for the journey is 48 minutes, find the total distance travelled by the man?

Correct

Explanation:
When we are given total time for 2 journeys of equal distance,
One way distance = multiplication of speeds/addition of speeds * total time
So here distance from A to B = 30*34/(30+34) *48/60 = 51/4
So total distance travelled = 2*(51/4) = 51/2

Incorrect

Explanation:
When we are given total time for 2 journeys of equal distance,
One way distance = multiplication of speeds/addition of speeds * total time
So here distance from A to B = 30*34/(30+34) *48/60 = 51/4
So total distance travelled = 2*(51/4) = 51/2

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

Find the volume of the cube whose surface area is 73 1/2 sq. m.

Correct

Explanation:
6a^{2} = 147/2
So a^{2} = 49/4, a = 7/2
So volume = 7/2 * 7/2 * 7/2 = 343/8

Incorrect

Explanation:
6a^{2} = 147/2
So a^{2} = 49/4, a = 7/2
So volume = 7/2 * 7/2 * 7/2 = 343/8

A box contains 4 blue, 6 green and 5 red balls. If two balls are drawn at random, what is the probability that no ball is red in color?

Correct

Explanation:
Total balls = 15
Not red means 2 balls from blue or green color i.e. any of (4+6) = 10 balls
So prob. = ^{10}C_{2} / ^{15}C_{2}

Incorrect

Explanation:
Total balls = 15
Not red means 2 balls from blue or green color i.e. any of (4+6) = 10 balls
So prob. = ^{10}C_{2} / ^{15}C_{2}

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

Rice is bought at the rate of Rs 10 per kg. Out of the total quantity of 120 kg, 70 kg of rice is sold at 10% profit. At what rate per kg the remaining need rice need to be sold so that there is a profit of 25% on the total price?

Correct

Explanation:
Let remaining (120-70) = 50 kg at x%. So by allegation method,
(70 kg)…………………(50 kg)
10% …………………….x%
…………….25%
(x-25)…………..………15
So (x-25)/15 = 70 kg/50 kg
Solve, x = 46%
50 kg costs = 50*10 = Rs 500
So at 46% profit SP of 50 kg is (146/100) * 500 = Rs 730
So SP of 1 kg = 730/50 = 14.6
OR
(70/120)*10 + (50/120)*x = 25
Solve, x = 46%, since its positive so profit
50 kg costs = 50*10 = Rs 500
So at 46% profit SP of 50 kg is (146/100) * 500 = Rs 730
So SP of 1 kg = 730/50 = 14.6

Incorrect

Explanation:
Let remaining (120-70) = 50 kg at x%. So by allegation method,
(70 kg)…………………(50 kg)
10% …………………….x%
…………….25%
(x-25)…………..………15
So (x-25)/15 = 70 kg/50 kg
Solve, x = 46%
50 kg costs = 50*10 = Rs 500
So at 46% profit SP of 50 kg is (146/100) * 500 = Rs 730
So SP of 1 kg = 730/50 = 14.6
OR
(70/120)*10 + (50/120)*x = 25
Solve, x = 46%, since its positive so profit
50 kg costs = 50*10 = Rs 500
So at 46% profit SP of 50 kg is (146/100) * 500 = Rs 730
So SP of 1 kg = 730/50 = 14.6